maps

How can I plot boundary line on G-Map on the basis of city searched like in this image red line showing searched city map? I have see various links but unable to find a solution. Thanks Currently Google Maps JavaScript API doesn't expose any boundaries of geographic features. There is very old feature request in the public issue tracker to add this functionality, however it looks like Google didn't set high priority on this task: https://issuetracker.google.com/issues/35816953 Feel free to star the public feature request to express your interest and subscribe to notifications. Also, you can

I have been trying to build a Choropleth / Bubble map of UK for my own shiny dashboard project. My dashboard is a student information management system and the map is supposed to show students come from which regions (zip codes or cities is also fine). Unfortunately, most packages, such as plotly and ggmap, only cover information about states of USA. So, could someone please tell me how to create a map for UK? Here is an example of what I am trying to accomplish: Choropleth Map for UK This is a step-by-step implementation of what I meant by my comment. I did not use the External Post that I

POJ3275 Ranking the Cows 1 #include <iostream> 2 #include <cstdio> 3 #include <bitset> 4 using namespace std; 5 const int maxn = 1005; 6 int n, m; 7 bitset<maxn> maps[maxn]; 8 void floyd() { 9 for (int k = 1; k <= n; k++) { 10 for (int i = 1; i <= n; i++) { 11 if (maps[i][k]) maps[i] |= maps[k]; 12 } 13 } 14 } 15 int main() { 16 scanf("%d%d",&n,&m); 17 for (int i = 1; i <= m; i++) { 18 int u, v; scanf("%d%d",&u,&v); 19 maps[u][v] = true; 20 } 21 floyd(); 22 int ans = 0; 23 for (int i = 1; i <= n; i++) { 24 for (int j = i+1; j <= n; j++) { 25 if (!maps[i][j] && !maps[j][i]) ans++; 26 } 27 } 28

P3385 【模板】负环 1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 2005, maxm = 3005; 4 const int inf = 0x3f3f3f3f; 5 struct edge { 6 int v, w; 7 }; 8 vector<edge> maps[maxn]; 9 int dis[maxn], n, m; 10 11 bool BellmanFord(int s) { // s为源点 12 fill(dis+1, dis+1+n, inf); 13 dis[s] = 0; 14 for (int i = 1; i <= n-1; i++) { 15 for (int u = 1; u <= n; u++) { 16 for (int j = 0; j < maps[u].size(); j++) { 17 int v = maps[u][j].v; 18 int w = maps[u][j].w; 19 if (dis[u] + w < dis[v]) { 20 dis[v] = dis[u] + w; 21 } 22 } 23 } 24 } 25 26 if (maps[s].size() == 0) return true; // 如果s点没有和其他点相连

Holy Grail 1 #include <bits/stdc++.h> 2 using namespace std; 3 const int maxn = 305, maxm = 505; 4 const int inf = 0x3f3f3f3f; 5 struct edge { 6 int v, w; 7 }; 8 vector<edge> maps[maxn]; 9 int dis[maxn], n, m; 10 11 bool BellmanFord(int s) { // s为源点 12 fill(dis, dis+n, inf); 13 dis[s] = 0; 14 for (int i = 0; i < n-1; i++) { 15 for (int u = 0; u < n; u++) { 16 for (int j = 0; j < maps[u].size(); j++) { 17 int v = maps[u][j].v; 18 int w = maps[u][j].w; 19 if (dis[u] + w < dis[v]) { 20 dis[v] = dis[u] + w; 21 } 22 } 23 } 24 } 25 for (int u = 0; u < n; u++) { 26 for (int j = 0; j < maps[u].size();

I want google maps to show the location of the user centered at the map as at the image 1 And this is my Fragment Code: public class MapFragment extends Fragment implements OnMapReadyCallback { GoogleMap googleMap; MapView mapView; View myview; public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { myview = inflater.inflate(R.layout.map_layout, container, false); mapView = (MapView) myview.findViewById(R.id.map); mapView.onCreate(savedInstanceState); mapView.onResume(); mapView.getMapAsync(this); return myview; } @Override public void onMapReady

for a school project I have to map some data on a geographical map in R. Therefore I've got some data containing the zipcode and many other information (just no more information on the state, county or whatever). I've been trying to point out on a map of the usa first all the zips I have. Just dots. Afterwards I wanted to mix and match the criteria like the count of zips I have in the data (e.g. the zips that appear very often I wanted to colour dark and the less often ones in a lither colour, later I wanted to point out e.g. the number of churns in a state). Can somebody help me out on how I