maps | 易学教程

【译】Source Maps浅析

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Time：2019/10/27~2019/10/29 Link：原文链接译文开始：对网站进行性能优化对一个最容易的方法就是把JS和CSS进行打包压缩。但是当你需要调试这些压缩文件中的代码的时候，会发生什么？可能会是一场噩梦。但是，不用害怕，即将有一个解决方案到来，它就是Source Maps。 source maps提供一种将压缩文件中的代码映射回源文件中原始位置的方法。这意味着，借助一些软件的帮助，即使你的资源被压缩，你也可以轻易调试你的程序。Chrome和Firefox内置的开发者工具都支持source maps了。在这篇文章中，你将会学习到source maps的实现原理以及怎么去生成source maps。我们主要是关注JavaScript代码的source maps，但是这些原则同样适用于CSS的source maps。 Source Maps实现原理顾名思义，source map（源映射）就是包含一堆的信息，可以将压缩文件的代码映射回到源代码。你可以为每个压缩文件指定不同的source map。通过在压缩文件底部添加特殊的注释，向浏览器表明souce map是可用的。 //# sourceMappingURL=/path/to/script.js.map 该注释通常会被用于生成source map的程序添加。仅当开发者工具支持source

Length buffer around polyline

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I'm not very good at mathematics, so I got a problem. I have a route from one, to another distination. Some time I was trying to apply a colored plot aroud the route in fixed length. But I cant get a nice rounded corners and my lack of math is making me a lot of truble. Now I got this And the code var r = []; var bla = result.routes[0].overview_path; for(i in result.routes[0].overview_path) { r.push(new google.maps.LatLng(bla[i].lat()+z, bla[i].lng()-z)); } bla.reverse(); for(x in bla) { r.push(new google.maps.LatLng(bla[x].lat()-z, bla[x].lng()+z)); } var kelias = new google.maps.Polyline({

Display a map and highlight certain countries

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Here's what I'm struggling to do : Display a map on page (Google map or any of it competitors, free is possible...) and highlight certain countries on this map (the list of theses countries would be stored in a variable by exemple). I tried to draw polygons on the map with a geo-json list of (almost) all the countries but it's too heavy. Any ideas ? I believe you will need a polygon to do that. http://code.google.com/apis/maps/documentation/overlays.html#Polygons_Overview http://code.google.com/apis/maps/documentation/reference.html#GPolygon like this sample: http://gmaps-samples-v3.googlecode

How Do I add Pins (Annotations) with Xcode 6 (Swift)

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This question was migrated from Ask Different because it can be answered on Stack Overflow. Migrated 4 years ago . Learn more . I'm new to the swift language, and haven't done an application with mapkit yet. But I have the map and regions set, but I'm hung up on how to allow users to add pins. Let me clarify, I have no idea of even where to start, All I have at the moment (for the pins) is my variable, but I'm not even sure if that's correct. Any help would be much appreciated!! What I have... var MyPins: MKPinAnnotatoinView! ...... override func viewDidLoad() { super.viewDidLoad() Mapview

Mapping values from two array in Ruby

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I'm wondering if there's a way to do what I can do below with Python, in Ruby: sum = reduce(lambda x, y: x + y, map(lambda x, y: x * y, weights, data)) I have two arrays of equal sizes with the weights and data but I can't seem to find a function similar to map in Ruby, reduce I have working. @Michiel de Mare Your Ruby 1.9 example can be shortened a bit further: weights.zip(data).map(:*).reduce(:+) Also note that in Ruby 1.8, if you require ActiveSupport (from Rails) you can use: weights.zip(data).map(&:*).reduce(&:+) In Ruby 1.9: weights.zip(data).map{|a,b| a*b}.reduce(:+) In Ruby 1.8:

Determine user location on osm maps

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I am working on an android application that determines user location in osm maps. I am being able to show user location on the map, but if the location change the whole map is reloaded, what’s wrong with that? Also how I can increase the accuracy of the user location? And how can I make a circle that increase and decrease according to the accuracy(as shown in Google one)? code : public class OsmDemoActivity extends Activity implements LocationListener, MapViewConstants { private MapView mMapView; private MapController mapController; private LocationManager mLocMgr; private ItemizedOverlay

H5实现图表和地图

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H5实现图表和地图的代码如下： 1 <!DOCTYPE html> 2 <html> 3 <head> 4 <title>图表和地图</title> 5 <meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0, user-scalable=no" /> 6 <style type="text/css"> 7 html,body{ 8 width:100%; 9 height:100%; 10 } 11 *{ 12 margin:0px; 13 padding:0px; 14 } 15 body, button, input, select, textarea { 16 font: 12px/16px Verdana, Helvetica, Arial, sans-serif; 17 } 18 p{ 19 width:603px; 20 padding-top:3px; 21 overflow:hidden; 22 } 23 .btn{ 24 width:142px; 25 } 26 #container{ 27 width:100%; 28 height:300px; 29 } 30 </style> 31 </head>

Want to Display Direction Between 100 Address on Google Maps

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问题 I want to display optimize route for about 100 addresses on the Google maps. I have searched for that but Google gives only 8 addresses per request in free and 23 addresses in Paid API. Than I saw one website who is doing same thing using unlimited address and named "Route4Me". The case is now I have all addresses's lati and longi in optimize manner. I just want to show a route using these data on Google maps. This situation is not exact as to route from A to B in Google Maps. I want to map

open maps/google maps in react native

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I am trying to open google maps or maps in my react-native application, but when I run the app in my Iphone/simulator I receive the error "Don't know how to open URI:...". What I am doing wrong? My code: openGps() { var url = 'geo:37.484847,-122.148386' this.openExternalApp(url) } openExternalApp(url) { Linking.canOpenURL(url).then(supported => { if (supported) { Linking.openURL(url); } else { console.log('Don\'t know how to open URI: ' + url); } }); } Narek Ghazaryan To open url with custom label ios/android: const scheme = Platform.select({ ios: 'maps:0,0?q=', android: 'geo:0,0?q=' }); const

How to get latitude and longitude position that stored in MySQL and use it in Android map application

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问题 I have tried to get the latitude and longitude position that was stored in MySQL. I want use the values to my Android map application. Here is my code: deskripsi.Java Button direction = (Button) findViewById (R.id.btnDir); direction.setOnClickListener(new OnClickListener(){ public void onClick(View arg0) { Intent z = getIntent(); des_lat = z.getExtras().getString("des_lat"); des_long = z.getExtras().getString("des_long"); Intent i = new Intent(android.content.Intent.ACTION_VIEW, Uri.parse(