lxml

I wanted to do get some experience with html crawling, so I wanted to see if I could grab some values of the following site: http://www.iex.nl/Aandeel-Koers/11890/Royal-Imtech/koers.aspx This site shows the price of imtech shares. If you take a look at the site, you see there is 1 number shown in bold, this is the price of the share. As you may have seen, this price changes, and that's okay. I only want the value at the time I run my script at this point in time. but if you reload the page, you may notice how it first shows "laatste koers" and after a delay of 1 second it shows "realtime" As

My application needs lxml >= 2.1, but to install lxml its requied to install libxml2-dev libxslt1-dev else it raises error while installing the lxml, is there a way that using python setup tool I can give this as dependency in my setup.py.... ohe Not really ... setuptools only handle dependencies on package wich belongs already to pypi. So if you want these kind of dependencies, i think that you have to select the packaging technology brought by your favorite distribution. But, you can override your setuptools build or install command to make extra check before installing the package. To do so

Is it possible not to add namespace for the tag when using html5parser from the lxml.html package? Example: from lxml import html print(html.parse('http://example.com').getroot().tag) # You will get 'html' from lxml.html import html5parser print(html5parser.parse('http://example.com').getroot().tag) # You will get '{http://www.w3.org/1999/xhtml}html' The easiest solution I found is to remove that using regex, but maybe it's possible not to include that text at all? There is a specific namespaceHTMLElements boolean flag that controls this behavior: from lxml.html import html5parser from

My goal is to write a python script that takes an artist's name as a string input and then appends it to the base URL that goes to the genius search query.Then retrieves all the lyrics from the returned web page's links (Which is the required subset of this problem that will also contain specifically the artist name in every link in that subset.).I am in the initial phase right now and just have been able to retrieve all links from the web page including the ones that I don't want in my subset. I tried to find a simple solution but failed continuously. import requests # The Requests library.

I have an xml file looks something like this <A> <B> <C> .... </C> </B> </A> I want to add root on top of element 'A'. I found out a way to add elements to root. But How to change existing root and add on top of it using python. After adding root to the xml it should look like this <ROOT> <A> <B> <C> .... </C> </B> </A> </ROOT> import lxml.etree as ET tree = ET.parse('data') root = tree.getroot() newroot = ET.Element("root") newroot.insert(0, root) print(ET.tostring(newroot, pretty_print=True)) yields <root> <A> <B> <C> .... </C> </B> </A> </root> But really, unless you need to add something

I'm following this link to try to get values of several tags: Parsing XML with namespace in Python via 'ElementTree' In this link there is no problem to access to the root tag like this: import sys from lxml import etree as ET doc = ET.parse('file.xml') namespaces_rdf = {'rdf': 'http://www.w3.org/1999/02/22-rdf-syntax-ns#'} # add more as needed namespaces_dcat = {'dcat': 'http://www.w3.org/ns/dcat#'} # add more as needed namespaces_dct = {'dct': 'http://purl.org/dc/terms/'} print doc.findall('rdf:RDF', namespaces_rdf) print doc.findall('dcat:Dataset', namespaces_dcat) print doc.findall('dct