logic

Can any one help me in explaining how to write a query for NAND and NOR? I am getting confused? Is there any good example which help to understand the NAND and NOR operation in query? I worked in AND and OR operation between two SQL Queries.. But when I am searching some thing related to NAND/NOR I cant find any tutorial. You can just combine Not + And / Not + Or for example create table test( v1 bit, v2 bit ); insert into test values ( false, false), (false,true), (true,true), (true,false); select v1, v2, not (v1 and v2) "nand", not (v1 or v2) "nor" from test http://sqlfiddle.com/#!2/0828b/3

I saw this code in a Lua Style Guide print(x == "yes" and "YES!" or x) Context: local function test(x) print(x == "yes" and "YES!" or x) -- rather than if x == "yes" then print("YES!") else print(x) end end What exactly happens at " x == "yes" and "YES!" ? Why does it print "YES!" or (x) not "true" or (x) ? EDIT: Is it like: X == "yes" -- > true true and (value) -- > value print( (x == "yes") and value) So checking x for the value "yes" results in true, adding true to a value gives the value and printing this process prints the value, right? From the docs : The operator and returns its first

I wrote a function to compare file versions between what a client currently has and the latest version of the file on a server. The client passes the "quad" (Major.Minor.Build.Private) version number as a string to the server, and then the server uses FileVersionInfo: // clientFileVersion will be in "quad" format, a la "3.1.4.1" private bool ServerFileIsNewer(string clientFileVersion, FileVersionInfo serverFile) { // Don't say I never learned nuthin' from Steve McConnell const int MAJOR_INDEX = 0; const int MINOR_INDEX = 1; const int BUILD_INDEX = 2; const int PRIVATE_INDEX = 3; string[]

There seems to be some kind of misconception that this is for a contest. I'm trying to work through an assignment and I've been stuck on this for an hour now. /* * isLessOrEqual - if x <= y then return 1, else return 0 * Example: isLessOrEqual(4,5) = 1. * Legal ops: ! ~ & ^ | + << >> * Max ops: 24 * Rating: 3 */ int isLessOrEqual(int x, int y) { int greater = (x + (~y + 1))>>31 & 1; return !(greater)|(!(x^y)); } I'm only able to use bitwise operators, as instructed in the comments. I cannot figure out how to solve x <= y ; My thought process is that I can set x as its two's complement ( ~x +1

This question already has an answer here: Logical operators in JavaScript — how do you use them? 2 answers When I type in browser's console: console.log(2 && 3) it results always with second number (in this case 3): 3 Can someone explain me why? If the left hand side of && evaluates as a false value, the whole expression evaluates as the left hand side. Otherwise it evaluates as the right hand side. 2 is a true value, so 2 && 3 is 3 . For comparison, try console.log(0 && 1) and console.log(false && "something") . The && logical operator will return the last value if all other values are truthy