let

What causes the different behaviors between “var” and “let” when assign them a returned value of a function which throws an error

送分小仙女□ 提交于 2019-11-28 02:07:19
Please find the code in the image below. 1. Assign the returned value of a function, which throws an error actually, to the variable 'withLet' that declared by using keyword 'let'. 2. call 'withLet', an error occured: 'withLet is not defined'. 3. try to assert 'withLet' using 'let', an error shows that 'withLet' has already been declared. But the paradox is not exist for 'var' (Please find in the following image). I'm curious about what caused the different behaviors between these two situations. It's quite wired that 'not defined' an 'already been declared' describe a same variable. let

What does `let 5 = 10` do? Is it not an assignment operation?

走远了吗. 提交于 2019-11-27 19:59:57
If I say let 5 = 10 , why does 5 + 1 return 6 instead of 11 ? When you say let 5 = 10 it's not a redefinition of 5, it's a pattern matching, the same which occurs when you say foo 5 = undefined ... foo 10 ... The pattern simply fails if it's ever matched. In let-expressions the match is lazy. This means the match is only being done when a variable bound by it is evaluated. This allows us to write things like let foo = undefined in 10 In your expression, no variable is bound, so the pattern is never matched. Arguably such patterns with no variables make no sense in let-bindings and should be

GHCi “let” — what does it do?

折月煮酒 提交于 2019-11-27 19:42:45
I'd appreciate is someone could point to docs on what "let" does in GHCi, or failing that, explain it convincingly :-). So far as I can tell, "let" (without "in") is not part of the Haskell language per se, and on the other hand, it doesn't appear to be a GHCI command either, as it's not prefixed by colon. sinan While programming in GHCi, you're like programming in the IO monad with do syntax, so for example you can directly execute an IO action, or use monadic bind syntax like r <- someIOFun . let is also a part of do so you can also use this. I think it's being desugared into let .. in <rest

Haskell: Where vs. Let

懵懂的女人 提交于 2019-11-27 16:56:43
I am new to Haskell and I am very confused by Where vs. Let . They both seem to provide a similar purpose. I have read a few comparisons between Where vs. Let but I am having trouble discerning when to use each. Could someone please provide some context or perhaps a few examples that demonstrate when to use one over the other? Where vs. Let A where clause can only be defined at the level of a function definition. Usually, that is identical to the scope of let definition. The only difference is when guards are being used . The scope of the where clause extends over all guards. In contrast, the

Why is using `let` inside a `for` loop so slow on Chrome?

时光毁灭记忆、已成空白 提交于 2019-11-27 15:41:02
问题 MAJOR UPDATE. Thought as yet not on the Chrome major release the new Ignition+Turbofan engines for Chrome Canary 59 has solved the problem. Test show identical times for let and var declared loop variables. Original (now mute) question. When using let in a for loop on Chrome it runs very slowly, compared to moving the variable just outside the loop's scope. for(let i = 0; i < 1e6; i ++); takes twice as long as { let i; for(i = 0; i < 1e6; i ++);} What is going on? Snippet demonstrates the

let vs def in clojure

ε祈祈猫儿з 提交于 2019-11-27 15:30:24
问题 I want to make a local instance of a Java Scanner class in a clojure program. Why does this not work: ; gives me: count not supported on this type: Symbol (let s (new Scanner "a b c")) but it will let me create a global instance like this: (def s (new Scanner "a b c")) I was under the impression that the only difference was scope, but apparently not. What is the difference between let and def ? 回答1: The problem is that your use of let is wrong. Let works like this: (let [identifier (expr)])

In Haskell, when do we use in with let?

假如想象 提交于 2019-11-27 10:43:57
In the following code, the last phrase I can put an in in front. Will it change anything? Another question: If I decide to put in in front of the last phrase, do I need to indent it? I tried without indenting and hugs complains Last generator in do {...} must be an expression import Data.Char groupsOf _ [] = [] groupsOf n xs = take n xs : groupsOf n ( tail xs ) problem_8 x = maximum . map product . groupsOf 5 $ x main = do t <- readFile "p8.log" let digits = map digitToInt $concat $ lines t print $ problem_8 digits Edit Ok, so people don't seem to understand what I'm saying. Let me rephrase:

Difference between “local” and “let” in SML

社会主义新天地 提交于 2019-11-27 06:01:46
问题 I couldn't find a beginner friendly answer to what the difference between the "local" and "let" keywords in SML is. Could someone provide a simple example please and explain when one is used over the other? 回答1: (TL;DR) Use case ... of ... when you only have one temporary binding. Use let ... in ... end for very specific helper functions. Never use local ... in ... end . Use opaque modules instead. Adding some thoughts on use-cases to sepp2k's fine answer: (Summary) local ... in ... end is a

How to “let” in lambda expression?

夙愿已清 提交于 2019-11-27 05:21:36
问题 How can I rewrite this linq query to Entity on with lambda expression? I want to use let keyword or an equivalent in my lambda expression. var results = from store in Stores let AveragePrice = store.Sales.Average(s => s.Price) where AveragePrice < 500 && AveragePrice > 250 For some similar questions like what is commented under my question, it's suggested to .Select(store=> new { AveragePrice = store.Sales.Average(s => s.Price), store}) which will calculate AveragePrice for each item, while

Variable scope + eval in Clojure

核能气质少年 提交于 2019-11-27 05:01:26
In Clojure, (def x 3) (eval '(prn x)) prints 3, whereas (let [y 3] (eval '(prn y))) and (binding [z 3] (eval '(prn z))) generate an 'Unable to resolve var' exception. According to http://clojure.org/evaluation , eval , load-string , etc generate temporary namespaces to evaluate their contents. Therefore, I'd expect neither of the above code samples to work, since (def x 3) is done in my current namespace, not the one created by eval . Why does the first code sample work and not the last two? How can I eval a form with bound variables without using def ? Thanks! danlei 1.: The reason this doesn