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可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am facing issues while consuming JAX-RS services as JSON. Below I have added my code. This is my service class: //Sets the path to base URL + /hello @Path("/hello") @Consumes(MediaType.APPLICATION_JSON) @Produces(MediaType.APPLICATION_JSON) public class Hello { @GET @Produces("application/json") public Student getStudent() { Student s = new Student(); s.first_name = "Test First Name !!!"; s.last_name = "Test Last Name!!!"; return s; } Student class which I am trying to get from service: @XmlRootElement public class Student implements

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: For a certain Hibernate entity we have a requirement to store its creation time and the last time it was updated. How would you design this? What data types would you use in the database (assuming MySQL, possibly in a different timezone that the JVM)? Will the data types be timezone-aware? What data types would you use in Java ( Date , Calendar , long , ...)? Whom would you make responsible for setting the timestamps―the database, the ORM framework (Hibernate), or the application programmer? What annotations would you use for the mapping (e

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: To get the last n characters from a string, I assumed you could use ending = string[-n..-1] but if the string is less than n letters long, you get nil . What workarounds are available? Background : The strings are plain ASCII, and I have access to ruby 1.9.1, and I'm using Plain Old Ruby Objects (no web frameworks). 回答1: Here you have a one liner, you can put a number greater than the size of the string: "123".split(//).last(5).to_s For ruby 1.9+ "123".split(//).last(5).join("").to_s For ruby 2.0+, join returns a string "123".split(//).last

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a data frame containing a time series with two time stamp columns, d$day and d$time , and say, for simplicity, one measured variable d$val1 . Suppose I want to examine the situation at the close of each day's experiment, i.e. the last measurement, if it exists. (Not every day has a measurement, and measurements can be taken at different times each day.) I would like to be able to aggregate by day and use some sort of last() or tail() function on time to pull back the corresponding val . I've tried variations like this with not much

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I have a basic PHP script that creates a csv file from an array. Here is an example of the code: $array = [ [ 1 , 2 , 3 ], [ 4 , 5 , 6 ] ]; $handle = fopen ( 'test.csv' , 'w' ); foreach ( $array as $v ) fputcsv ( $handle , $v ); fclose ( $handle ); The resulting file always has a blank line at the end of the file, because fputcsv doesn't know that this is the last line. Any (simple) ideas on how to prevent this? EDIT: The original question is now irrelevant (to me, but maybe someone will need to do this). fputcsv is supposed to add

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have been using " public boolean setLastModified (long time) " for setting the file modified time but it always return false. I have seen few similar posts related to this but none of them could work for me. can someone give me solution for this? Please do not post me any URL's, I have already seen them : file.lastModified() is never what was set with file.setLastModified() Is it possible to reset the last modified date of an Android file? http://www.mkyong.com/java/how-to-change-the-file-last-modified-date-in-java/ 回答1: setLastModified()

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have used LinkedHashMap because it is important the order in which keys entered in the map. But now I want to get the value of key in the first place (the first entered entry) or the last. Should there be a method like first() and last() or something like that? Do I need to have an iterator to just get the first key entry? That is why I used LinkedHashMap ! Thanks! 回答1: The semantics of LinkedHashMap are still those of a Map, rather than that of a LinkedList . It retains insertion order, yes, but that's an implementation detail, rather

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I am trying to load a preferences window for my application and I would like the apply button to initially be disabled, then when a preference is updated, the apply button gets enabled again. I have some controls data bound to a preferences object and what happens is that after the window loads, the combobox events get triggered. Is there any event that is guaranteed to happen dead last after everything is stable? Here is what my code looks like (the apply button is always enabled after the window loads): private void Window_Loaded

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a C string that looks like "Nmy stringP" , where N and P can be any character. How can I edit it into "my string" in C? 回答1: To "remove" the 1st character point to the second character: char mystr[] = "Nmy stringP"; char *p = mystr; p++; /* 'N' is not in `p` */ To remove the last character replace it with a '\0' p[strlen(p)-1] = 0; /* 'P' is not in `p` (and it isn't in `mystr` either) */ 回答2: Another option, again assuming that "edit" means you want to modify in place: void topntail(char *str) { size_t len = strlen(str); assert(len >=

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am working on my Naver Crawler (its a Korea Google :P). I have working on this code for a week now, and I have one last task to solve! So my code below shows Data Crawling through Naver API and receiving data to "js" in each loop. All I need to do is combine each dataframe (dfdfdf) and combine at the bottom. But my result always shows the last looped data. Bottom line is that I want to add DataFrame for each loop that I am taking. I tried merge, join but it seems to be not working. Please let me know and if my code below does not make