laravel

Uncaught TypeError: $(…).steps is not a function

由 ＊爱你＆永不变心＊ 提交于 2021-01-24 10:58:38
问题 So I saw really good looking forms in my bootstrap template and I wanted to use them in my project. I placed all the required files that I think we need to import which are added at the bottom of the code, required files are in the correct directories, for example, jquery steps: C:\xampp\htdocs\rps\public\files\bower_components\jquery.steps\js\jquery.steps.js 'initialize-steps.js': $("#practitioner-form").steps({ headerTag: "h3", bodyTag: "fieldset", transitionEffect: "slideLeft",

Laravel Fortify Customize Authentication Redirect

由 前提是你 提交于 2021-01-24 08:56:46
问题 In Laravel fortify on customization authentication process, i can not able to redirect to login page with error message which we were able to do in Auth. Here is the customization documentation link: https://jetstream.laravel.com/1.x/features/authentication.html#customizing-the-authentication-process if ($user && Hash::check($request->password, $user->password) && $user->status == 'active') { return $user; } elseif ($user->status == 'inactive') { //redirect with some error message to login

Pagination with many to many relationships

由 只愿长相守 提交于 2021-01-24 07:20:24
问题 The bounty expires in 3 days . Answers to this question are eligible for a +50 reputation bounty. curved wants to draw more attention to this question. I have products , categories and category_product (pivot) tables in my database. I want to return the category info and products with pagination in the same response . I know I can use Product::with('categories')->pagination(20) , but I don't want to attach the category to each product. What is the proper way to get products belong to a

Render Laravel 7 component programmatically

由 别说谁变了你拦得住时间么 提交于 2021-01-24 05:43:58
问题 I have a Laravel 7 component which looks like this class Input extends Component { public $name; public $title; public $value; public $type = 'text'; /** * Create a new component instance. * * @return void */ public function __construct($name, $title) { $this->name = $name; $this->title = $title; $this->value = \Form::getValueAttribute($name); } /** * Get the view / contents that represent the component. * * @return \Illuminate\View\View|string */ public function render() { return view(

Render Laravel 7 component programmatically

由 早过忘川 提交于 2021-01-24 05:42:43
问题 I have a Laravel 7 component which looks like this class Input extends Component { public $name; public $title; public $value; public $type = 'text'; /** * Create a new component instance. * * @return void */ public function __construct($name, $title) { $this->name = $name; $this->title = $title; $this->value = \Form::getValueAttribute($name); } /** * Get the view / contents that represent the component. * * @return \Illuminate\View\View|string */ public function render() { return view(

Render Laravel 7 component programmatically

由 风格不统一 提交于 2021-01-24 05:41:33
问题 I have a Laravel 7 component which looks like this class Input extends Component { public $name; public $title; public $value; public $type = 'text'; /** * Create a new component instance. * * @return void */ public function __construct($name, $title) { $this->name = $name; $this->title = $title; $this->value = \Form::getValueAttribute($name); } /** * Get the view / contents that represent the component. * * @return \Illuminate\View\View|string */ public function render() { return view(

Laravel: Unable to JSON encode payload. Error code: 5

由 只谈情不闲聊 提交于 2021-01-24 05:00:48
问题 I'm working on Laravel (v5.7) app that converts uploaded CSV (with contacts) into array that is then passed as argument when job class is being dispatched. Here is the example of CSV file (format that is supported): 123456,Richard,Smith 654321,John,Doe Uploaded (CSV) file is handled like this: $file_path = $request->file_name->store('contacts'); $file = storage_path('app/' . $file_path); $contactsIterator = $this->getContacts($file); $contacts = iterator_to_array($contactsIterator); // Array

Laravel: Unable to JSON encode payload. Error code: 5

由 北慕城南 提交于 2021-01-24 04:48:54
问题 I'm working on Laravel (v5.7) app that converts uploaded CSV (with contacts) into array that is then passed as argument when job class is being dispatched. Here is the example of CSV file (format that is supported): 123456,Richard,Smith 654321,John,Doe Uploaded (CSV) file is handled like this: $file_path = $request->file_name->store('contacts'); $file = storage_path('app/' . $file_path); $contactsIterator = $this->getContacts($file); $contacts = iterator_to_array($contactsIterator); // Array

Laravel: Unable to JSON encode payload. Error code: 5

由 删除回忆录丶 提交于 2021-01-24 04:48:38
问题 I'm working on Laravel (v5.7) app that converts uploaded CSV (with contacts) into array that is then passed as argument when job class is being dispatched. Here is the example of CSV file (format that is supported): 123456,Richard,Smith 654321,John,Doe Uploaded (CSV) file is handled like this: $file_path = $request->file_name->store('contacts'); $file = storage_path('app/' . $file_path); $contactsIterator = $this->getContacts($file); $contacts = iterator_to_array($contactsIterator); // Array

网站架构优化性能概念

由 核能气质少年 提交于 2021-01-23 20:38:34
最开始的网站架构 最初业务量不大，访问量小，此时的架构，应用程序、数据库、文件都部署在一台服务器上，有些甚至仅仅是租用主机空间 1. 应用、数据、文件分离 将应用程序、数据库、文件各自部署在独立的服务器上，并且根据服务器的用途配置不同的硬件，达到最佳的性能效果。 2. 利用缓存改善网站性能 大部分网站访问都遵循28原则,即80%的访问请求，最终落在20%的数据上,所以我们可以对热点数据进行缓存，减少热点数据的访问路径，提高用户体验。缓存实现常见的方式是本地缓存、分布式缓存。当然还有CDN、反向代理。 2.1 本地缓存 本地缓存，顾名思义是将数据缓存在应用服务器本地，可以存在内存中，也可以存在文件，组件。本地缓存的特点是速度快，但因为本地空间有限所以缓存数据量也有限。 2.2 分布式缓存 分布式缓存的特点是，可以缓存海量的数据，并且扩展非常容易，在门户类网站中常常被使用，速度按理没有本地缓存快，常用的分布式缓存是Memcached、Redis。 2.3 反向代理 部署在网站的机房，当用户请求达到时首先访问反向代理服务器，反向代理服务器将缓存的数据返回给用户，如果没有缓存数据才会继续访问应用服务器获取，这样做减少了获取数据的成本。 2.4 CDN 假设我们的服务器都部署在杭州的机房，对于浙江的用户来说访问是较快的，而对于北京的用户访问是较慢的
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