laravel-routing

I have two forms on a page both submits the data via POST method . I want to handle both requests on the same url i.e /home and use different controllers and methods for both forms. Below are the two routes. Route::post('home' ,'FacebookControllers\PostsController@save'); Route::post('home' , 'FacebookControllers\MessageController@storeMessage'); In PostsController@save I am checking if(isset($_POST['submitPost']) && $_SERVER['REQUEST_METHOD']=='POST'){ //do something } and in MessageController@storeMessage I am doing the same for other form if(isset($_POST['sendMessage']) && $_SERVER['REQUEST

I'm trying to create a set of rules under the new \HTTP\Requests\UpdateArticle class for the slug field, which needs to have unique filter applied, but only when the id is not equal the url parameter of the route name article/{article} . What I got so far is: public function rules() { return [ 'title' => 'required|min:3', 'excerpt' => 'required', 'body' => 'required', 'slug' => 'required|unique:articles,slug,?', 'active' => 'required', 'published_at' => 'required|date' ]; } I need to replace the question mark at the end of the unique filter for slug field with the id from the url, but don't

In my Controller, I have Route::getCurrentRoute()->getAction()['as'] Everything works well in the browser but as soon as I type php artisan route:list in the terminal I have this exception [Symfony\Component\Debug\Exception\FatalErrorException] Call to a member function getAction() on a non-object If I comment this line everything works well. Seems obvious doesn't it? Get current route in a browser will return the currently visited route. In the terminal you do not have such a request. Laravel will return null when asking what route is visited. You would have to check for the return value

I would like to be able to override the routes defined in app/Http/routes.php with a route in a package. For example, in app/Http/routes.php I might have this: Route::get('/search/{type?}',['as' => 'search','uses' => 'SearchController@search']); I want to be able to define this in /vendor/author/package/src/Http/routes.php: Route::get('/search/properties', ['as' => 'properties','uses' => 'PropertyController@search']); The app/Http/routes.php file is loaded first so the route in their is used, not the package. In Laravel 4 I would do this using App::before or App::after, giving them a priority.

I am using Laravel 5 and need to do a wildcard route, sending the user to different controllers based on the URL type, pulled in from the database. I need to check the URL slug in the database, and then load the relevant controller/method based on the slug type, held in the database. I am struggling with the final part, which is sending the user to the relevant controller. Below is my route: Route::any('{slug}', function($slug){ $url = \App\Url_slug::where('url_slug', $slug)->first(); if($url->count()){ switch($url->url_type){ case 'product': // SEND USER TO PRODUCT CONTROLLER break; case

Goal : I want to make route filter in Laravel 4 using Route::group and Route::filter Description I have 2 types of user : Internal Distributor For, Internal , I have 2 groups: admin regular For Distributor , I have 4 groups: gold silver bronze oem Eligible Route OEM Distributor are eligible for only 5 routes. Route::get('distributors/{id}', array('before' =>'profile', 'uses'=>'DistributorController@show')); Route::get('distributors/{id}/edit', 'DistributorController@edit'); Route::put('distributors/{id}/update', array('as'=>'distributors.update', 'uses'=>'DistributorController@update')); Route