问题
I am using Laravel 5 and need to do a wildcard route, sending the user to different controllers based on the URL type, pulled in from the database.
I need to check the URL slug in the database, and then load the relevant controller/method based on the slug type, held in the database. I am struggling with the final part, which is sending the user to the relevant controller. Below is my route:
Route::any('{slug}', function($slug){
$url = \App\Url_slug::where('url_slug', $slug)->first();
if($url->count()){
switch($url->url_type){
case 'product':
// SEND USER TO PRODUCT CONTROLLER
break;
case 'category':
// SEND USER TO CATEGORY CONTROLLER
break;
case 'page':
// SEND USER TO PAGE CONTROLLER
break;
}
} else {
abort(404);
}
});
What do I need to replace the comments with in order the send the user to the relevant controller?
回答1:
To do this, you need to load an instance of app() and then call make('Controller') method as well as callAction. Full route below:
Route::any('{slug}', function($slug){
$url = \App\Url_slug::where('url_slug', $slug)->first();
if($url->count()){
$app = app();
switch($url->url_type){
case 'product':
$controller = $app->make('App\Http\Controllers\ProductController');
break;
case 'category':
$controller = $app->make('App\Http\Controllers\CategoryController');
break;
case 'page':
$controller = $app->make('App\Http\Controllers\PageController');
break;
}
return $controller->callAction('view', ['url_slug' => $url->url_slug, 'url_slug_id' => $url->id]);
} else {
abort(404);
}
});
回答2:
You can simply resolve a controller instance from the service container, and call methods on that:
return app('App\Http\Controllers\ProductController')->show($product);
This will call the ProductController@show action, pass whatever is in $product as a parameter, and return the rendered Blade template.
来源:https://stackoverflow.com/questions/31721736/how-can-i-do-variable-wildcard-routes-in-laravel