lapply

I need to access list names inside the lapply function. I've found some threads online where it's said I should iterate through the names of the list to be able to fetch each list element name in my function: > n = names(mylist) > mynewlist = lapply(n, function(nameindex, mylist) { return(mylist[[nameindex]]) }, mylist) > names(mynewlist) NULL > names(mynewlist) = n The problem is that mynewlist loses the original mylist indexes and I have to add that last names() assignment to restore them. Is there a way to give an explicit index name to each element returned by the lapply function? Or a

I have a question regarding passing multiple arguments to a function, when using lapply in R . When I use lapply with the syntax of lapply(input, myfun); - this is easily understandable, and I can define myfun like that: myfun <- function(x) { # doing something here with x } lapply(input, myfun); and elements of input are passed as x argument to myfun . But what if I need to pass some more arguments to myfunc ? For example, it is defined like that: myfun <- function(x, arg1) { # doing something here with x and arg1 } How can I use this function with passing both input elements (as x argument)

I have used lapply to apply a function to a number of data frames: data.cleaned <- lapply(data.list, shooter_cleaning) And then labeled each of the resulting data frames in the list according to their subject number (e.g., 100): names(data.cleaned) <- subject.names What I want to do is to save each new data frame as an individual .csv file based on its subject number. For example, for subject 100 I'd like the .csv file to be labeled as "100.csv" Normally to do this (for a single data frame) I would just write (where x is the data frame): write.csv(x, "100.csv", row.names = F) But, obviously