lapply

In order to be able to process I'd like to replace the first occurrence of a : in a string (which is my marker, that a speech begins). text <- c("Mr. Mark Francois (Rayleigh) (Con): If the scheme was so poorly targeted, why were the Government about to roll it out to employees in the Department of Trade and Industry and the Department for Work and Pensions on the very day the Treasury scrapped it? The CBI and the TUC have endorsed the scheme, which has helped 500,000 people and their families to improve their computer skills. When the Chancellor announced the original concession, he told the

I'm making plots of one y variable against multiple x variables. I have a working solution using lapply. However, I can't manage to write the name of the x variable as the x label for each plot. Here's a simplified example of what I have: The goal is to plot the y variable against each x variable resulting in three plots and adding the name of each x variable as the x axis label. Generate a dataframe with one y variable and three x variables: df <- data.frame(y.variable=c(11:20), x1=c(21:30),x2=c(1:10),x3=c(31:40)) A function that is supposed to retrieve the variable name as a string: get_name

I am trying to use lapply (and want the solution with lapply) to rename columns of a data.frame located in a list, but it's returning names, not the renamed data.frames: # define list li <- list(u_n = data.frame(x = 1:3), r_l = data.frame(y = 4:6)) # trying to rename columns after the element of the list they're located in li_2 <- lapply(1:length(li), function(x,y) colnames(y[[x]]) <- names(y)[x], y = li) However, this returns: [[1]] [1] "u_n" [[2]] [1] "r_l" If I use the same method as the function specified in lapply individually, it does work: li[1] $u_n x 1 1 2 2 3 3 colnames(li[[1]]) <-

I'm trying to use lapply on a list of data frames; but failing at passing the parameters correctly (I think). List of data frames: df1 <- data.frame(A = 1:10, B= 11:20) df2 <- data.frame(A = 21:30, B = 31:40) listDF <- list(df1, df2,df3) #multiple data frames w. way less columns than the length of vector todos Vector with columns names: todos <-c('col1','col2', ......'colN') I'd like to change the column names using lapply: lapply (listDF, function(x) { colnames(x)[2:length(x)] <-todos[1:length(x)-1] } ) but this doesn't change the names at all. Am I not passing the data frames themselves, but

I am new to R, and this is a very simple question. I've found a lot of similar things to what I want but not exactly it. Basically I have multiple data frames and I simply want to run the same function across all of them. A for-loop could work but I'm not sure how to set it up properly to call data frames. It also seems most prefer the lapply approach with R. I've played with the get function as well to no avail. I apologize if this is a duplicated question. Any help would be greatly appreciated! Here's my over simplified example: 2 data frames: df1, df2 df1 start stop ID 0 10 x 10 20 y 20 30

I have a list of data frames and have given each element in the list (e.g. each data frame) a name: e.g. df1 <- data.frame(x = c(1:5), y = c(11:15)) df2 <- data.frame(x = c(1:5), y = c(11:15)) mylist <- list(A = df1, B = df2) I have a function that I want to apply to each data frame; In this function, I want to include a line to write the results to file (eventually I want to do more complicated things like save plots of the correlation between two variables for each data frame but thought I'd start simple) e.g. NewVar <- function(mydata, whichVar, i) { mydata$newVar <- mydata[, whichVar] + 1