keyboard

问题 i ran in to Problem while trying Textfield Widget :"bottom overflowed by 48pixels".after that i tried to use SingleChildScrollView widget,but it became more complicated,it shows now this error: ======== Exception caught by rendering library ===================================================== RenderBox was not laid out: RenderCustomPaint#7fee2 relayoutBoundary=up3 NEEDS-PAINT any Suggestion how can i solve this Problem?! emulator without use of SingleCHildScrollView import 'package:flutter

问题 I am developing an android custom keyboard and i want to send stickies to my friends for example on hangouts from my keyboard. I added some png for this. When I use the android's share api I have to select first an app to share with. Is it possible to detect the current opened application from my keyboard? For example if I am chatting with hangouts then I want to call the intent telling it to share with "com.something.hangouts" If I am in FB messenger then telling it "com.something.facebook

问题 I regularly code in R, and I just realized how much of a pain it is for me to move my hand down to the arrow keys and then back to they letters on the keyboard. In Rstudio, I have to do this regularly because the studio completes certain synax automatically, (like parentheses and quotation marks) and then I have to press the arrow key to move out of the parentheses (or quotation marks), this then removed any possible advantage from having R complete the syntax for me. This is extra costly for

问题 I would like to know how to detect the keyboard adapter on Windows when using two keyboards, that a key eg. W was pressed on first or on the second keyboard. Can anybody help me how to do it? I would like to use a cheap solution for macros. I would plan to bind macros for entrie second keyboard, when somebody press key W (just for example), keybaord would type a world uint8_t. 来源： https://stackoverflow.com/questions/61139696/c-getting-keyboard-adapter-when-using-two-keyboards-determine-where

问题 I am receiving the error: Warning: Functions are not valid as a React child. I am writing a React Native application. interface RegisterScreenProps { navigation: NavigationContainerRef; } const RegisterScreen: FunctionComponent<RegisterScreenProps> = ({ navigation, }: RegisterScreenProps) => { const { container, headerLogo, headerTitle, body } = styles; return ( <SafeAreaView style={{ flex: 1 }}> <KeyboardAwareScrollView style={styles.container}> <View> <TextInput value={

问题 I am receiving the error: Warning: Functions are not valid as a React child. I am writing a React Native application. interface RegisterScreenProps { navigation: NavigationContainerRef; } const RegisterScreen: FunctionComponent<RegisterScreenProps> = ({ navigation, }: RegisterScreenProps) => { const { container, headerLogo, headerTitle, body } = styles; return ( <SafeAreaView style={{ flex: 1 }}> <KeyboardAwareScrollView style={styles.container}> <View> <TextInput value={

问题 I am trying to capture single keyboard inputs in a non blocking way inside a while loop using boost asio async_read. The handler is expected to display the read characters. My code: #include <boost/asio/io_service.hpp> #include <boost/asio/posix/stream_descriptor.hpp> #include <boost/asio/read.hpp> #include <boost/system/error_code.hpp> #include <iostream> #include <unistd.h> #include <termios.h> using namespace boost::asio; void read_handler(const boost::system::error_code&, std::size_t) {

问题 I am creating one chatting application and there I want to open the emoji keyboard when the user clicks on the emoji icon it will open the emoji keyboard. here are the image and I want to open the emoji keyboard on click on the left side emoji icon. 回答1: Use Emoji Picker for this, below is the complete example import 'package:emoji_picker/emoji_picker.dart'; import 'package:flutter/material.dart'; void main() => runApp(MainApp()); class MainApp extends StatelessWidget { @override Widget build

问题 How can I activate/deactivate a button based on the content of a TextFormField? I want to make sure a user can only press Button X if the TextFormField has 10 entered numbers (if it's a mobile number). Thanks! 回答1: A simple way would be to set the autovalidate property of our TextFormField to true . This will automatically detect for changes on our TextFormField widget. We can then try to check if our TextFormField's value has a String length of 10 characters on the validator property . After

问题 How can I activate/deactivate a button based on the content of a TextFormField? I want to make sure a user can only press Button X if the TextFormField has 10 entered numbers (if it's a mobile number). Thanks! 回答1: A simple way would be to set the autovalidate property of our TextFormField to true . This will automatically detect for changes on our TextFormField widget. We can then try to check if our TextFormField's value has a String length of 10 characters on the validator property . After