kadanes-algorithm

Finding minimal absolute sum of a subarray

由 梦想的初衷 提交于 2019-12-18 04:42:22
问题 There's an array A containing (positive and negative) integers. Find a (contiguous) subarray whose elements' absolute sum is minimal, e.g.: A = [2, -4, 6, -3, 9] |(−4) + 6 + (−3)| = 1 <- minimal absolute sum I've started by implementing a brute-force algorithm which was O(N^2) or O(N^3) , though it produced correct results. But the task specifies: complexity: - expected worst-case time complexity is O(N*log(N)) - expected worst-case space complexity is O(N) After some searching I thought that

find all subarrays in o(n) time 1D array using javascript

由 天涯浪子 提交于 2019-12-13 09:29:25
问题 I want to collect all subarrays for further computation efficiently in javascript. I'm not sure this is possible, but it seems for a subarray sum kadane's formula is o(n) which is more efficient than other methods. But I'm not sure I how I can store the array at each step. Similar to this quora question, for me the pseudo code was not enough. Thanks for the further breakdown. another meta link an example in action of this for [3, 3, 9, 9, 5] [3], [9], [5], [9, 5], [9, 3], [9, 9], [3, 3], [3,

Finding the maximum sublist in Prolog

由 瘦欲@ 提交于 2019-12-10 17:42:09
问题 I'm new to Prolog and trying to solve instances of the maximum subarray problem. I have got the following quite elegant C++ code: int maxSubArray(vector<int> List) { int maxsofar = 0; int maxendinghere = 0; for (int i = 0; i < List.size(); i++) { maxendinghere = max(maxendinghere+List[i], 0); maxsofar = max(maxsofar, maxendinghere); } return maxsofar; } And here is my Prolog code: max(X,X,X). max(X,Y,X) :- X>Y. max(X,Y,Y) :- X<Y. %define max function prev(L,T,H) :- reverse(L,[H|T1]), reverse

How to implement Kadane algorithm for 2D matrix [closed]

由 怎甘沉沦 提交于 2019-12-08 05:28:29
Closed. This question is off-topic . It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I am trying to figure out how to implement C# code for Kadane's 2D Matrix algorithm. I found a 1D version here: Kadane's algorithm to find subarray with the maximum sum But I want a 2D version. Basically, given a Matrix N x N of positive and negative numbers, I need to find a submatrix where sum of all elements would be the greatest. Figured it out. For those who is interested static void Main(string[] args) {

How to implement Kadane algorithm for 2D matrix [closed]

由 筅森魡賤 提交于 2019-12-08 05:08:32
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I am trying to figure out how to implement C# code for Kadane's 2D Matrix algorithm. I found a 1D version here: Kadane's algorithm to find subarray with the maximum sum But I want a 2D version. Basically, given a Matrix N x N of positive and negative numbers, I need to find a submatrix where sum of all elements

Does Kadane's Max Sub Array algorithm work on all positive integer array?

由 徘徊边缘 提交于 2019-12-05 22:50:10
I Implemented the Kadane's Max Sub array problem in javascript but seems i end up always getting 0 in the console even though there exists higher numbers( I understand that it does what it's doing because of for loop from 0 - size where size = subarray size ). So how do i implement the algorithm correctly? Does it also work for all positive integer array? JsBin http://jsbin.com/ajivan/edit#javascript,live You're passing n=3 as an argument while your array has length 6. I changed your algorithm to use length : function SubSequence(a){ var now = 0,prev =0; for(var i = 0;i < a.length;i++){ prev =

Kadane's algorithm to find subarray with the maximum sum [duplicate]

由 那年仲夏 提交于 2019-12-05 22:45:30
问题 This question already has answers here : Maximum sum sublist? (13 answers) Closed 5 years ago . I have the following implementation of Kadane's algorithm to solve the problem of the maximum subarray of an array: public static decimal FindBestSubsequence (this IEnumerable<decimal> source, out int startIndex, out int endIndex) { decimal result = decimal.MinValue; decimal sum = 0; int tempStart = 0; List<decimal> tempList = new List<decimal>(source); startIndex = 0; endIndex = 0; for (int index

How to find a subarray with minimum k length and maximum sum?

由 只愿长相守 提交于 2019-12-05 20:53:22
The subarray contains both positive and negative numbers. You have to find a maximum sum subarray such that the length of the sub-array is greater than or equal to k. Here is my code in c++ using Kadane's algorithm. #include <iostream> using namespace std; int main(){ int n,k; cin >> n >> k; int array[n]; int sum = 0; int maxsum = 0; int beststarts[n]; for(int i = 0;i < n; i++){ cin >> array[i]; } for(int i = 0;i < k-1;i ++){ sum = sum+array[i]; beststarts[i] = 0; } for(int i = k-1;i < n; i++){ //best end search with min length; sum = sum+array[i]; int testsum = sum; if(i > 0){ beststarts[i] =

kadane algorithm in java

由 让人想犯罪 __ 提交于 2019-12-05 18:23:39
问题 I have the following implementation of Kadane's algorithm in java. It is basically to find the maximum sum of contiguous subarray. String[] numbers = string.split(","); int max_so_far = 0; int max_ending_here = 0; for (int i = 0; i < numbers.length-1;i++){ max_ending_here = max_ending_here + Integer.parseInt(numbers[i]); if (max_ending_here < 0) max_ending_here = 0; if (max_so_far < max_ending_here) max_so_far = max_ending_here; } System.out.println(max_so_far); However this doesn't work if

Kadane's algorithm to find subarray with the maximum sum [duplicate]

由 旧城冷巷雨未停 提交于 2019-12-04 03:21:00
This question already has answers here : Closed 5 years ago . Maximum sum sublist? (13 answers) I have the following implementation of Kadane's algorithm to solve the problem of the maximum subarray of an array: public static decimal FindBestSubsequence (this IEnumerable<decimal> source, out int startIndex, out int endIndex) { decimal result = decimal.MinValue; decimal sum = 0; int tempStart = 0; List<decimal> tempList = new List<decimal>(source); startIndex = 0; endIndex = 0; for (int index = 0; index < tempList.Count; index++) { sum += tempList[index]; if ((sum > result) || (sum == result &&
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