java.util.scanner

what's the correct way to use multiple Scanner objects in my program. For example, I use scanner to read a file, then depending on what is found in the file, i use scanner again to prompt for user input. An extract of my code is shown .... Scanner f = new Scanner (System.in); //get the file name String fileName = f.next(); Scanner input = new Scanner( new File( fileName ) ); while ( input.hasNext() ) { String currentLine = input.nextLine(); if ( some pattern found) { Scanner getUserInput = new Scanner (System.in); String userInput = getUserInput.next(); ..... } } .... It doesn't seem to work.

I have a class that creates multiple Integer objects and puts them into a LinkedList as shown below: public class Shares<E> implements Queue<E> { protected LinkedList<E> L; public Shares() { L = new LinkedList<E>(); } public boolean add(E price) { System.out.println("How many of these shares would you like?"); Scanner scanInt; scanInt = new Scanner(System.in); Integer noShares = scanInt.nextInt(); for (int i = 0; i < noShares; i++) { L.addLast(price); } scanInt.close(); return true; } } I have an application that scans for the input "add" from the console and if found, invokes the method add

I am writing a program that asks for the person's full name and then takes that input and reverses it (i.e John Doe - Doe, John). I started by trying to just get the input, but it is only getting the first name. Here is my code: public static void processName(Scanner scanner) { System.out.print("Please enter your full name: "); String name = scanner.next(); System.out.print(name); } Prabhakaran Change to String name = scanner.nextLine(); instead of String name = scanner.next(); See more on documentation here - next() and nextLine() Try replacing your code String name = scanner.nextLine();

Sorry if this sounds too simple. I'm very new to Java. Here is some simple code I was using to examine hasNextLine() . When I run it, I can't make it stop. I thought if you didn't write any input and pressed Enter , you would escape the while loop. Can someone explain to me how hasNextLine() works in this situation? import java.util.*; public class StringRaw { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while (sc.hasNextLine()) { String str = sc.nextLine(); } System.out.print("YOU'VE GOT THROUGH"); } } When reading from System.in, you are reading from the

What is the Scanner method to get a char returned by the keyboard in Java. like nextLine() for String , nextInt() for int , etc. To get a char from a Scanner , you can use the findInLine method. Scanner sc = new Scanner("abc"); char ch = sc.findInLine(".").charAt(0); System.out.println(ch); // prints "a" System.out.println(sc.next()); // prints "bc" If you need a bunch of char from a Scanner , then it may be more convenient to (perhaps temporarily) change the delimiter to the empty string. This will make next() returns a length-1 string every time. Scanner sc = new Scanner("abc"); sc

Here's some sample code: import java.util.Scanner; class In { public static void main (String[]arg) { Scanner in = new Scanner (System.in) ; System.out.println ("how many are invading?") ; int a = in.nextInt() ; System.out.println (a) ; } } If I run the program and give it an int like 4 , then everything goes fine. On the other hand, if I answer too many it doesn't laugh at my funny joke. Instead I get this(as expected): Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:819) at java.util.Scanner.next(Scanner.java:1431) at java.util.Scanner