intervals

Why is datediff interval “weekday” returning interval based on weeks and not days minus weekends?

由 只谈情不闲聊 提交于 2019-11-26 14:58:46
问题 I'm using the expression builder to give me a calculated value. It looks like this: =DateDiff("w",Date(),[Latest_Call_Date]) However, this is giving me results as if it were doing a calculation based on weeks instead of days minus weekends . When I try the same function, but with the interval set to days (d) instead of weekdays (w) I get the expected results (but of course, including Saturdays and Sundays, which I do not wish to include in the calculation). So, for example, for everyday this

Union of intervals

由 喜你入骨 提交于 2019-11-26 14:17:43
问题 I've got a class representing an interval. This class has two properties "start" and "end" of a comparable type. Now I'm searching for an efficient algorithm to take the union of a set of such intervals. Thanks in advance. 回答1: Sort them by one of the terms (start, for example), then check for overlaps with its (right-hand) neighbor as you move through the list. class tp(): def __repr__(self): return '(%d,%d)' % (self.start, self.end) def __init__(self,start,end): self.start=start self.end

Using a variable period in an interval in Postgres

由 左心房为你撑大大i 提交于 2019-11-26 14:11:32
问题 I have a relation that maintains monthly historical data. This data is added to the table on the last day of each month. A service I am writing can then be called specifying a month and a number of months prior for which to retrieve the historical data. I am doing this by creating startDate and endDate variables, and then returning data between the two. The problem I am having is that startDate is a variable number of months before endDate, and I cannot figure out how to use a variable period

C: How to wrap a float to the interval [-pi, pi)

由 拥有回忆 提交于 2019-11-26 11:58:03
问题 I\'m looking for some nice C code that will accomplish effectively: while (deltaPhase >= M_PI) deltaPhase -= M_TWOPI; while (deltaPhase < -M_PI) deltaPhase += M_TWOPI; What are my options? 回答1: Edit Apr 19, 2013: Modulo function updated to handle boundary cases as noted by aka.nice and arr_sea: static const double _PI= 3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348; static const double _TWO_PI= 6

Algorithm to find the maximum sum in a sequence of overlapping intervals

由 荒凉一梦 提交于 2019-11-26 11:56:31
问题 The problem I am trying to solve has a list of intervals on the number line, each with a pre-defined score. I need to return the maximum possible total score. The catch is that the intervals overlap, and of the overlapping intervals I can use only one. Here is an example. Intervals - Score 0- 5 - 15 4- 9 - 18 10-15 - 12 8-21 - 19 25-30 - 25 Here, the intervals 0-5, 4-9 and 8-21 overlap. The intervals 10-15 and 8-21 also overlap. The maximum sum would be 55 (18+12+25). It is important to note

Do something every x minutes in Swift

由 我的梦境 提交于 2019-11-26 11:39:49
How can I run a function every minute? In JavaScript I can do something like setInterval , does something similar exist in Swift? Wanted output: Hello World once a minute... Unheilig var helloWorldTimer = NSTimer.scheduledTimerWithTimeInterval(60.0, target: self, selector: Selector("sayHello"), userInfo: nil, repeats: true) func sayHello() { NSLog("hello World") } Remember to import Foundation. Swift 4: var helloWorldTimer = Timer.scheduledTimer(timeInterval: 60.0, target: self, selector: #selector(ViewController.sayHello), userInfo: nil, repeats: true) @objc func sayHello() { NSLog("hello

Find date range overlaps within the same table, for specific user MySQL

由 倾然丶 夕夏残阳落幕 提交于 2019-11-26 11:32:11
问题 I am by no means an MySQL expert, so I am looking for any help on this matter. I need to perform a simple test (in principle), I have this (simplified) table: tableid | userid | car | From | To -------------------------------------------------------- 1 | 1 | Fiesta | 2015-01-01 | 2015-01-31 2 | 1 | MX5 | 2015-02-01 | 2015-02-28 3 | 1 | Navara | 2015-03-01 | 2015-03-31 4 | 1 | GTR | 2015-03-28 | 2015-04-30 5 | 2 | Focus | 2015-01-01 | 2015-01-31 6 | 2 | i5 | 2015-02-01 | 2015-02-28 7 | 2 |

Find which interval row in a data frame that each element of a vector belongs in

由 蓝咒 提交于 2019-11-26 09:46:37
问题 I have a vector of numeric elements, and a dataframe with two columns that define the start and end points of intervals. Each row in the dataframe is one interval. I want to find out which interval each element in the vector belongs to. Here\'s some example data: # Find which interval that each element of the vector belongs in library(tidyverse) elements <- c(0.1, 0.2, 0.5, 0.9, 1.1, 1.9, 2.1) intervals <- frame_data(~phase, ~start, ~end, \"a\", 0, 0.5, \"b\", 1, 1.9, \"c\", 2, 2.5) The same

Create a simple countdown in processing

由 血红的双手。 提交于 2019-11-26 08:37:03
问题 I have searched up so many sites on Google to try and get this to work but NO ONE seems to have this anywhere , and if they do it\'s just NOT working with my program... What I am trying to achieve is to have a player recoil that when the player gets hit, he has a \"x\" amount of time between getting hit the first time and the second time. So I have a Boolean \"hit\" = false and when he gets hit, it changes to true . Which means he can\'t get hit again until it\'s changed to false again. So I\

format interval with to_char

由 我是研究僧i 提交于 2019-11-26 08:30:50
问题 Following SQL command select TO_CHAR(NVL(arg1 - arg2, TO_DSINTERVAL(\'0 00:00:00\'))) from table1 produces a result of the format: +000000000 00:03:01.954000. Is it possible to enter a special format in the to_char function in order to get a result of format: +00 00:00:00.000? 回答1: I realize it's not clever at all, nor is it the special format string you're looking for, but this answer does work, given that the output is fixed length: SELECT SUBSTR(TO_CHAR(NVL(arg1 - arg2, TO_DSINTERVAL('0 00
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