intervals

Create a jQuery special event for content changed

感情迁移 提交于 2019-11-27 05:20:09
问题 I'm trying to create a jQuery special event that triggers when the content that is bound, changes. My method is checking the content with a setInterval and check if the content has changed from last time. If you have any better method of doing that, let me know. Another problem is that I can't seem to clear the interval. Anyway, what I need is the best way to check for content changes with the event.special. (function(){ var interval; jQuery.event.special.contentchange = { setup: function

SQL: Merge Date Ranges

天涯浪子 提交于 2019-11-27 04:38:17
问题 I've a table, which describes work slices of a business working calendar: (date format is 24 hours format) PK | STARTDATE | ENDDATE __________________________________________ 1 | 2012/07/21 02:00 | 2012/07/21 04:00 2 | 2012/07/21 03:00 | 2012/07/21 10:00 3 | 2012/07/21 06:00 | 2012/07/21 17:00 4 | 2012/07/21 18:00 | 2012/07/21 19:00 Now, I like to merge the date ranges (within a given start and end date) like this: PK | STARTDATE | ENDDATE __________________________________________ 1 | 2012

Merge Records Over Time Interval

青春壹個敷衍的年華 提交于 2019-11-27 03:41:43
问题 Let me begin by saying this question pertains to R (stat programming language) but I'm open straightforward suggestions for other environments. The goal is to merge outcomes from dataframe (df) A to sub-elements in df B. This is a one to many relationship but, here's the twist , once the records are matched by keys they also have to match over a specific frame of time given by a start time and duration. For example, a few records in df A: OBS ID StartTime Duration Outcome 1 01 10:12:06 00:00

Postgres birthdays selection

二次信任 提交于 2019-11-27 03:36:15
问题 I work with a Postgres database. This DB has a table with users, who have a birthdate (date field). Now I want to get all users who have their birthday in the upcoming week.... My first attempt: SELECT id FROM public.users WHERE id IN (lange reeks) AND birthdate > NOW() AND birthdate < NOW() + interval '1 week' But this does not result, obviously because off the year. How can I work around this problem? And does anyone know what happen to PG would go with the cases at 29-02 birthday? 回答1: We

Create a simple countdown in processing

你说的曾经没有我的故事 提交于 2019-11-27 02:14:36
I have searched up so many sites on Google to try and get this to work but NO ONE seems to have this anywhere , and if they do it's just NOT working with my program... What I am trying to achieve is to have a player recoil that when the player gets hit, he has a "x" amount of time between getting hit the first time and the second time. So I have a Boolean "hit" = false and when he gets hit, it changes to true . Which means he can't get hit again until it's changed to false again. So I'm trying to set up a function in my program to set a "timer" for "x" amount of seconds IF hit = true and once

In JavaScript, how can I have a function run at a specific time?

泪湿孤枕 提交于 2019-11-27 01:55:54
问题 I have a website that hosts a dashboard: I can edit the JavaScript on the page and I currently have it refreshing every five seconds. I am trying to now get a window.print() to run every day at 8 AM. How could I do this? 回答1: JavaScript is not the tool for this. If you want something to run at a specific time every day, you're almost certainly looking for something that runs locally, like python or applescript. However, let's consider for a moment that JavaScript is your only option. There

Find which interval row in a data frame that each element of a vector belongs in

我们两清 提交于 2019-11-27 01:47:02
I have a vector of numeric elements, and a dataframe with two columns that define the start and end points of intervals. Each row in the dataframe is one interval. I want to find out which interval each element in the vector belongs to. Here's some example data: # Find which interval that each element of the vector belongs in library(tidyverse) elements <- c(0.1, 0.2, 0.5, 0.9, 1.1, 1.9, 2.1) intervals <- frame_data(~phase, ~start, ~end, "a", 0, 0.5, "b", 1, 1.9, "c", 2, 2.5) The same example data for those who object to the tidyverse: elements <- c(0.1, 0.2, 0.5, 0.9, 1.1, 1.9, 2.1) intervals

Merging intervals in one pass in SQL

ぐ巨炮叔叔 提交于 2019-11-26 23:23:59
问题 Let's say I have a table with two columns: start and end , both integers, and the table is ordered by the first, then second column. Each row represents an interval. What I need is the table of merged intervals: all overlapping or adjacent intervals gobbled up into one. It can be constructed with a JOIN query, but that is quadratic in the number of rows, which is 4 million rows in my case (I decided to compose this question because the query is still running). It can also be done in a single

how to overlap intervals efficiently

余生长醉 提交于 2019-11-26 21:56:36
问题 I require your help, I have a problem (see picture), I have let say two arrays and each of this array contains intervals with different length and real values and I need to find out how I'm gone overlap this intervals efficiently. I'm open to ideas, or paper theory or concret algorithms which will let me find a way out! I'm guessing about to transform this somehow in waves and overlap them. Its very important, its for my thesis. as an example, here in numbers to explain it better: Array: 1-2,

How to map the PostgreSQL Interval column type in Hibernate?

时光毁灭记忆、已成空白 提交于 2019-11-26 21:16:02
问题 Under PostgreSQL, I'm using PersistentDuration for the mapping between the sql type interval & duration but it doesn't work. Another user found the same issue & come with his own class: public void nullSafeSet(PreparedStatement statement, Object value, int index) throws HibernateException, SQLException { if (value == null) { statement.setNull(index, Types.OTHER); } else { Long interval = ((Long) value).longValue(); Long hours = interval / 3600; Long minutes = (interval - (hours * 3600)) / 60;