intervals

I have two objects calendar Calendar startCalendar = new GregorianCalendar(2013,0,31); Calendar endCalendar = new GregorianCalendar(); I want to know if the interval between the two dates listed above is covered by n of other objects pair calendars without holes between intervals Example1: Calendar startCalendar1(2013,0,31); Calendar endCalendar1(2014,0,31); Calendar startCalendar2(2013,5,31); Calendar endCalendar2(); Is GOOD Example2: Calendar startCalendar1(2013,0,31); Calendar endCalendar1(2014,0,31); Calendar startCalendar2(2014,2,31); Calendar endCalendar2(); NOT GOOD I use Java 6 Thanks

How can I set a macro to run at a specific time and then at set intervals afterwards? I would like it to run at the top of each hour so I would like to start it at 07:00AM for example and then every hour after I want it to run again. Here is the code: Sub Refresh_All() ' ' Refresh_All Macro ' ' Keyboard Shortcut: Ctrl+Y ' ChDir "Q:\Quality Control" Workbooks.Open Filename:= _ "Q:\Quality Control\Internal Failure Log - Variable Month.xlsm" Dim endTime As Date endTime = DateAdd("s", 10, Now()) Do While Now() < endTime DoEvents Loop ActiveWorkbook.RefreshAll endTime = DateAdd("s", 10, Now()) Do

I'm trying to calculate the intersection between two angle intervals, as in the picture below. Unfortunately, the branch at -pi is making the code much uglier than I have hoped. Here is my first draft. Note that I have not tested this code for correctness, but rather have just gone through the scenarios in my head. As you can see in the function branchify , angle intervals are constrained such that from (p)a1 -> (p)a2 counter-clockwise, the difference is at most pi. In otherwise, the intervals are defined by the smallest difference in angle. [a1, a2] is the first interval, [pa1, pa2] the

I have been searching for an efficient algorithm to merge overlapping intervals on a dynamic array of intervals. For example, (start time, end time) wise, [(1, 2), (4, 8), (3, 10)] becomes [(1, 2), (3, 10)] after merging because (4, 8) and (3, 10) are overlapped. Overlapping means any part of the two intervals share the same moment. I know when a full array is given the operation can be done with a stack after sorting the intervals on start time ascending order ( reference: geeksforgeeks ). But this algorithm is effectively applicable only when given array is non dynamic, but I am searching

I have asked this question a long time ago, but haven't found the answer yet. I do not know if this is legit in stackoverflow, but I repost it. I have a data.table in R and I want to create a new column that finds the interval for every price of the respective year/month. Reproducible example: set.seed(100) DT <- data.table(year=2000:2009, month=1:10, price=runif(5*26^2)*100) intervals <- list(year=2000:2009, month=1:10, interval = sort(round(runif(9)*100))) intervals <- replicate(10, (sample(10:100,100, replace=T))) intervals <- t(apply(intervals, 1, sort)) intervals.dt <- data.table

Without creating multiple NSTimer instances, how would one achieve an NSTimer to fire a specific or multiple method with different intervals in a sequence. For example method1 (0.3 sec), method2 (0.5), method3 (0.7) and so on. I would appreciate if someone could please share any example code. holex I'm not sure what your final goal is with this but after reading your question I would recommend to try the following way , maybe this is what you'd look for. you should put this code where you normally wanted to start the same NSTimer class with different intervals (what is not possible,

I have two sets of ranges, represented by [ start, stop ] values. Some of the ranges overlap, meaning that the start of one range is in between the [ start, stop ] of the other range. I'd like to make a new set of ranges that has no such overlap, and also doesn't include any new values in a range. The ranges look like this: @starts @ends 5 108 5 187 44 187 44 229 44 236 64 236 104 236 580 644 632 770 The output that I expect would be this: @starts @ends 5 236 580 770 This is because the first seven ranges overlap with the interval from 5 => 236, and the last two overlap with the interval from