intervals

问题 I am a new user of matlab and I want to tackle the following problem: I want to construct a piecewise constant function f . f should be an anonymous function like f=@(t)1[0,0.25)(t) . However, the number of intervals for the piecewise constant function is not fixed in general. Instead, the piecewise interval depends on users input. For example, if one enters 4, the piecewise interval becomes [0,0.25), [0.25,0.5), [0.5,0.75) and [0.75,1) then f=@(t)a1*1[0,0.25)(t)+a2*[0.25,0.5)(t)+a3*1[0.5,0

问题 I am trying to make a simple 'Simon Game'. I am currently stuck trying to add a class 'on' to a div for one second, then remove that class for the same amount of time. So I have four divs that I am blinking on and off depending on a sequence of numbers, e.g. [0, 1, 2, 3] . This would blink div[0] on for one second and off for one second then move to div[1] , on and off and so on. Here is my function /** * sequence => array [0, 1, 2, 3] * speed => int 1000 (one second) */ playSequence:

问题 I'm converting an Oracle SQL outer interval join in Pandas Dataframe. Below is the Oracle SQL: WITH df_interval AS (SELECT '1' id, 'AAA' interval, 1000 begin, 2000 end FROM DUAL UNION ALL SELECT '1' id, 'BBB' intrvl, 2100 begin, 3000 end FROM DUAL UNION ALL SELECT '2' id, 'CCC' intrvl, 3100 begin, 4000 end FROM DUAL UNION ALL SELECT '2' id, 'DDD' intrvl, 4100 begin, 5000 end FROM DUAL), df_point AS (SELECT '1' id, 'X1' point, 1100 mid FROM DUAL UNION ALL SELECT '1' id, 'X2' point, 2050 mid

问题 This is a question for the algorithms gurus out there :-) Let S be a set of intervals of the natural numbers that might overlap and N be a list of numbers. I want to find the smallest subset (let's call P) of S such that for each number in our list N, there exists at least one interval in P that contains it. The intervals in P are allowed to overlap. Trivial example: S = {[1..4], [2..7], [3..5], [8..15], [9..13]} N = [1, 4, 5] // so P = {[1..4], [2..7]} I think a dynamic algorithm might not

问题 I have table with two columns like this: +-----------+------------+ | FROM | TO | +-----------+------------+ |2015-03-01 | 2015-03-04 | |2015-03-05 | 2015-03-09 | +-----------+------------+ And I want to write the function which will take two arguments - DateFrom, and DateTo, and check this interval. For example, if function takes DateFrom = 2015-03-03 , and DateTo = 2015-03-08 as arguments it should return true , because every day from this interval is in table. But if table is like this: +-

问题 I need a subsystem that needs to output 1 at interval or 30 seconds or slightly over 30 seconds. Written in matlab code it should work like that function y = fcn(time,uplinkTimeInterval) %#codegen persistent lastTriggerTime if isempty(lastTriggerTime) lastTriggerTime = 0; end if time>=lastTriggerTime || time == 0 y = 1; lastTriggerTime = time + uplinkTimeInterval; else y = 0; end end where ulplinkTimeInterval is 30 seconds. Of course I tried to use the matlab function block with this code but

问题 You are given two lists of intervals, A and B . In A , the intervals are sorted by their starting points. None of the intervals within A overlap. Likewise, in B , the intervals are sorted by their starting points. None of the intervals within B overlap. Return the intervals that overlap between the two lists. Example: A: {[0,4], [7,12]} B: {[1,3], [5,8], [9,11]} Return: {[1,3], [7,8], [9,11]} I got this in an interview and was stumped. I thought of comparing intervals between the two lists.

问题 I want to create an array containing values from 0 to 1 with interval of 0.1. I can use: float[] myArray = new float[10]; float increment = 0.1; for(i = 0; i < 10; i++) { myArray[i] = increment; increment += 0.1; } I was wondering whether there is a function like Enumerable.Range that permits to specify also the increment interval. 回答1: An interesting fact is that every answer posted so far has fixed the bug in your proposed code, but only one has called out that they've done so. Binary

问题 I am trying to collapse a series of intervals into fewer, equally meaningful intervals. Consider for example this list of intervals Intervals = list( c(23,34), c(45,48), c(31,35), c(7,16), c(5,9), c(56,57), c(55,58) ) Because the intervals overlap, the same intervals can be described with few vectors. Plotting these intervals make obvious that a list of 4 vectors would be enough plot(1,1,type="n",xlim=range(unlist(Intervals)),ylim=c(0.9,1.1)) segments( x0=sapply(Intervals,"[",1), x1=sapply

问题 With a the R package data.table is it possible to find the values that are in a given interval without a full vector scan of the data. For example >DT<-data.table(x=c(1,1,2,3,5,8,13,21,34,55,89)) >my.data.table.function(DT,min=3,max=10) x 1: 3 2: 5 3: 8 Where DT can be a very big table. Bonus question: is it possible to do the same thing for a set of non-overlapping intervals such as >I<-data.table(i=c(1,2),min=c(3,20),max=c(10,40)) >I i min max 1: 1 3 10 2: 2 20 40 > my.data.table.function2