intervals

问题 I would like to run a for loop in Python that checks, given a certain amount of intervals, for each element of the loop, in which interval it is. For instance: interval_1 = [1; 10] interval_2 = [11; 58] I was looking for a more elegant solution than a large if/elif/else condition, for instance my idea was to load an excel worksheet containing n couples of numbers corresponding to the interval extremities, and use a function that finds me for in which interval my number is. Does a similar

问题 I've got a ts with the following properties: summary(Y$Date) Min. 1st Qu. Median Mean 3rd Qu. Max. "2001-01-01 05:30:00" "2004-03-15 10:40:30" "2007-01-03 04:00:00" "2006-11-11 15:53:11" "2009-08-13 12:00:00" "2011-12-30 12:30:00" str(Y$Date) POSIXlt[1:174110], format: "2001-01-01 12:00:00" "2001-01-01 05:30:00" "2001-01-02 01:30:00" "2001-01-02 02:00:00" "2001-01-02 02:00:00" "2001-01-02 02:01:00" "2001-01-02 04:00:00" "2001-01-02 04:00:00" ... length(Y$Date) [1] 174110 Y$Date[1:5] [1] "2001

问题 There are bird observations from various observation points ( obs ) over certain areas ( name ). The start and end time was taken, and the time difference ( diff_corr ) recalculated with a correction factor, so it is not simply difftime of the start-end-interval. I now need to "split" these values to "nice" intervals (15 minutes, e.g. 10:15:00, 10:30:00, ...) and then aggregate area-wise( name ) in order be able to make a plot of the presence of birds on those areas in those clean 15-minute

问题 NOTE: I edited the question! I am having trouble with iteration in Python, especially when I would like to sum up values up to a certain number. Here's more information on the problem I'm facing: I have a list of tuples that looks like this: [(1, 0.5, 'min'), (2, 3, 'NA'), (3, 6, 'NA'), (4, 40, 'NA'), (5, 90, 'NA'), (6, 130.8, 'max'), (7, 129, 'NA'), (8, 111, 'NA'), (9, 8, 'NA'), (10, 9, 'NA'), (11, 0.01, 'min'), (12, 9, 'NA'), (13, 40, 'NA'), (14, 90, 'NA'), (15, 130.1, 'max'), (16, 112, 'NA

问题 Why doesn't interval comparison bomb in JavaScript? if(-1 < x < 1) { console.log('x: ', x) } Why are we allowed to do this without getting errors? Also it seems that: -1 < x < 1 is true for x<=-1 1 < x < 1 is true for x<=1 -1 < x < -1 is always false -2 < x < 2 is always true In the last 2 cases it seems it is just comparing the 2 ends of the expressions. How are those expressions evalued? 回答1: Because JavaScript allows implicit type coercion, in this case from boolean to number. The -1 < x

问题 I’ve got drawings of planets that revolve around the sun. They rotate fine, but they need to be positioned accurately. They move at the same speed so it doesn’t look realistic. I would like to know how to make some planets swing a lot faster than others but they’re all in the same animation function and trying to make several animation functions just causes errors. Here's my relevant code: function rotate_point(pointX, pointY, originX, originY, ang) { ang = Math.PI / 180.0; return { x: Math

问题 Test code: s = pd.Series(pd.array([pd.Interval(0,1.2), pd.Interval(5,123)])) s.dtype s.dtype.kind is None >>> interval[float64] >>> True Is it some bug or made intentionally? If latter - for what reason? 回答1: The reason this is appearing as None is simply because the implementation of IntervalDtype explicitly sets kind = None. This should probably be updated to 'O' , though some care is needed here as it will result in unintended side effects, e.g. this would cause is_string_dtype to return

问题 What is the best approach to query a list of date intervals for overlapping intervals, given granularity to the second (or even millisecond)? From the exhaustive list of other questions regarding overlapping integer intervals, I was pointed to the Interval Tree. After reading it, I modified this implementation, which handles integer intervals, for dates. His search implementation loops from the starting search interval to the ending search interval, recursively appending from the left node or

问题 I am playing with the gyro on iPhone 4, although I am setting the gyro update rate to 100Hz motionManager.gyroUpdateInterval = 0.01; Despite that I seem to be getting the updates only with 50Hz. Does anyone have experience with that and can either confirm that number or maybe tell me what the official update frequency is? Cheers Esden 回答1: The ST chipsets used in iPhone are capable of 1KHz for Accel and 800Hz for Gyro, in theory you may be able to get that.. 回答2: Since iOS 4.2 you can run the

问题 Interval interval = new Interval(new DateTime("2014-01-01"), new DateTime("2014-01-30")); Is there a way to get the weekend days numbers? something like: interval.toPeriod.getWeekendDays(); 回答1: Custom Iterator WeekendDayIterator is an Iterator of the weekend days in the Interval specified: class WeekendDayIterator(interval: Interval) extends Iterator[LocalDate] { var day = interval.getStart.toLocalDate private def peek = day.plusDays(1) def hasNext: Boolean = peek.isBefore(interval.getEnd