int32

System.Console.WriteLine(int.MaxValue); This line gives me the answer of 2,147,483,647 as I have a 32-bit PC. Will the answer be same on a 64-bit PC? Unknown Yes. int.MaxValue: 2,147,483,647 Source: https://www.dotnetperls.com/int-maxvalue Daniel LeCheminant Yes, the answer will be the same on a 64-bit machine. In .NET, an int is a signed 32-bit integer , regardless of the processor. Its .NET framework type is System.Int32 . The C# Language specification states: The int type represents signed 32-bit integers with values between –2,147,483,648 and 2,147,483,647 . int is just an alias for Int32

In VB.NET, is there any difference between Integer and Int32 ? If yes, please explain. JaredPar Functionally, there is no difference between the types Integer and System.Int32 . In VB.NET Integer is just an alias for the System.Int32 type. The identifiers Int32 and Integer are not completely equal though. Integer is always an alias for System.Int32 and is understood by the compiler. Int32 though is not special cased in the compiler and goes through normal name resolution like any other type. So it's possible for Int32 to bind to a different type in certain cases. This is very rare though; no

I saw in MSDN documents that the maximum value of Int32 is 2,147,483,647 , hexadecimal 0x7FFFFFFF . I think, if it's Int32 it should store 32-bit integer values that finally should be 4,294,967,295 and hexadecimal 0xFFFFFFFF . My question is why Int32 stores 31-bit integer values? It's because it's a signed integer. An unsigned 32-bit integer give you the value you expect. Check out this MSDN page - http://msdn.microsoft.com/en-us/library/exx3b86w(v=vs.80).aspx For a more in depth explanation on why this is check out the link in Jackson Popes answer related to Two's Complement number

I have following code int varOut; int.TryParse(txt1.Text, out varOut); // Here txt1.Text = 4286656181793660 Here txt1.Text is the random 16 digit number generated by JavaScript which is an integer. But the above code always return false i.e. varOut value is always zero. What I am doing wrong here ? The limit for int ( 32-bit integer) is -2,147,483,648 to 2,147,483,647 . Your number is too large. For large integer number such as your case, try to Parse using long.TryParse (or Int64.TryParse since Int64 is long in C#) instead. The limit for long number is of the range of -9.2e18 to 9.2e18 * long

Looking at the msdn documentation for Convert.ToInt32() it states: If value is halfway between two whole numbers, the even number is returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6. http://msdn.microsoft.com/en-us/library/ffdk7eyz.aspx Why is this? Surely it would be more logical to round to the nearest whole number, wouldn't it? If so, 4.5 would become 5, and 5.5 would become 6, which seems to be more intuitive. Adam Houldsworth The History section of the Wikipedia entry for Rounding has some statements about the role of "round to even" in computing. Interestingly, it

I am using Entity Framework, and I have a line of code that convert string field (id)to int and compare with a number students = students.Where(s => (Int32.Parse( s.id)>5555)); Whenever I try to run it I receive rhis error. "LINQ to Entities does not recognize the method 'Int32 Parse(System.String)' method, and this method cannot be translated into a store expression." I have tried seveal different things and nothing is working, so any help would be great. Firstly I would highly recommend against converting the column into an int, you lose the indexing on the column. You rather convert the int

I'm really stumped on this one. I'm coding in C# for Windows Phone 7.5; I am taking text from a text box, parsing it into an array, then converting each array element into an Int32 using Convert.ToInt32, then running the resulting Int32 values through a series of mathematical calculations, multiplying and adding the Int32 values to hardcoded numbers (all dependent upon what's selected in the UI). All is well until I take the resulting calculations and multiply them together: I'm getting a negative number from multiplying two positive numbers! This is the only time I am doing any calculations

I thought .net had some kind of easy conversion method to use for converting an int into a byte array? I did a quick search and all solutions are bit masking/shifting one byte at a time, like "the good ol days". Is there not a ToByteArray() method somewhere? byte[] bytes = BitConverter.GetBytes(i); although note also that you might want to check BitConverter.IsLittleEndian to see which way around that is going to appear! Note that if you are doing this repeatedly you might want to avoid all those short-lived array allocations by writing it yourself via either shift operations ( >> / << ), or

I have been playing around with SQL and databases in C# via SqlCeConnection . I have been using ExecuteReader to read results and BigInt values for record IDs which are read into Longs. Today I have been playing with SQL statements that use COUNT based statements ('SELECT COUNT(*) FROM X') and have been using ExecuteScalar to read these single valued results. However, I ran into an issue. I can't seem to store the values into a Long data type, which I have been using up to now. I can store them into Int64's. I have been using BigInt for record IDs to get the maximum potential number of records