instantiation

object instantiation in c++

ぃ、小莉子 提交于 2019-12-11 05:08:02
问题 In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object? I tried to point to a method of a class with two different objects, but I'd problems with pointer to member. Any idea? 回答1: In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object? No, member functions are not usually copied anywhere. A different implicit

Instantiate a helper class but not in view

被刻印的时光 ゝ 提交于 2019-12-11 04:42:50
问题 I need a way to instantiate a class thats supposed to help me with some querystring-building when it comes to my links in the view, and I cant use this methods that i require as static methods since that would cause the querystringbuilder to keep data during the whole life-time of the application (which would cause some serious problems) So my question to you guys is, Is it possible to some how be able to instantiate the class/object that i require but not in the actual view itself? SO to

Instantiate interface in JAVA?

北慕城南 提交于 2019-12-11 04:17:20
问题 I'm reading the docs on the UIBinder of GWT and the first code snippet made me confused: public class HelloWorld extends UIObject { // Could extend Widget instead interface MyUiBinder extends UiBinder<DivElement, HelloWorld> {} private static MyUiBinder uiBinder = GWT.create(MyUiBinder.class); @UiField SpanElement nameSpan; public HelloWorld() { // createAndBindUi initializes this.nameSpan setElement(uiBinder.createAndBindUi(this)); } } On the second line an interface is created locally which

Java: Passing an instance of “this” during instantiation [closed]

馋奶兔 提交于 2019-12-11 02:57:00
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 6 years ago . myClass1: public class myClass1 { public myClass2 myclass2; public void createsecondclass (String[] args) { myclass2 = new myClass2(this); myclass2.dosomething(); } myClass2: public class myClass2 { public myclass1; public myClass2(myClass1 myclass1) { this.myclass1 = myclass1; }

Accessing instantiated object from another class - c#

Deadly 提交于 2019-12-11 02:09:52
问题 I have a Player class , NPC class , BattleManager class , and Game class . Player class stores/gets/sets player stats such as health, stamina, level, experience. NPC is similar, but is for NPCs. Game class instantiates Player class and NPC class . Game glass has two GameStates, battle and non-battle. When the player is in battle, GameState goes to battle, when the battle finishes, it switches to non-battle. What I'm trying to do is have the BattleManager class manage battles between the NPC

How many instances and references are created for a Base-Sub Class?

五迷三道 提交于 2019-12-11 01:45:17
问题 In C# .NET, I have 2 concrete classes. Class A and B. Class B is a subclass of Class A. How many instances (objects on the heap) and references from the stack to the heap objects are created for each line of code: ClassB b = new ClassB(); ClassA a = new ClassB(); 回答1: Going with the analogy that the object is a balloon and the reference is a string that is tied to the baloon, in each of the following cases there would be one balolon and one string: ClassB b = new ClassB(); //one reference,

c++: instantiate object [duplicate]

与世无争的帅哥 提交于 2019-12-11 01:31:21
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: C++ Object Instantiation vs Assignment I am quite new to C++ and was wondering what is the difference(if any) between instantiating an object as int main () { vector< int > x(2); } or int main () { vector< int > x = vector< int > (2); } except for the fact that the latter takes longer to write. Thanks in advance! 回答1: The difference is largely grammatical: vector<int> x(2); is direct initialization . vector<int>

Inject anonymous classes with spring

爱⌒轻易说出口 提交于 2019-12-11 01:19:42
问题 I've read a lot about getting generic type at runtime and I've understood that to prevent full type erasure and get generic type without giving it to constructor I can use an anonymous class plus an utility method, i.e. interface Generic<T> { public Class<T> getGenericType(); } @Component class GenericImpl<T> extends AbstractGenericImpl<T> { } abstract class AbstractGenericImpl<T> implements Generic<T> { protected Class<T> klass; @SuppressWarnings("unchecked") public Class<T> getGenericType()

Is it possible to instantiate an object of one class in two different ways?

青春壹個敷衍的年華 提交于 2019-12-11 00:02:11
问题 Here is an example which creates a point as p=Point(x, y) . Assume that I have some array ppp=(x, y) where x and y are numbers and I want to make it of class Point but in the way: p=Point(ppp) . I can do either one or another way but not both simultaneously. Is it possible to have both ways? 回答1: If you know that you have a tuple/list while creating the instance, you can do: p = Point(*ppp) , where ppp is the tuple. 回答2: There are two different ways to acquire the result, the first is to

If .Create() can't instantiate, should it return empty object, null, or throw an exception?

拜拜、爱过 提交于 2019-12-10 19:46:21
问题 I want to be able to instantiate any object in my application with this kind of code: SmartForm smartForm = SmartForm.Create("id = 23"); Customer customer = Customer.Create("id = 222"); I'm now debating what Create() should return if that object does not exist. if Create() returns an empty object , then this is kind of a "null pattern" and I can still pass that object around my application and call methods on it, which makes programming with this model convenient and easy if Create() returns