问题
In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object?
I tried to point to a method of a class with two different objects, but I'd problems with pointer to member.
Any idea?
回答1:
In C++ is it true that if you instantiate an object of a class, that for every object all of methods of the class are copied for the new object?
No, member functions are not usually copied anywhere. A different implicit parameter this is instead passed to any non-static member function, for each object of that class-type.
回答2:
No, that is absolutely not true.
Class instances (objects) contain data members. Function members look like they're "in" the class, but that's only for scoping and such: your function code doesn't "exist" inside the type, and it certainly doesn't exist inside the object†.
† I think it could, theoretically, in that the standard doesn't outright forbid it. But honestly, no. Just no.
回答3:
The code for a class exists only once.
For getting a pointer to a member function (probably what you meant by method), take a look at std::function, and for attaching the function call to different objects, take a look at std::bind.
来源：https://stackoverflow.com/questions/21316374/object-instantiation-in-c