inner-join

Left JOIN faster or Inner Join faster?

元气小坏坏 提交于 2019-11-29 18:00:41
问题 So... which one is faster (NULl value is not an issue), and are indexed. SELECT * FROM A JOIN B b ON b.id = a.id JOIN C c ON c.id = b.id WHERE A.id = '12345' Using Left Joins: SELECT * FROM A LEFT JOIN B ON B.id=A.bid LEFT JOIN C ON C.id=B.cid WHERE A.id = '12345' Here is the actual query Here it is.. both return the same result Query (0.2693sec) : EXPLAIN EXTENDED SELECT * FROM friend_events, zcms_users, user_events, EVENTS WHERE friend_events.userid = '13006' AND friend_events.state =0 AND

Multiple INNER JOIN from the same table

我怕爱的太早我们不能终老 提交于 2019-11-29 17:08:14
问题 I have a table of metals MetalID integer MetalName text MetalCode text Item table ItemID integer ItemName text ... Metal1 int Ref.-> metals.metalID Metal2 int Ref.-> metals.metalID Metal3 int Ref.-> metals.metalID I am trying to select three MetalCodes SELECT m.MetalCode as 'Metal1', m.MetalCode as 'Metal2',m.MetalCode as 'Metal3' FROM Item as k INNER JOIN Metals AS m ON m.metalID=k.metal1 INNER JOIN Metals AS m ON m.metalID=k.metal2 INNER JOIN Metals AS m ON m.metalID=k.metal3 WHERE k.ItemID

join two json files based on common key with jq utility or alternative way from command line

时间秒杀一切 提交于 2019-11-29 15:18:32
I have 2 json files with common key and I need to JOIN them with jq utility or alternative way from command line As follows: (for example: jq -join -key "id" jsonFile1 jsonFile2) jsonFile1: {"id":"10","data":"abc"} {"id":"20","data":"xyz"} {"id":"30","data":"qwe"} {"id":"40","data":"wsx"} {"id":"50","data":"zxc"} jsonFile2: {"id":"60","content":"ert"} {"id":"40","content":"tgb"} {"id":"10","content":"yui"} {"id":"30","content":"ujm"} {"id":"70","content":"rfv"} output: {"id":"10","data":"abc","content":"yui"} {"id":"30","data":"qwe","content":"ujm"} {"id":"40","data":"wsx","content":"tgb"}

Get first/last n records per group by

孤者浪人 提交于 2019-11-29 14:38:25
问题 I have two tables : tableA (idA, titleA) and tableB (idB, idA, textB) with a one to many relationship between them. For each row in tableA, I want to retrieve the last 5 rows corresponding in tableB (ordered by idB). I've tried SELECT * FROM tableA INNER JOIN tableB ON tableA.idA = tableB.idA LIMIT 5 but it's just limiting the global result of INNER JOIN whereas I want to limit the result for each different tableA.id How can I do that ? Thanks 回答1: I think this is what you need: SELECT tableA

Inner Joining the same table multiple times

[亡魂溺海] 提交于 2019-11-29 14:11:21
So I have received this error: #1066 - Not unique table/alias: 'Purchase' I am trying to do the following: SELECT Blank.BlankTypeCode ,Blank.BlankCode ,Payment.Amount ,Payment.Type ,Purchase.PurchaseDate ,Payment.DatePaid FROM Blank INNER JOIN Ticket ON Blank.BlankCode = Ticket.Blank_BlankCode INNER JOIN MCO_Blank ON Blank.BlankCode = MCO_Blank.Blank_BlankCode INNER JOIN Purchase ON Ticket.PurchaseID = Purchase.PurchaseID INNER JOIN Purchase ON MCO_Blank.PurchaseID = Purchase.PurchaseID INNER JOIN Payment ON Ticket.PurchaseID = Payment.PurchaseID INNER JOIN Payment ON MCO_Blank.PurchaseID =

The multi-part identifier could not be bound

随声附和 提交于 2019-11-29 11:52:23
trying this select tblPersonalInfo.companyname, tblJobBudget.title,tblJobBudget.lastmodifiedby, tblJobAdv.advtitle, tblJobAdv.userId, tblApplication.advid, tblApplication.position from tblJobAdv inner join tblApplication ON tblJobAdv.advid = tblApplication.advid inner join tblPersonalInfo On tblJobBudget.lastmodifiedby = tblPersonalInfo.userid gives error Msg 4104, Level 16, State 1, Line 8 The multi-part identifier "tblJobBudget.lastmodifiedby" could not be bound. Msg 4104, Level 16, State 1, Line 2 The multi-part identifier "tblJobBudget.title" could not be bound. Msg 4104, Level 16, State 1

SQL Server 2005 - Order of Inner Joins

痞子三分冷 提交于 2019-11-29 10:58:28
I have a query containing three inner join statements in the Where clause. The query takes roughly 2 minutes to execute. If I simply change the order of two of the inner joins, performance drops to 40 seconds. How can doing nothing but changing the order of the inner joins have such a drastic impact of query performance? I would have thought the optimizer would figure all this out. SQL is declarative, that is, the JOIN order should not matter. However it can in practice, say, if it's a complex query when the optimiser does not explore all options (which in theory could take months). Another

SQL Server - INNER JOIN WITH DISTINCT

让人想犯罪 __ 提交于 2019-11-29 09:17:28
I am having a hard time doing the following: select a.FirstName, a.LastName, v.District from AddTbl a order by Firstname inner join (select distinct LastName from ValTbl v where a.LastName = v.LastName) I want to do a join on ValTbl but only for distinct values. Try this: select distinct a.FirstName, a.LastName, v.District from AddTbl a inner join ValTbl v on a.LastName = v.LastName order by a.FirstName; Or this (it does the same, but the syntax is different): select distinct a.FirstName, a.LastName, v.District from AddTbl a, ValTbl v where a.LastName = v.LastName order by a.FirstName; Nate ,

INNER or LEFT Joining Multiple Table Records Into A Single Row

混江龙づ霸主 提交于 2019-11-29 08:58:42
Phone Table +----------------+-------------+ | Field | Type | +----------------+-------------+ | f_id | int(15) | | f_client_id | int(11) | | f_phone_type | varchar(50) | | f_phone_number | varchar(13) | +----------------+-------------+ Clients Table +-----------------------------+--------------+------+-----+ | Field | Type | Null | Key | +-----------------------------+--------------+------+-----+ | f_id | int(15) | NO | PRI | | f_first_name | varchar(13) | YES | MUL | | f_mi | char(1) | YES | | | f_last_name | varchar(20) | NO | MUL | +-----------------------------+--------------+------+-----

How can I perform an inner join with two object arrays in JavaScript?

自古美人都是妖i 提交于 2019-11-29 07:40:17
I have two object arrays: var a = [ {id: 4, name: 'Greg'}, {id: 1, name: 'David'}, {id: 2, name: 'John'}, {id: 3, name: 'Matt'}, ] var b = [ {id: 5, name: 'Mathew', position: '1'}, {id: 6, name: 'Gracia', position: '2'}, {id: 2, name: 'John', position: '2'}, {id: 3, name: 'Matt', position: '2'}, ] I want to do an inner join for these two arrays a and b , and create a third array like this (if the position property is not present, then it becomes null): var result = [{ {id: 4, name: 'Greg', position: null}, {id: 1, name: 'David', position: null}, {id: 5, name: 'Mathew', position: '1'}, {id: 6,