increment

问题 I have a class Transaction which has a var amount of type Int . I want to access it from another class, where I have an array of Transactions and sum all of their amounts. So I have this piece of code func computeTotal()-> Int{ let total = 0 for transaction in transactions{ //get the amounts of each and sum all of them up total += transaction.amount } return total } But it gives me an error Cannot invoke "+=" with an argument list of type (Int, @value Int) What can cause that? I know that in

问题 So I need to get a function that generates a list of letters that increase from a, and end in zzz. Should look like this: a b c ... aa ab ac ... zzx zzy zzz The code I currently have is this: for combo in product(ascii_lowercase, repeat=3): print(''.join(combo)) However, this does only increase with 3 letters, and the output is more like a ab abc abcd ... So, to recap: Function that letters increase, and when it goes past z, it returns to aa. Thanks! UPDATE: I am having the same output as

问题 I have a table called 'Workspaces' where the columns 'AreaID' and 'SurfaceID' work as a composite primary key. The AreaID references to another table called 'Areas' which only has AreaID as the primary key. What I want to do now is to make the surfaceID recound from 1 on every new AreaID. Right now I'm using the following code for the tables 'Areas' and 'Workspaces': --Table 'Areas' CREATE TABLE Areas ( AreaID INT IDENTITY(1,1) PRIMARY KEY, Areaname VARCHAR(60) UNIQUE NOT NULL ) --Table

问题 This question already has answers here : Is short-circuiting logical operators mandated? And evaluation order? (7 answers) Closed 2 years ago . I have a question concerning pre and post increments with logical operators if I have this code void main() {int i = - 3 , j = 2 , k = 0 , m ; m=++i||++j&&++k; printf("%d %d %d %d",i,j,k,m);} knowing that the increment and the decrement operators have higher precedence than && and || So they'll be executed first Then the && is higher than means -2||3&

问题 I'm trying to increment a number inside an element on page. But I need the number to include a comma for the thousandth place value. (e.g. 45,000 not 45000) <script> // Animate the element's value from x to y: $({someValue: 40000}).animate({someValue: 45000}, { duration: 3000, easing:'swing', // can be anything step: function() { // called on every step // Update the element's text with rounded-up value: $('#el').text(Math.round(this.someValue)); } }); </script> <div id="el"></div> How can I

问题 #include <stdio.h> int main() { int x = 4, y, z; y = --x; z = x--; printf("%d %d %d", x, y, z); } Output: 2 3 3 Can anyone explain this? And what does i =+ j mean (suppose i = 1 and j = 2 )? 回答1: simple explanation: --x or ++x : Value will be modified after. x-- or x++ : Value will be modified before Detailed explanation: --x or ++x : pre-decrement/increment: will first do the operation of decrementing or incrementing first, then it will assign x. x-- or x++ : post:decrement/increment : will

问题 #include<stdio.h> int main() { void add(); int i=2; add(i++,--i); print("%d",i) } void add(int a,int b) { print("%d %d",a,b); } /*what are a and b's value i am actually not getting the answer why b is 2 */ 回答1: in line 6 where add() is called first args is i++ so it will send value 2 ie value of i to the function and then add 1 now i=3. second args is --i now it will subtract 1 and iwill now be 2 again and then send value 2 to function So I think your answer will print 2 2 (that is value of a

问题 #include<stdio.h> int main() { void add(); int i=2; add(i++,--i); print("%d",i) } void add(int a,int b) { print("%d %d",a,b); } /*what are a and b's value i am actually not getting the answer why b is 2 */ 回答1: in line 6 where add() is called first args is i++ so it will send value 2 ie value of i to the function and then add 1 now i=3. second args is --i now it will subtract 1 and iwill now be 2 again and then send value 2 to function So I think your answer will print 2 2 (that is value of a

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 7 days ago . I am familiar with python codes and now trying to learn writing short and effective codes. here i am trying to increment inside a for loop but I am not sure if iam doing right. k = 0 if limit == "4 days": day = DATA[k][:9] + ", "" High/Low:" + DATA[k][10:] + ",  " + STATUS[k] + "  " + "<br/><br/>"

问题 I'm creating an "animated letter incrementer" that takes any given word and increments each letter of that word starting from A. Example: Word = Dog D - Increments from A to D [A, B, C, D] O - Increments from A to O [A, B, C, D, E, F, G, H, I, J, K, L, M, N, O] G - Increments from A to G [A, B, C, D, E, F, G] The effect I'd like to achieve is similar to this jQuery animated number counter, except I'll be incrementing letters instead of counting numbers. Also, each letter of the word should