increment counter in for loop python [closed]

问题

I am familiar with python codes and now trying to learn writing short and effective codes. here i am trying to increment inside a for loop but I am not sure if iam doing right.

k = 0
if limit == "4 days":
    day = DATA[k][:9] + ",&nbsp;""&nbsp;High/Low:" + DATA[k][10:] + ",&nbsp;&nbsp;" + STATUS[k] + "&nbsp;&nbsp;" + "<br/><br/>"
    for i in range(k):
        if k == 3:
            break
        k += 1
        return day

it should print day when k is equal to 0, 1, 2 and 3 -> so, 4 lines the output should be!

回答1:

k is 0 so you won't have anything to loop over, and even if it did, your for loop doesn't do anything, instead since you've specified a limit, just set that limit to what you're range is supposed to use

for i in range(k):
    day = DATA[i][:9] + ",&nbsp;""&nbsp;High/Low:" + DATA[i][10:] + ",&nbsp;&nbsp;" + STATUS[i] + "&nbsp;&nbsp;" + "<br/><br/>"

Having said that, you only return the first iteration of the for loop too, so just skip the loop

return DATA[0][:9] + ",&nbsp;""&nbsp;High/Low:" + DATA[0][10:] + ",&nbsp;&nbsp;" + STATUS[0] + "&nbsp;&nbsp;" + "<br/><br/>"

return f"{DATA[0][:9]},&nbsp;""&nbsp;High/Low:{DATA[0][10:]},&nbsp;&nbsp;{STATUS[0]}&nbsp;&nbsp;<br/><br/>"

To get your desired output, you need to not use return inside the for loop, add your items to a collection of some sort and then print those as required

def get_days():
   for i in range(k):
       yield DATA[i][:9] + ",&nbsp;""&nbsp;High/Low:" + DATA[i][10:] + ",&nbsp;&nbsp;" + STATUS[i] + "&nbsp;&nbsp;" + "<br/><br/>"

print(*get_days())

来源：https://stackoverflow.com/questions/59377649/increment-counter-in-for-loop-python

标签

python

loops

for-loop

increment