if-statement

问题 This question already has answers here : How to test multiple variables against a value? (24 answers) Closed 2 years ago . I'm trying to create a small python program to emulate rolling a single die. My problem arises in that I want the program to accept both upper and lower-case 'Y' to trigger a re-roll. My program works when I accept either upper or lower case y but when I try to change the line if usr == 'Y' to if usr == 'Y' or 'y' creates a problem where it never enters the else statement

问题 I have a dataframe listing 400 Products. Each of these Products belong to a certain category: BODY CLEANSING, HAIR, DEO, HAND BODY, FACE, MEN, LIP, SUN and FEMALE SHAVE. Furthermore I have the Sales Month, in which each of the 400 Products were launched. I want to create a new column in my dataframe displaying TRUE if the product was launched in high season and FALSE if not. The logic is something like this: If a product in the cateogry BODY CLEANSING or HAIR or DEO or HAND BODY or FACE or

问题 I have a dataframe listing 400 Products. Each of these Products belong to a certain category: BODY CLEANSING, HAIR, DEO, HAND BODY, FACE, MEN, LIP, SUN and FEMALE SHAVE. Furthermore I have the Sales Month, in which each of the 400 Products were launched. I want to create a new column in my dataframe displaying TRUE if the product was launched in high season and FALSE if not. The logic is something like this: If a product in the cateogry BODY CLEANSING or HAIR or DEO or HAND BODY or FACE or

问题 I have a dataframe listing 400 Products. Each of these Products belong to a certain category: BODY CLEANSING, HAIR, DEO, HAND BODY, FACE, MEN, LIP, SUN and FEMALE SHAVE. Furthermore I have the Sales Month, in which each of the 400 Products were launched. I want to create a new column in my dataframe displaying TRUE if the product was launched in high season and FALSE if not. The logic is something like this: If a product in the cateogry BODY CLEANSING or HAIR or DEO or HAND BODY or FACE or

问题 I have a question regarding function-calls using if-statements and recursion. I am a bit confused because python seems to jump into the if statements block even if my function returns "False" Here is an example: 1 def function_1(#param): 2 if function_2(#param): 3 #do something 4 if x<y: 5 function_1(#different parameters) 6 if x>y: 7 function_1(#different parameters) My function_2 returns "False" but python continues the code on line 5 for example. Can anyone explain this behavior? Thanks in

问题 function colorize(){ for(i = 1; i<=8; i++) { var id = document.getElementById('op' + i); var stat = id.innerHTML; document.write(stat + " "); if(stat == 1) { id.innerHTML = "<div style='background:#00FF00; width: 20px; height: 20px; border-radius: 15px;'></div>"; } else{ id.innerHTML = "<div style='background:#FF0000; width: 20px; height: 20px; border-radius: 15px;'></div>"; } } } It should check if there is a 1 or 0 and replace it with a green or red circle, but I only get red circles. "stat

问题 Here's the link for the flowchart: http://i1146.photobucket.com/albums/o530/HTHVampire/C%20plus%20plus/Capture_zps5a6c3acf.jpg Here's the code for the flowchart as shown, just ignore the ambiguous statement in the flowchart. #include <iostream> using namespace std; int main() { //declare and initialize a variable int a = 0; //prompt user for a value cout << "please enter a value" << endl; cin >> a; again1: //enter a decision block if(a > 10) { if(a < 10) { again2: if(a < 100) { a = a - 3;

问题 Simple Hide Row not functioning when given multiple options I've tried setting a Variable for the range and got same mismatch If Range("J178") = "Credit" Or "Debit" Or "Both" Then Rows("180").Hidden = False Else Rows("180").Hidden = True End If I expected the code to run or not; not the Run time 13 type mismatch I'm receiving. 回答1: Option 1 - Write out each condition longhand (case sensitive) If Range("J178") = "Credit" Or Range("J178") = "Debit" Or Range("J178") = "Both" Then Rows("180")

问题 Simple Hide Row not functioning when given multiple options I've tried setting a Variable for the range and got same mismatch If Range("J178") = "Credit" Or "Debit" Or "Both" Then Rows("180").Hidden = False Else Rows("180").Hidden = True End If I expected the code to run or not; not the Run time 13 type mismatch I'm receiving. 回答1: Option 1 - Write out each condition longhand (case sensitive) If Range("J178") = "Credit" Or Range("J178") = "Debit" Or Range("J178") = "Both" Then Rows("180")

问题 Why isn't my code reading the next condition in the if statement? MySqlCommand cmd = new MySqlCommand("Select * from admin where Username='" + txtuser.Text + "' and Password='" + txtpass.Text + "' ", con); dr = cmd.ExecuteReader(); if (dr.Read()) { if (txtuser.Text == dr["Username"].ToString() && txtpass.Text == dr["Password"].ToString()) { this.Hide(); Form f1 = new Form1(); f1.Show(); } else if (txtuser.Text != dr["Username"].ToString() && txtpass.Text == dr["Password"].ToString()) {