if-statement

问题 I need to know how to make an if - else if statement so that different messages will appear, based on the button (the answer) the user will press. 回答1: You can use the If , ElseIf and End If directives. If i = 10 Then response.write("Just started...!") ElseIf i = 11 Then response.write("Hungry!") End If 来源： https://stackoverflow.com/questions/21838570/if-else-if-statement-in-vbs-scripts

问题 I am currently new to Python and am trying to run a few simple lines of code. I cannot understand how Python is evaluating this syntax after the if statement. Any explanations will be appreciated. number = int(raw_input("Enter number : ")) if number == (1 or 2 or 3): print "Match" else: print "No match" Only the integer 1 yield a positive result and any other numbers including 2 and 3 go through the else branch. Can the conditions be stated as the following only?: if number == 1 or number ==

问题 While coding, i sometimes make the error of writing a single = instead of == in an if-statement. So lets say i have this: <?php $name = 'piet'; if($name == 'jan'){ print 'hello jan'; } ?> And i make a mistake and write this instead: <?php $name = 'piet'; if($name = 'jan'){ print 'hello jan'; } ?> This won't throw an error of course, since it is valid php code. However, i never use this short-hand notation, so if i enter it by mistake it will break the logic of my code without telling me why.

问题 This question already has answers here : Asking the user for input until they give a valid response (19 answers) How to let a raw_input repeat until I want to quit? (4 answers) Closed 4 years ago . I am attempting to make my program repeat when the user inputs y/n, however I am confused on how to use a while true with this type of input, below is some code. again = input("Would you like to play again? enter y/n: ") if again == "n": print ("Thanks for Playing!") quit if again == "y": print (

问题 I'd like to learn how to conditionally replace values in R data frame using if/then statements. Suppose I have a data frame like this one: df <- data.frame( customer_id = c(568468,568468,568468,485342,847295,847295), customer = c('paramount','paramount','paramount','miramax','pixar','pixar')); I'd like to do something along the lines of, "if customer in ('paramount','pixar') make customer_id 99. Else do nothing". I'm using this code, but it's not working: if(df$customer %in% c('paramount',

问题 I'm not really familiar with TCSH I would like run a command2 if a command1 was entered in the shell, something like this: if command1 then echo "Command succeeded" command2 else echo "Command failed" fi I tried this code but it doesn't work. Step two would be to read and print in a file a part some variable that command1 changed (making a kind of history only for some variables). 回答1: You can use $? to get exit code from last command. #!/bin/tcsh # command below can fail or succeed command1

问题 Hello People here is my jquery code. $(val1+","+val2).mouseleave(function(){ $('.opacity').remove(); $(val3).show(); $(val4).hide(); }); i want to edit this code in such a way that after $(val1+","+val2).mouseleave(function(){ if mouse doe not enter val3 or val4 then $('.opacity').remove(); $(val3).show(); $(val4).hide(); else nothing.... something like ... $(val1 + "," + val2).mouseleave(function() { if ($(val3 + "," + val4).mouseenter) { } else { $('.opacity').remove(); $(val3).show(); $

问题 The following command gives me a list of matching expressions: grep -f /tmp/list Filename* > /tmp/output The list file is then parsed and used to search Filename* for the parsed string. The results are then saved to output . How would I output the parsed string from list in the case where there is no match in Filename*? Contents of the list file could be: ABC BLA ZZZ HJK Example Files: Filename1:5,ABC,123 Filename2:5,ZZZ,342 Result of Running Command: BLA HJK Stack overflow question 2480584

问题 An example would be: If filter_purchase = 0 Or "" Then SetDocVar "filter_purchase", "0" Else SetDocVar "filter_purchase", CStr(filter_purchase) End If But I get a 'Type Mismatch'. Would there be an easier way than doing Else IFs? 回答1: you have to explicitly state the condition for each OR. Please see below If filter_purchase = 0 Or filter_purchase = "" Then SetDocVar "filter_purchase", "0" Else SetDocVar "filter_purchase", CStr(filter_purchase) End If 回答2: This should be the condition you

问题 I need to URLs with three specific specific substrings out of a loop. The following code worked, but I am sure there's a more elegant way to do it: for node in soup.findAll('loc'): url = node.text.encode("utf-8") if "/store/" not in url and "/cell-phones/" not in url and "/accessories/" not in url: objlist.loc.append(url) else: continue Thank you! 回答1: url = node.text.encode("utf-8") sub_strings = ['/store','/cell-phones/','accessories'] if not any(x in url for x in sub_strings): objlist.loc