if-statement

keras (tensorflow backend) conditional assignment with K.switch()

断了今生、忘了曾经 提交于 2021-01-01 13:34:30
问题 I'm trying to implement something like if np.max(subgrid) == np.min(subgrid): middle_middle = cur_subgrid + 1 else: middle_middle = cur_subgrid Since the condition can only be determined at run-time, I'm using Keras syntax as following middle_middle = K.switch(K.max(subgrid) == K.min(subgrid), lambda: tf.add(cur_subgrid,1), lambda: cur_subgrid) But I'm getting this error: <ipython-input-112-0504ce070e71> in col_loop(j, gray_map, mask_A) 56 57 ---> 58 middle_middle = K.switch(K.max(subgrid) ==

Optional vs if/else-if performance java 8

℡╲_俬逩灬. 提交于 2020-12-29 09:31:42
问题 Hello i have two samples of code if/else if/else statements private Object getObj(message) { if (message.getA() != null) return message.getA(); else if (message.getB() != null) return message.getB(); else if (message.getC() != null) return message.getC(); else return null; } Optional statements private Optional<Object> wrap(Object o){ return Optional.ofNullable(o); } private Object getObj(message) { return wrap(message.getA()) .orElseGet(() -> wrap(message.getB()) .orElseGet(() -> wrap

How do I write a function in r to do cacluations on a record?

跟風遠走 提交于 2020-12-26 10:58:05
问题 In C# I am used to the concept of a data set and a current record. It would be easy for me to write a complicated calc-price function with conditions on the current record. I am having trouble understanding how to do this in r. I tried the following train <- read.csv("Train.csv" ) df <- as.data.frame.matrix(train) v = c( df$Fuel.Type ,df$No.Gears) names(v ) <- c( "FuelType" ,"NoGears") df$FEType = FEType( v) Where the my function is defined as FEType <- function(v ){ ret="Low" if (v["FuelType

Is using if (0) to skip a case in a switch supposed to work?

你离开我真会死。 提交于 2020-12-24 02:43:15
问题 I have a situation where I would like for two cases in a C++ switch statement to both fall through to a third case. Specifically, the second case would fall through to the third case, and the first case would also fall through to the third case without passing through the second case. I had a dumb idea, tried it, and it worked! I wrapped the second case in an if (0) { ... } . It looks like this: #ifdef __cplusplus # include <cstdio> #else # include <stdio.h> #endif int main(void) { for (int i

how to check for multiple images != nil

夙愿已清 提交于 2020-12-15 06:38:25
问题 I am trying to check if multiple UIImageView != nil using if statement and && operator but the problem is that when the user pick any photo of the 3 driverPImg.image != nil && passImg.image != nil && carImg.image != nil the next code exuted and it will not check for the rest conditions this image shows 3 images line up Horizontally all those images should be filled or not nil before the Btn change color to red but what it suppose to happen didn't happen extension VC:

The generate if condition must be a constant expression

走远了吗. 提交于 2020-12-15 04:56:52
问题 I am trying to create an Immediate Generator for RISC-V assembly but I have encountered with if statement. Here is my code in Verilog: module signextend(in, out, sel); parameter nin = 32; parameter nout = 32; input [nin-1:nin-25] in; input [2:0] sel; output [nout-1:0] out; if (sel == 3'b000) begin assign out[19:0] = in[31:12]; assign out[31:20] = {12{in[31]}}; end else if (sel == 3'b001) begin assign out[11:0] = in[31:20]; assign out[31:12] = {20{in[31]}}; end else if (sel == 3'b010) begin

Coin Change Algorithm JS

≡放荡痞女 提交于 2020-12-15 04:56:13
问题 I have been trying to come up with a solution for this algorithm for 3-4 days but nothing seems to work and the available solutions are a bit more advanced for me. It has to be solved with conditionals only so no recursion or dynamic programming. I need to determine the least amount of coins necessary to give change given the following denominations: 1, 0.5, 0.2, 0.1, 0.05, 0.02 and 0.01. Input is the following: Price of an item Sum paid by customer Current ideas: let price = +gets(); let

Interpreting “condition has length > 1” warning from `if` function

夙愿已清 提交于 2020-12-15 01:41:30
问题 I have an array: a <- c(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) and would like to implement the following function: w<-function(a){ if (a>0){ a/sum(a) } else 1 } This function would like to check whether there is any value

Conditional statement combining case_when and mutate

允我心安 提交于 2020-12-13 04:23:06
问题 I want create a bivariate map plotting two variables: production and possession . In order to give part of the data the correct colour I want to add a column with color codes "A", "B", "C" for one variable and for the other 1, 2, 3 . Then later concatinating the two. Just so that the data is coded like the following example: Here's my example df and failing code: library(dplyr) example_df <- structure(list(production = c(0.74, 1.34, 2.5), possession = c(5, 23.8, 124.89)), .Names = c(

PLSQL: using subquery in if-statement error PLS-00405

回眸只為那壹抹淺笑 提交于 2020-12-11 08:59:10
问题 I'm getting error pls-00405 when I try to run this code: BEGIN IF :P10_KAART_CODE IN (SELECT KAART_CODE FROM CADEAUKAART) THEN RETURN TRUE; ELSE RETURN FALSE; END IF; END; There are some similar questions about this but couldn't find a solution for this simple code. Is there another way of writing this without facing a error? 回答1: You may try a cursor, alternatively : DECLARE v_flag boolean := FALSE; BEGIN FOR c IN ( SELECT KAART_CODE FROM CADEAUKAART ) LOOP IF :P10_KAART_CODE = c.KAART_CODE