if-statement

Print Only When Condition is True in R

眉间皱痕 提交于 2021-01-05 04:46:24
问题 This solution Automate Seed as a Vector Instead of an Integer in R library(forecast) SEED_vector <- c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) arima_order_results = data.frame() for (my_seed in SEED_vector){ set.seed(my_seed) ar1 <- arima.sim(n = 10, model=list(ar=0.2, order = c(1, 0, 0)), sd = 1) ar2 <- auto.arima(ar1, ic ="aicc") arima_order = arimaorder(ar2) arima_order = t(as.data.frame(arima_order)) # Print the arima order. print(arima_order) # This line of code is just if you

Print Only When Condition is True in R

我只是一个虾纸丫 提交于 2021-01-05 04:44:13
问题 This solution Automate Seed as a Vector Instead of an Integer in R library(forecast) SEED_vector <- c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19) arima_order_results = data.frame() for (my_seed in SEED_vector){ set.seed(my_seed) ar1 <- arima.sim(n = 10, model=list(ar=0.2, order = c(1, 0, 0)), sd = 1) ar2 <- auto.arima(ar1, ic ="aicc") arima_order = arimaorder(ar2) arima_order = t(as.data.frame(arima_order)) # Print the arima order. print(arima_order) # This line of code is just if you

Don't understand this SyntaxError: illegal target for annotation

試著忘記壹切 提交于 2021-01-04 09:48:46
问题 I have some simple if... elif... in my python3.6 (& OpenCV 4.0), but no matter what I do I keep getting strange error messages. I need to crop some pics according to some bounding boxes. # the image to be cropped loads here: tobecropped= cv2.imread(img) images.append(tobecropped) (imageheight, imagewidth) = tobecropped.shape[:2] # sample bounding box: y = 833 # center vertically x = 183 # center horizontally width = 172 height = 103 # calculation of cropping values adding 10% extra: y1 = y-

VBA - Nested “With Statements” within “IF Statements”

[亡魂溺海] 提交于 2021-01-04 07:35:07
问题 Language: VBA - MS Access I am using User-Defined-Types (UDT) within my code. I would like to be able determine which section of the UDT i'm loading data into based on a state variable. My first attempt was to use "With" statements nested into an "IF" statement. This doesn't work (I get a compiler error that says Else without if). Is there a way to make this work? or another way of going about using a state variable to determine which section of the UDT i'm loading? Type MyOtherType Name as

How to break a loop by a shorthand “if-else” result?

回眸只為那壹抹淺笑 提交于 2021-01-03 07:01:53
问题 Suppose I have got a shorthand if-else statement inside a loop as in this case : for(...) { a = b == c ? b : c; // More unnecessary code if the result was true. } And I would like to break the loop by the result of the condition: for(...) { a = b == c ? b break : c; // Now the unnecessary code is not executed. } I realize I could just type it in a full way as in this example: for(...) { if( b == c ) { a = b; break; } else { a = c; } // Now the unnecessary code is not executed. } But it is too

How to break a loop by a shorthand “if-else” result?

瘦欲@ 提交于 2021-01-03 07:00:57
问题 Suppose I have got a shorthand if-else statement inside a loop as in this case : for(...) { a = b == c ? b : c; // More unnecessary code if the result was true. } And I would like to break the loop by the result of the condition: for(...) { a = b == c ? b break : c; // Now the unnecessary code is not executed. } I realize I could just type it in a full way as in this example: for(...) { if( b == c ) { a = b; break; } else { a = c; } // Now the unnecessary code is not executed. } But it is too

Compiler error `assigning incompatible type within if statement` [duplicate]

空扰寡人 提交于 2021-01-03 06:30:42
问题 This question already has answers here : using std::is_same, why my function still can't work for 2 types (4 answers) Closed 3 months ago . The compiler keeps assigning incompatible types during the build. error Message: error: assigning to 'int' from incompatible type 'QString' typeduserproperty.cpp:115:28: note: in instantiation of member function 'core::TypedUserProperty<int>::setValue' requested here Sample code /** * @brief setValue * set value to property * @param val * value to set to

Compiler error `assigning incompatible type within if statement` [duplicate]

牧云@^-^@ 提交于 2021-01-03 06:28:45
问题 This question already has answers here : using std::is_same, why my function still can't work for 2 types (4 answers) Closed 3 months ago . The compiler keeps assigning incompatible types during the build. error Message: error: assigning to 'int' from incompatible type 'QString' typeduserproperty.cpp:115:28: note: in instantiation of member function 'core::TypedUserProperty<int>::setValue' requested here Sample code /** * @brief setValue * set value to property * @param val * value to set to

Compiler error `assigning incompatible type within if statement` [duplicate]

江枫思渺然 提交于 2021-01-03 06:28:15
问题 This question already has answers here : using std::is_same, why my function still can't work for 2 types (4 answers) Closed 3 months ago . The compiler keeps assigning incompatible types during the build. error Message: error: assigning to 'int' from incompatible type 'QString' typeduserproperty.cpp:115:28: note: in instantiation of member function 'core::TypedUserProperty<int>::setValue' requested here Sample code /** * @brief setValue * set value to property * @param val * value to set to

keras (tensorflow backend) conditional assignment with K.switch()

╄→гoц情女王★ 提交于 2021-01-01 13:35:18
问题 I'm trying to implement something like if np.max(subgrid) == np.min(subgrid): middle_middle = cur_subgrid + 1 else: middle_middle = cur_subgrid Since the condition can only be determined at run-time, I'm using Keras syntax as following middle_middle = K.switch(K.max(subgrid) == K.min(subgrid), lambda: tf.add(cur_subgrid,1), lambda: cur_subgrid) But I'm getting this error: <ipython-input-112-0504ce070e71> in col_loop(j, gray_map, mask_A) 56 57 ---> 58 middle_middle = K.switch(K.max(subgrid) ==