hierarchy

How can I list all classes loaded in a specific class loader

由 情到浓时终转凉″ 提交于 2019-11-26 05:29:46
问题 For debug reasons, and curiosity, I wish to list all classes loaded to a specific class loader. Seeing as most methods of a class loader are protected, what is the best way to accomplish what I want? Thanks! 回答1: Instrumentation.getInitiatedClasses(ClassLoader) may do what you want. According to the docs: Returns an array of all classes for which loader is an initiating loader. I'm not sure what "initiating loader" means though. If that does not give the right result try using the

Make multiple dependent / cascading selectOneMenu dropdown lists in JSF

由 一世执手 提交于 2019-11-26 04:27:07
问题 I am trying to make 4 dependent menus. When the user chooses an item from the first menu, the second menu will show dependent data and when the user chooses item from the second one , the third one will show dependent data and so on. The user will see items on the first menu only and the other ones will be blank. If he chooses an item on the first menu the second one will show data but the third and the fourth will remain blank, and so on. The user must eventually choose entries from all the

How to view hierarchical package structure in Eclipse package explorer

由 蹲街弑〆低调 提交于 2019-11-26 03:00:16
问题 OK here\'s what I would like: in the Eclipse package explorer, I see the following: (dot represents a clickable arrow that I can use to expand the folder) PROJECT Source Folder Package Class Package.SubPackage Foo Bar Package.OtherSubPackage Package.OtherSubPackage.VerySubPackage OtherPackage Foobar OtherPackage.SubPackage Baz Long story short, I want to have many packages, each with many subpackages, in a source folder (and several source folders, so making more won\'t solve the problem)--so

JPA: How to have one-to-many relation of the same Entity type

由 冷暖自知 提交于 2019-11-26 02:16:37
问题 There\'s an Entity Class \"A\". Class A might have children of the same type \"A\". Also \"A\" should hold it\'s parent if it is a child. Is this possible? If so how should I map the relations in the Entity class? [\"A\" has an id column.] 回答1: Yes, this is possible. This is a special case of the standard bidirectional @ManyToOne / @OneToMany relationship. It is special because the entity on each end of the relationship is the same. The general case is detailed in Section 2.10.2 of the JPA 2

SQL - How to store and navigate hierarchies?

由 别等时光非礼了梦想. 提交于 2019-11-26 01:49:12
问题 What are the ways that you use to model and retrieve hierarchical info in a database? 回答1: The definitive pieces on this subject have been written by Joe Celko, and he has worked a number of them into a book called Joe Celko's Trees and Hierarchies in SQL for Smarties. He favours a technique called directed graphs. An introduction to his work on this subject can be found here 回答2: I like the Modified Preorder Tree Traversal Algorithm. This technique makes it very easy to query the tree. But

SQL - How to store and navigate hierarchies?

由 别说谁变了你拦得住时间么 提交于 2019-11-26 00:43:08
What are the ways that you use to model and retrieve hierarchical info in a database? andy47 The definitive pieces on this subject have been written by Joe Celko, and he has worked a number of them into a book called Joe Celko's Trees and Hierarchies in SQL for Smarties. He favours a technique called directed graphs. An introduction to his work on this subject can be found here markus I like the Modified Preorder Tree Traversal Algorithm. This technique makes it very easy to query the tree. But here is a list of links about the topic which I copied from the Zend Framework (PHP) contributors

Attempt to present UIViewController on UIViewController whose view is not in the window hierarchy

由 荒凉一梦 提交于 2019-11-25 21:56:01
问题 Just started using Xcode 4.5 and I got this error in the console: Warning: Attempt to present < finishViewController: 0x1e56e0a0 > on < ViewController: 0x1ec3e000> whose view is not in the window hierarchy! The view is still being presented and everything in the app is working fine. Is this something new in iOS 6? This is the code I\'m using to change between views: UIStoryboard *storyboard = self.storyboard; finishViewController *finished = [storyboard instantiateViewControllerWithIdentifier
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