Attempt to present UIViewController on UIViewController whose view is not in the window hierarchy

荒凉一梦 提交于 2019-11-25 21:56:01

问题


Just started using Xcode 4.5 and I got this error in the console:

Warning: Attempt to present < finishViewController: 0x1e56e0a0 > on < ViewController: 0x1ec3e000> whose view is not in the window hierarchy!

The view is still being presented and everything in the app is working fine. Is this something new in iOS 6?

This is the code I\'m using to change between views:

UIStoryboard *storyboard = self.storyboard;
finishViewController *finished = 
[storyboard instantiateViewControllerWithIdentifier:@\"finishViewController\"];

[self presentViewController:finished animated:NO completion:NULL];

回答1:


Where are you calling this method from? I had an issue where I was attempting to present a modal view controller within the viewDidLoad method. The solution for me was to move this call to the viewDidAppear: method.

My presumption is that the view controller's view is not in the window's view hierarchy at the point that it has been loaded (when the viewDidLoad message is sent), but it is in the window hierarchy after it has been presented (when the viewDidAppear: message is sent).


Caution

If you do make a call to presentViewController:animated:completion: in the viewDidAppear: you may run into an issue whereby the modal view controller is always being presented whenever the view controller's view appears (which makes sense!) and so the modal view controller being presented will never go away...

Maybe this isn't the best place to present the modal view controller, or perhaps some additional state needs to be kept which allows the presenting view controller to decide whether or not it should present the modal view controller immediately.




回答2:


Another potential cause:

I had this issue when I was accidentally presenting the same view controller twice. (Once with performSegueWithIdentifer:sender: which was called when the button was pressed, and a second time with a segue connected directly to the button).

Effectively, two segues were firing at the same time, and I got the error: Attempt to present X on Y whose view is not in the window hierarchy!




回答3:


viewWillLayoutSubviews and viewDidLayoutSubviews (iOS 5.0+) can be used for this purpose. They are called earlier than viewDidAppear.




回答4:


For Display any subview to main view,Please use following code

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController presentViewController:composeViewController animated:YES completion:nil];

For Dismiss any subview from main view,Please use following code

UIViewController *yourCurrentViewController = [UIApplication sharedApplication].keyWindow.rootViewController;

while (yourCurrentViewController.presentedViewController) 
{
   yourCurrentViewController = yourCurrentViewController.presentedViewController;
}

[yourCurrentViewController dismissViewControllerAnimated:YES completion:nil];



回答5:


I also encountered this problem when I tried to present a UIViewController in viewDidLoad. James Bedford's answer worked, but my app showed the background first for 1 or 2 seconds.

After some research, I've found a way to solve this using the addChildViewController.

- (void)viewDidLoad
{
    ...
    [self.view addSubview: navigationViewController.view];
    [self addChildViewController: navigationViewController];
    ...
}



回答6:


Probably, like me, you have a wrong root viewController

I want to display a ViewController in a non-UIViewController context,

So I can't use such code:

[self presentViewController:]

So, I get a UIViewController:

[[[[UIApplication sharedApplication] delegate] window] rootViewController]

For some reason (logical bug), the rootViewController is something other than expected (a normal UIViewController). Then I correct the bug, replacing rootViewController with a UINavigationController, and the problem is gone.




回答7:


TL;DR You can only have 1 rootViewController and its the most recently presented one. So don't try having a viewcontroller present another viewcontroller when it's already presented one that hasn't been dismissed.

After doing some of my own testing I've come to a conclusion.

If you have a rootViewController that you want to present everything then you can run into this problem.

Here is my rootController code (open is my shortcut for presenting a viewcontroller from the root).

func open(controller:UIViewController)
{
    if (Context.ROOTWINDOW.rootViewController == nil)
    {
        Context.ROOTWINDOW.rootViewController = ROOT_VIEW_CONTROLLER
        Context.ROOTWINDOW.makeKeyAndVisible()
    }

    ROOT_VIEW_CONTROLLER.presentViewController(controller, animated: true, completion: {})
}

If I call open twice in a row (regardless of time elapsed), this will work just fine on the first open, but NOT on the second open. The second open attempt will result in the error above.

However if I close the most recently presented view then call open, it works just fine when I call open again (on another viewcontroller).

func close(controller:UIViewController)
{
    ROOT_VIEW_CONTROLLER.dismissViewControllerAnimated(true, completion: nil)
}

What I have concluded is that the rootViewController of only the MOST-RECENT-CALL is on the view Hierarchy (even if you didn't dismiss it or remove a view). I tried playing with all the loader calls (viewDidLoad, viewDidAppear, and doing delayed dispatch calls) and I have found that the only way I could get it to work is ONLY calling present from the top most view controller.




回答8:


My issue was I was performing the segue in UIApplicationDelegate's didFinishLaunchingWithOptions method before I called makeKeyAndVisible() on the window.




回答9:


If you have AVPlayer object with played video you have to pause video first.




回答10:


I had the same issue. The problem was, the performSegueWithIdentifier was triggered by a notification, as soon as I put the notification on the main thread the warning message was gone.




回答11:


It's working fine try this.Link

UIViewController *top = [UIApplication sharedApplication].keyWindow.rootViewController;
[top presentViewController:secondView animated:YES completion: nil];



回答12:


I've ended up with such a code that finally works to me (Swift), considering you want to display some viewController from virtually anywhere. This code will obviously crash when there is no rootViewController available, that's the open ending. It also does not include usually required switch to UI thread using

dispatch_sync(dispatch_get_main_queue(), {
    guard !NSBundle.mainBundle().bundlePath.hasSuffix(".appex") else {
       return; // skip operation when embedded to App Extension
    }

    if let delegate = UIApplication.sharedApplication().delegate {
        delegate.window!!.rootViewController?.presentViewController(viewController, animated: true, completion: { () -> Void in
            // optional completion code
        })
    }
}



回答13:


This kind of warning can mean that You're trying to present new View Controller through Navigation Controller while this Navigation Controller is currently presenting another View Controller. To fix it You have to dismiss currently presented View Controller at first and on completion present the new one. Another cause of the warning can be trying to present View Controller on thread another than main.




回答14:


In my situation, I was not able to put mine in a class override. So, here is what I got:

let viewController = self // I had viewController passed in as a function,
                          // but otherwise you can do this


// Present the view controller
let currentViewController = UIApplication.shared.keyWindow?.rootViewController
currentViewController?.dismiss(animated: true, completion: nil)

if viewController.presentedViewController == nil {
    currentViewController?.present(alert, animated: true, completion: nil)
} else {
    viewController.present(alert, animated: true, completion: nil)
}



回答15:


I had the same problem. I had to embed a navigation controller and present the controller through it. Below is the sample code.

- (void)viewDidLoad
{
    [super viewDidLoad];
    // Do any additional setup after loading the view, typically from a nib.

    UIImagePickerController *cameraView = [[UIImagePickerController alloc]init];
    [cameraView setSourceType:UIImagePickerControllerSourceTypeCamera];
    [cameraView setShowsCameraControls:NO];

    UIView *cameraOverlay = [[UIView alloc]initWithFrame:CGRectMake(0, 0, 768, 1024)];
    UIImageView *imageView = [[UIImageView alloc]initWithImage:[UIImage imageNamed:@"someImage"]];
    [imageView setFrame:CGRectMake(0, 0, 768, 1024)];
    [cameraOverlay addSubview:imageView];

    [cameraView setCameraOverlayView:imageView];

    [self.navigationController presentViewController:cameraView animated:NO completion:nil];
//    [self presentViewController:cameraView animated:NO completion:nil]; //this will cause view is not in the window hierarchy error

}



回答16:


In case it helps anyone, my issue was extremely silly. Totally my fault of course. A notification was triggering a method that was calling the modal. But I wasn't removing the notification correctly, so at some point, I would have more than one notification, so the modal would get called multiple times. Of course, after you call the modal once, the viewcontroller that calls it it's not longer in the view hierarchy, that's why we see this issue. My situation caused a bunch of other issue too, as you would expect.

So to summarize, whatever you're doing make sure the modal is not being called more than once.




回答17:


I fixed it by moving the start() function inside the dismiss completion block:

self.tabBarController.dismiss(animated: false) {
  self.start()
}

Start contains two calls to self.present() one for a UINavigationController and another one for a UIImagePickerController.

That fixed it for me.




回答18:


You can also get this warning when performing a segue from a view controller that is embedded in a container. The correct solution is to use segue from the parent of container, not from container's view controller.




回答19:


Have to write below line.

self.searchController.definesPresentationContext = true

instead of

self.definesPresentationContext = true

in UIViewController




回答20:


With Swift 3...

Another possible cause to this, which happened to me, was having a segue from a tableViewCell to another ViewController on the Storyboard. I also used override func prepare(for segue: UIStoryboardSegue, sender: Any?) {} when the cell was clicked.

I fixed this issue by making a segue from ViewController to ViewController.




回答21:


I had this issue, and the root cause was subscribing to a button click handler (TouchUpInside) multiple times.

It was subscribing in ViewWillAppear, which was being called multiple times since we had added navigation to go to another controller, and then unwind back to it.




回答22:


It happened to me that the segue in the storyboard was some kind of broken. Deleting the segue (and creating the exact same segue again) solved the issue.




回答23:


With your main window, there will likely always be times with transitions that are incompatible with presenting an alert. In order to allow presenting alerts at any time in your application lifecycle, you should have a separate window to do the job.

/// independant window for alerts
@interface AlertWindow: UIWindow

+ (void)presentAlertWithTitle:(NSString *)title message:(NSString *)message;

@end

@implementation AlertWindow

+ (AlertWindow *)sharedInstance
{
    static AlertWindow *sharedInstance;
    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{
        sharedInstance = [[AlertWindow alloc] initWithFrame:UIScreen.mainScreen.bounds];
    });
    return sharedInstance;
}

+ (void)presentAlertWithTitle:(NSString *)title message:(NSString *)message
{
    // Using a separate window to solve "Warning: Attempt to present <UIAlertController> on <UIViewController> whose view is not in the window hierarchy!"
    UIWindow *shared = AlertWindow.sharedInstance;
    shared.userInteractionEnabled = YES;
    UIViewController *root = shared.rootViewController;
    UIAlertController *alert = [UIAlertController alertControllerWithTitle:title message:message preferredStyle:UIAlertControllerStyleAlert];
    alert.modalInPopover = true;
    [alert addAction:[UIAlertAction actionWithTitle:@"OK" style:UIAlertActionStyleCancel handler:^(UIAlertAction *action) {
        shared.userInteractionEnabled = NO;
        [root dismissViewControllerAnimated:YES completion:nil];
    }]];
    [root presentViewController:alert animated:YES completion:nil];
}

- (instancetype)initWithFrame:(CGRect)frame
{
    self = [super initWithFrame:frame];

    self.userInteractionEnabled = NO;
    self.windowLevel = CGFLOAT_MAX;
    self.backgroundColor = UIColor.clearColor;
    self.hidden = NO;
    self.rootViewController = UIViewController.new;

    [NSNotificationCenter.defaultCenter addObserver:self
                                           selector:@selector(bringWindowToTop:)
                                               name:UIWindowDidBecomeVisibleNotification
                                             object:nil];

    return self;
}

/// Bring AlertWindow to top when another window is being shown.
- (void)bringWindowToTop:(NSNotification *)notification {
    if (![notification.object isKindOfClass:[AlertWindow class]]) {
        self.hidden = YES;
        self.hidden = NO;
    }
}

@end

Basic usage that, by design, will always succeed:

[AlertWindow presentAlertWithTitle:@"My title" message:@"My message"];



回答24:


Sadly, the accepted solution did not work for my case. I was trying to navigate to a new View Controller right after unwind from another View Controller.

I found a solution by using a flag to indicate which unwind segue was called.

@IBAction func unwindFromAuthenticationWithSegue(segue: UIStoryboardSegue) {
    self.shouldSegueToMainTabBar = true
}

@IBAction func unwindFromForgetPasswordWithSegue(segue: UIStoryboardSegue) {
    self.shouldSegueToLogin = true
}

Then present the wanted VC with present(_ viewControllerToPresent: UIViewController)

override func viewWillAppear(_ animated: Bool) {
    super.viewWillAppear(animated)
    let storyboard = UIStoryboard(name: "Main", bundle: nil)
    if self.shouldSegueToMainTabBar {
        let mainTabBarController = storyboard.instantiateViewController(withIdentifier: "mainTabBarVC") as! MainTabBarController
        self.present(mainTabBarController, animated: true)
        self.shouldSegueToMainTabBar = false
    }
    if self.shouldSegueToLogin {
        let loginController = storyboard.instantiateViewController(withIdentifier: "loginVC") as! LogInViewController
        self.present(loginController, animated: true)
        self.shouldSegueToLogin = false
    }
}

Basically, the above code will let me catch the unwind from login/SignUp VC and navigate to the dashboard, or catch the unwind action from forget password VC and navigate to the login page.




回答25:


I had similar issue on Swift 4.2 but my view was not presented from the view cycle. I found that I had multiple segue to be presented at same time. So I used dispatchAsyncAfter.

func updateView() {

 DispatchQueue.main.asyncAfter(deadline: .now() + 0.1) { [weak self] in

// for programmatically presenting view controller 
// present(viewController, animated: true, completion: nil)

//For Story board segue. you will also have to setup prepare segue for this to work. 
 self?.performSegue(withIdentifier: "Identifier", sender: nil)
  }
}



回答26:


I just had this issue too, but it had nothing to do with the timing. I was using a singleton to handle scenes, and I set it as the presenter. In other words "Self" wasn't hooked up to anything. I just made its inner "scene" the new presenter and voila, it worked. (Voila loses its touch after you learn its meaning, heh).

So yeah, it's not about "magically finding the right way", it's about understanding where your code stands and what it's doing. I'm happy Apple gave such a plain-English warning message, even with emotion to it. Kudos to the apple dev who did that!!




回答27:


If other solutions does not look good for some reason, you can still use this good old workaround of presenting with the delay of 0, like this:

dispatch_after(0, dispatch_get_main_queue(), ^{
    finishViewController *finished = [self.storyboard instantiateViewControllerWithIdentifier:@"finishViewController"];
    [self presentViewController:finished animated:NO completion:NULL];    
});

While I've seen no documented guarantee that your VC would be on the view hierarchy on the time dispatch block is scheduled to execution, I've observed it would work just fine.

Using delay of e.g. 0.2 sec is also an option. And the best thing - this way you don't need to mess with boolean variable in viewDidAppear:




回答28:


This works for to present any view controller ,if you have navigation controller available. self.navigationController?.present(MyViewController, animated: true, completion: nil) Also , I can able to present alerts and mail controller also.




回答29:


I fixed this error with storing top most viewcontroller into constant which is found within while cycle over rootViewController:

if var topController = UIApplication.shared.keyWindow?.rootViewController {
    while let presentedViewController = topController.presentedViewController {
        topController = presentedViewController
    }
    topController.present(controller, animated: false, completion: nil)
    // topController should now be your topmost view controller
}


来源:https://stackoverflow.com/questions/11862883/attempt-to-present-uiviewcontroller-on-uiviewcontroller-whose-view-is-not-in-the

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