formula

How to map a property with formula in NHibernate?

旧时模样 提交于 2019-12-02 05:16:41
I have a class which I want to add a property with using formula attribute. Here is the mapping that I use in mapping file. <property name="CurrentUserVote" type="Climate.Domain.Vote, Climate.Domain" formula="(select v from Vote v where v.AchievementId=Id and (v.IP=:CurrentUserVoteFilter.CurrentUserIP))"></property> As you see, I want this property to be an object which refers to class that already has an nhibernate mapping. But this mapping gives a mapping exception; Could not determine type for: Climate.Domain.Vote, Climate.Domain, for columns: NHibernate.Mapping.Formula( (select v from Vote

What does a formula with no left argument mean in R, e.g. ~x?

荒凉一梦 提交于 2019-12-02 04:00:25
I understand that in a formula like y ~ x I am looking at "y" as a function of "x". In maths this would be something like f(x) = x . In R, functions like xtabs can take formula objects without a left side, e.g. xtabs( ~ x) . From my understanding of formulas, I am now looking at nothing as a function of "x", in maths = x , but that is obviously not how R understands the formula (it returns a contingency table of a factor, for example). So how can I understand the meaning of an empty left hand argument? I'm sure this has been explained somewhere, but I have a hard time googling for "R ~".

VBA — variable in .formula

送分小仙女□ 提交于 2019-12-02 03:52:07
is there a more elegant (simpler) way to put a variable in .formula? I don't want to use .formulaR1C1 I have this code: Range("C8").Select Selection.End(xlDown).Select PosR = ActiveCell.Row KonR = PosR - 2 Range("N" & PosR).Select aAddress = Range("$N$9").Address & ":" & Range("$N$" & KonR).Address ActiveCell.Formula = "=SUM(" & aAddress & ")" Obviously I want to put =SUM($N$9:$N$101) (101 is the last cell minus 2) into that cell and this code does the job. But I just want to be sure that this is the easiest way to do this. The easiest way is to skip all that selecting and those variables PosR

NetSuite saved search formula to multiply results of two other columns

南笙酒味 提交于 2019-12-02 03:04:15
I currently have a saved search that populates a list of items. My current results are standard NetSuite fields which are "Name", "Description", "Type", "Average Cost" & "Available" I am trying to add another column for a formula that multiplies the Average Cost by the Available to give me the Value of the Available SOH. In your saved search results add a new field of type formula(numeric) . In the formula popup window use this formula: NVL({averagecost}, 0) * NVL({quantityavailable}, 0) This will multiply the average cost and quantity available together and give you the result. I put the NVL

Crystal Report Date formula to make it the end of the month

我是研究僧i 提交于 2019-12-02 02:01:16
问题 I'm new to CR and need a formula that would give me the end of the month a on a date field. If the Date is 628/2012 or 7/12/2012 I need the formula to to be the end of the month no matter which day of the month the field shows. Of course we know that not every month ends on the 30th or 31th and February sometimes 29th or 30th. So what formula can I use to do this Example field name {table.end_date} Any help is greatly appreciated. Thanks in advance. 回答1: Create a formula field to calculate

Crystal Report Date formula to make it the end of the month

亡梦爱人 提交于 2019-12-02 01:22:38
I'm new to CR and need a formula that would give me the end of the month a on a date field. If the Date is 628/2012 or 7/12/2012 I need the formula to to be the end of the month no matter which day of the month the field shows. Of course we know that not every month ends on the 30th or 31th and February sometimes 29th or 30th. So what formula can I use to do this Example field name {table.end_date} Any help is greatly appreciated. Thanks in advance. Create a formula field to calculate the end of the month: //{@EndOfMonth} // find the first day of the month, add a month to it, then subtract a

How to write Mathematical formula with “^” (caret) in JavaScript?

梦想的初衷 提交于 2019-12-02 01:20:17
I need some help how to make this math formula in javascript. i have tried searching but couldn't really find cause i dont even know what ^ is called in English. Thanks in advance Math.floor(20*(1.1^(x-10))); Math.floor(20*(Math.pow(1.1, (x-10)))); ^ is the bitwise XOR operator - not what you want. Use the Math.pow function for exponentiation: Math.floor( 20 * (Math.pow(1.1, x - 10)) ); Set this up in a function so you can use x for whatever value it may be: var eq = function(x) { return Math.floor( 20 * (Math.pow(1.1, x - 10)) ); }; Math.pow() is what you are looking for. ^ , as used in other

Reading rpart Input Parameters from a Text Variable

℡╲_俬逩灬. 提交于 2019-12-02 00:45:30
问题 I'm using rpart to make a decision tree. For example: fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis) How do I read in the formula part from a text file and get it in a format that rpart likes? I've tried: predictor_variables <- c("Age", "Number", "Start") rpart_formula <- Kyphosis ~ parse(text=paste(predictor_variables, collapse="+")) fit <- rpart(rpart_formula, data=kyphosis) but I get an error: invalid type (expression) for variable 'parse(text = paste(predictor_variables,

Reading rpart Input Parameters from a Text Variable

ε祈祈猫儿з 提交于 2019-12-01 21:52:47
I'm using rpart to make a decision tree. For example: fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis) How do I read in the formula part from a text file and get it in a format that rpart likes? I've tried: predictor_variables <- c("Age", "Number", "Start") rpart_formula <- Kyphosis ~ parse(text=paste(predictor_variables, collapse="+")) fit <- rpart(rpart_formula, data=kyphosis) but I get an error: invalid type (expression) for variable 'parse(text = paste(predictor_variables, collapse = "+"))' How can I format rpart_formula so that rpart sees it correctly? Use as.formula : rpart

Extract Formula From lm with Coefficients (R)

核能气质少年 提交于 2019-12-01 20:52:33
问题 I have an lm object and want to get the formula extracted with coefficients. I know how to extract the formula without coefficients, and how to get the coefficients without the formula, but not how to get eg. y ~ 10 + 1.25b as opposed to y~b or a table of what intercept, b etc. equal This is the code I'm working with currently: a = c(1, 2, 5) b = c(12, 15, 20) model = lm(a~b) summary(model) formula = formula(model) formula coefficients(model) What I'd like to get from the above is y ~ -5.326