formula

VBA to fill formula down until last row in empty column

房东的猫 提交于 2019-12-02 13:02:01
I have a report with a row count that changes daily. I need to autofill column C with a formula down to the last row of column B (columns A and B have different row counts, if that matters). I have the formula in C2 (and a header in C1), how do I get vba to copy the formula in C2 down to the same row number as column B? let C2 Autofill the column C until the last populated cell in column B : With Sheets("Report") .Range("C2").AutoFill .Range("C2:C" & .Cells(.Rows.count, "B").End(xlUp).row) End With 来源: https://stackoverflow.com/questions/44191297/vba-to-fill-formula-down-until-last-row-in

How to map a property with formula in NHibernate?

岁酱吖の 提交于 2019-12-02 12:29:19
问题 I have a class which I want to add a property with using formula attribute. Here is the mapping that I use in mapping file. <property name="CurrentUserVote" type="Climate.Domain.Vote, Climate.Domain" formula="(select v from Vote v where v.AchievementId=Id and (v.IP=:CurrentUserVoteFilter.CurrentUserIP))"></property> As you see, I want this property to be an object which refers to class that already has an nhibernate mapping. But this mapping gives a mapping exception; Could not determine type

NetSuite saved search formula to multiply results of two other columns

杀马特。学长 韩版系。学妹 提交于 2019-12-02 12:06:58
问题 I currently have a saved search that populates a list of items. My current results are standard NetSuite fields which are "Name", "Description", "Type", "Average Cost" & "Available" I am trying to add another column for a formula that multiplies the Average Cost by the Available to give me the Value of the Available SOH. 回答1: In your saved search results add a new field of type formula(numeric) . In the formula popup window use this formula: NVL({averagecost}, 0) * NVL({quantityavailable}, 0)

Formula in Netsuite Saved Search

不打扰是莪最后的温柔 提交于 2019-12-02 11:16:56
I have a problem here. In Column 1 I have count of All he transaction, In column 2 I have Count of transaction of specific status. In column 3 I want the percentage of above 2; like count of specific transaction/Count of total. Is it possible in Netsuite? Actually there is an interesting feature that makes this possible. Formula fields that have aggregate functions work when the row has an aggregate on it. So for instance if you wanted to see a percentage of orders with status Billed on a Sales Order search you would enter a Formula (Percent) result with a formula like: sum(case when {status}

What does a formula with no left argument mean in R, e.g. ~x?

痞子三分冷 提交于 2019-12-02 10:59:03
问题 I understand that in a formula like y ~ x I am looking at "y" as a function of "x". In maths this would be something like f(x) = x . In R, functions like xtabs can take formula objects without a left side, e.g. xtabs( ~ x) . From my understanding of formulas, I am now looking at nothing as a function of "x", in maths = x , but that is obviously not how R understands the formula (it returns a contingency table of a factor, for example). So how can I understand the meaning of an empty left hand

Running lagged regressions with lapply and two arguments

喜欢而已 提交于 2019-12-02 10:23:37
问题 I am running multiple univariate regressions, like in this reproducible example: require(dynlm) data(USeconomic) US<-USeconomic vars<-colnames(US)[-2] a<-lapply(colnames(US),function(x) dynlm(log(GNP)~get(x),data=US)) a contains a list of 3 univariate regressions. Assume now I´d like to run the same regressions with 3 lags: l<-c(0,1,4) where 0 is of course the case I already got. Is there a way to use the vector l directly, like # this did not work for me, I obtain multivariate regressions

Hibernate 中<Property>中的formula属性的使用

末鹿安然 提交于 2019-12-02 10:02:41
Hibernate 中 formula属性的好用处在于 无需在数据库有真实的列 只需要写出sql 就可以创建一个 虚拟的列 然后在 Dao层 的查询中使用 ,比如在表 M_Confirmation 中有两列 Confirmation_Cost 和 Confirmation_Fee 这两列都容许包含null, 我们的query要求取得 Confirmation_Cost 和 Confirmation_Fee的和(暂时命名为Total_Price) 并查出此Total_Price>= 某个前台传进来的某个filter的数据 。 写成sql 就是 select (confirmation_cost + confirmation+fee) from m_confirmation where (confirmation_cost + confirmation+fee) >= ? ; 这时候创建虚拟列 ,formula后面的部分 会自动跟在hibernate发出的sql中 select后面作为一列 就好比 select formula from M_confirmation: <property name="totalPrice" formula="((CASE WHEN Confirmation_Cost IS NULL THEN 0 ELSE Confirmation_Cost END)

关于Hibernate 中formula简介

折月煮酒 提交于 2019-12-02 10:02:06
今天做项目第一次用到Hibernate的formula,解决了困扰了很长时间的一个问题 以前做各种层级树的时候,查询结点是不是叶子结点,如果是叶子节点就直接展开图标,当时想到了几种解决方案但是总感觉别扭,今天看hibernate书籍的时候看到了formula可以解决关于派生属性的映射,把项目中的代码重构了一下,顿时感觉很不错。 以前的解决方案如下: 解决方案一:在对应的entry上面做一个一对多关联,然后再 创建一个临时字段 @Transient private String shiFouYZJD 在getShiFouYZJD()中判断关联查询的set集合是不是empty,然后给shiFouYZJD附上对应的标识位,这种做法理解是好理解,但是当我的树层级超过三级树上节点数目超过一万就挂了,举个例子假如第二层节点有一百个,每个节点下再挂100个子节点。。。那么关联查询内存中存放的对象你懂得100*100.。。。 性能很受影响。 解决方案二: 写sql,用createSQLQuery然后得到一个List<Object[]> 类型的集合。。。紧接着做遍历new个实体然后使劲的set值。。如果一个表中有30个字段。。。你会瞬间崩溃的各种if(value!=null),最后功能实现了,但是代码你自己看的都蛋疼。。你自己都会想到肯定会有比这好的方法 今天用了formula感觉不错

Formula code in Word 2015 [mac]

隐身守侯 提交于 2019-12-02 08:08:52
问题 I'm currently making an invoice template in word, but I'm fighting with the formula code which is used. Currently this is my table: But, the number of rows wil depend on the days which I've worked. Right now, I have to manually alter the code to edit the cell-references (d9, b10, c10) if I create more rows. Is there an easier way to do this? To let the cell-reference automatically change or change the formula code in a way that naming the cell-references isn't needed? Thanks in advance :)

How to remove all text from right after certain characters in excel

余生颓废 提交于 2019-12-02 05:49:41
Sorry I'm a noob in excel and need help with this. Say I have the following text in my excel. D:/folder A/ folder B.1/text_01.txt D:/folder A/Folder C/ folder C.1/text_02.msg I like to remove all the text from the right after the first occurrence "/" counting from the right. So I would get the followings. D:/folder A/ folder B.1 D:/folder A/Folder C/ folder C.1 Use LEFT() with FIND and SUBSTITUTE to find the last / =LEFT(A1,FIND("}}}",SUBSTITUTE(A1,"/","}}}",LEN(A1)-LEN(SUBSTITUTE(A1,"/","")))-1) If you don't mind a bit of vba , then InStrRev was almost tailor made for cases like these: Public