fibonacci

问题 I was reading this Wikipedia article, and attempting to implement a 'map' based solution in C, where a 'map' is just an int array, initialized to 0. For some reason it works up to fib(93) , then starts outputting strange numbers. If it matter's I'm specifying -std=c99 : #include <stdio.h> #include <stdlib.h> // represents a fib num typedef unsigned long long fib_t; // the default value of our 'map' const int FIB_NULL = 0; // could get from input, set here for now const int FIB_MAX = 100; //

问题 the code below interates from Fibonacci 0 to 100. However after the Fibonacci number reaches 2 and moves on to 3, the resulting numbers are 0. when they should be 3, 5, 8 etc. by everything I see it should work and I am not sure why. However you will notice the else{ return 0; } at the end of the code, I did that because the code yells at me that the code is to return a value of type long. If there is a way to fix that please let know thanks guys public static void runFibonacci () { for (int

问题 Just started re-learning Haskell (did it at uni but forgot most of it) and thought I would implement a Fibonacci function to start of with. However, I keep getting a stackoverflow, even for very small n . Can anyone spot any problems with my function? fib :: Integer -> Integer fib 0 = 0 fib 1 = 1 fib n = fib (n-1) + fib (n+1) 回答1: You have an error in your fibonacci formula: fib :: Integer -> Integer fib 0 = 0 fib 1 = 1 fib n = fib (n-1) + fib (n-2) Note the very last term where there is n-2

问题 I was asked to use dynamic programming to solve a problem. I have mixed notes on what constitutes dynamic programming. I believe it requires a "bottom-up" approach, where smallest problems are solved first. One thing I have contradicting information on, is whether something can be dynamic programming if the same subproblems are solved more than once, as is often the case in recursion. For instance. For Fibonacci, I can have a recursive algorithm: RecursiveFibonacci(n) if (n=1 or n=2) return 1

问题 I am using Python to create a Fibonacci using this formula: I have this recursive Fibonacci function: def recursive_fibonacci(n): if n <= 1: return int((((1 / (5 ** 0.5)) * (1 + (5 ** 0.5))) ** n) - (((1 / (5 ** 0.5)) * (1 - (5 ** 0.5))) ** n)) else: return(recursive_fibonacci(n - 1) + recursive_fibonacci(n - 2)) To display it I am using this: nterms = 10 if nterms <= 0: print("Please Enter a positive integer") else: print("Recursive Fibonacci Sequence: " , [recursive_fibonacci(i) for i in

问题 I've spent considerable time today trying to calculate the Fibonacci nth term when n is a very large number. I decided to use Objective-C which in hindsight may not have been the best decision, considering how long it has taken. I researched and decided to use Binet's formula which seems to work for other people using other programming languages. double phi = (sqrt(5) + 1) / 2.0; long long j = (long long) round(pow(phi, number) / sqrt(5)); Is the gist of a fibonacci(number) function in C. I

问题 I was calculating the time complexity of this code that prints all Fibonacci numbers from 0 to n. According to what I calculated, the fib() method takes O(2^n) and since it is being called i number of times, so it came out to be O(n*2^n) . However, the book says it is O(2^n) . Can anyone explain why the time complexity here will be O(2^n) ? Here is the code: void allFib(int n){ for(int i = 0 ; i < n ; i++){ System.out.println(i + ": " + fib(i)); } } int fib(int n ){ if(n <= 0) return 0; else

问题 I know that the coding for the Fibonacci series is: int fib(int n) { if (n==0 || n==1) return n; else return fib(n-1)+fib(n-2); } I was wondering if there is a way, using the aforementioned code, to print the previous results of the series, but neither using a void function (that acts only like a printer of the series) or calling the fibonacci funcion for each calculation I do not want to do this for (int i=0;i<4;i++){ System.out.prinntln(fib(i)); } Intead I want to only call the function

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I implemented the following tail-call recursive fibonacci function to try out gcc's Tail Call Optimization (as mentioned here): #include <stdint.h> uint64_t fib_tc( uint8_t n) { uint64_t fib_helper(uint8_t n, uint64_t acc, uint64_t prev) { if(n == 0) return acc; else return fib_helper( n-1, acc+prev, acc); } fib

问题 (ns src.helloworld) (defn fibonacci[a b] (println a b (fibonacci (+ b 1) a + b))) (fibonacci 0 1) I'm new to Functional Programming and decided to start learning Clojure as it's very different from C#. I'd like to broaden my horizons. Here's the error I get: Clojure 1.2.0 java.lang.IllegalArgumentException: Wrong number of args (4) passed to: helloworld$fibonacci (helloworld.clj:0) 1:1 user=> #<Namespace src.helloworld> 1:2 src.helloworld=> Math problems never were my strong suit and I never