elementtree

I have a dict that's feed with url response. Like: >>> d { 0: {'data': u'<p>found "\u62c9\u67cf \u591a\u516c \u56ed"</p>'} 1: {'data': u'<p>some other data</p>'} ... } While using xml.etree.ElementTree function on this data values ( d[0]['data'] ) I get the most famous error message: UnicodeEncodeError: 'ascii' codec can't encode characters... What should I do to this Unicode string to make it suitable for ElementTree parser? PS. Please don't send me links with Unicode & Python explanation. I read it all already unfortunately, and can't make use of it, as hopefully others can. You'll have to

I am getting a path separator error in python 2.6.1. I have not found this issue with python 2.7.2 version, but unfortunately I need this in 2.6.1 only. Is there any another way to achieve the same? :( my code :- import xml.etree.ElementTree as ET #version 1.2.6 import sys class usersDetail(object): def __init__(self, users=None): self.doc = ET.parse("test.xml") self.root = self.doc.getroot() def final_xml(self,username): r = self.root.find("user[@username='user1']") #not working in 2.6.1 :( self.root.remove(r) print r tree = ET.ElementTree(self.root) tree.write("msl.xml") if __name__ == '_

Is there a way to ignore the XML namespace in tage names in elementtree.ElementTree ? I try to print all technicalContact tags: for item in root.getiterator(tag='{http://www.example.com}technicalContact'): print item.tag, item.text And I get something like: {http://www.example.com}technicalContact blah@example.com But what I really want is: technicalContact blah@example.com Is there a way to display only the suffix (sans xmlns), or better - iterate over the elements without explicitly stating xmlns? You can define a generator to recursively search through your element tree in order to find

I'm trying to parse an XML document I retrieve from the web, but it crashes after parsing with this error: ': failed to load external entity "<?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="GreenButtonDataStyleSheet.xslt"?> That is the second line in the XML that is downloaded. Is there a way to prevent the parser from trying to load the external entity, or another way to solve this? This is the code I have so far: import urllib2 import lxml.etree as etree file = urllib2.urlopen("http://www.greenbuttondata.org/data/15MinLP_15Days.xml") data = file.read() file

Possible Duplicate: When using lxml, can the XML be rendered without namespace attributes? How can I strip the python attributes from an lxml.objectify.ObjectifiedElement ? Example: In [1]: from lxml import etree, objectify In [2]: foo = objectify.Element("foo") In [3]: foo.bar = "hi" In [4]: foo.baz = 1 In [5]: foo.fritz = None In [6]: print etree.tostring(foo, pretty_print=True) <foo xmlns:py="http://codespeak.net/lxml/objectify/pytype" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" py:pytype="TREE"> <bar py:pytype="str">hi</bar> <baz py