问题
I have the following XML file as input:
<Test>
<callEvents>
<moc>
<causeForTermination>0</causeForTermination>
<serviceCode>
<teleServiceCode>11</teleServiceCode>
</serviceCode>
<dialledDigits>5555555</dialledDigits>
<connectedNumber>77777</connectedNumber>
</moc>
<moc>
<causeForTermination>0</causeForTermination>
<serviceCode>
<teleServiceCode>11</teleServiceCode>
</serviceCode>
<dialledDigits>2222222</dialledDigits>
</moc>
</callEvents>
<callEventsCount>100</callEventsCount>
</Test>
I want to output all the values for dialledDigits. However, my code only displays the first instance of dialledDigits.
dialledDigits {} 5555555
My desired output should contain both instances.
dialledDigits {} 5555555
dialledDigits {} 2222222
Here is my code
import xml.etree.ElementTree as ET
tree = ET.parse('as.xml')
root = tree.getroot()
callevent=root.find('callEvents')
Moc1=callevent.find('moc')
for node in Moc1.getiterator():
if node.tag=='dialledDigits':
print node.tag, node.attrib, node.text
回答1:
Use findall:
moc1 = callevent.findall('moc')
for moc in moc1:
for node in moc.getiterator():
if node.tag=='dialledDigits':
print node.tag, node.attrib, node.text
Output:
dialledDigits {} 5555555
dialledDigits {} 2222222
回答2:
You can also write an XPath expression. Just 2 lines instead of 5 and a single loop:
for node in tree.findall('.//callEvents/moc/dialledDigits'):
print node.tag, node.attrib, node.text
Demo:
>>> import xml.etree.ElementTree as ET
>>>
>>>
>>> tree = ET.parse('as.xml')
>>> root = tree.getroot()
>>>
>>> for node in tree.findall('.//callEvents/moc/dialledDigits'):
... print node.tag, node.attrib, node.text
...
dialledDigits {} 5555555
dialledDigits {} 2222222
回答3:
find()
will return first tag object, so use finadall()
which return all tag objects`
>>> Moc1=callevent.find('moc')
>>> Moc1
<Element 'moc' at 0x869a2ac>
>>> Moc1=callevent.findall('moc')
>>> Moc1
[<Element 'moc' at 0x869a2ac>, <Element 'moc' at 0x869a4ec>]
>>>
Iterate on it:
>>> Mocs=callevent.findall('moc')
>>> for moc in Mocs:
... for node in moc.getiterator():
... if node.tag=='dialledDigits':
... print node.tag, node.attrib, node.text
...
dialledDigits {} 5555555
dialledDigits {} 2222222
来源:https://stackoverflow.com/questions/29266605/getting-all-instances-of-child-node-using-xml-etree-elementtree