each

jquery: reverse an order

拜拜、爱过 提交于 2019-12-04 09:17:57
问题 How can I reverse an order with jquery? I tried with the suggestion like this but it won't work! $($(".block-item").get().reverse()).each(function() { /* ... */ }); Have a look here. I want the boxed to be rearranged like this, 18 17 16 etc Thanks. 回答1: If you have a container around the list, it's a little easier: $("#container").append($(".block-item").get().reverse()); http://jsfiddle.net/BhTEN/12/ 回答2: You can use this: $($(".block-item").get().reverse()).each(function (i) { $(this).text(

Project Four: Blackjack

一个人想着一个人 提交于 2019-12-04 06:24:59
Project Four: Blackjack Out: Oct. 31, 2019; Due: Nov. 14, 2019 I. Motivation To give you experience in implementing abstract data types (ADTs), using interfaces (abstract base classes), and using interface/implementation inheritance. II. Introduction In this project, we will implement a simplified version of the card game called Blackjack, also sometimes called 21. It is a relatively simple game played with a standard deck of 52 playing cards. There are two participants, a dealer and a player. The player starts with a bankroll, and the game progresses in rounds called hands. At the start of

Jmeter参数化总结

女生的网名这么多〃 提交于 2019-12-04 06:22:38
参数化步骤: 1.连接数据库 2.获取account表手机号数据 3.获取手机号个数 4.增加For Each控制器 5.将请求添加至循环控制器里面 脚本: 循环登录.jmx 页面如下: 下面主要说明For Each控制器的配置: 部分操作参考: Jmeter接口关联总结 、 Jmeter压测数据库总结 ,其实就是把这些组合起来 配置如下: 来源: https://www.cnblogs.com/wanyuan/p/11837369.html

Practical Uses for jQuery's $().each() method for a presentation

一笑奈何 提交于 2019-12-04 06:03:55
I'm giving a presentation to some coworkers today on how to use jQuery with ColdFusion. This is more of an introduction to jQuery than an advanced session. I'm trying to show how one can loop using jQuery's $().each() method, and in trying to come up with some practical, real world examples and I've drawn a blank. Any suggestions? // changes every other div green $("div").each(function(i) { if (i % 2) this.style.backgroundColor = "green"; }); Skip it. It'd be confusing to the new users, anyhow. jQuery returns arrays of objects and applies function calls to each already, which isn't obvious to

Jquery之each函数详解

末鹿安然 提交于 2019-12-04 05:33:26
目录 Jquery之each函数详解 全局jQuery.each() 函数详解 each函数处理一维数组 each函数遍历二维数组 使用each函数遍历对象属性 jQuery.each()函数同样可以遍历jQuery对象中匹配的元素 遍历Dom中的元素 再来看一个Json的子: 区别 $ ().each()和$.each()/jQuery.each() 总结 $().each $.each() Jquery之each函数详解 全局jQuery.each() 函数详解   所谓全局jQuery.each()函数也即是指$.each()函数,它可以用来遍历任何一个集合,不管是一个JavaScript对象或者是一个数组,或者是一个JSon对象。它的基本语法如下: $.each(collection, callback(indexInArray, valueOfElement) ) collection可以是数组,可以是任何一个JS对象或者JSON对象,callback我们称之为回掉函数;如果是一个数组的话,回调函数每次传递一个数组的下标和这个下标所对应的数组的值;callback回调函数用于遍历指定的对象和数组,并以对象的每个属性(或数组的每个成员)作为上下文来遍历执行指定的函数。 我们来看下面的几个例子大家就明白了: each函数处理一维数组 var arr1 = [ "aaa",

Jquery if its the first time element is being clicked

我们两清 提交于 2019-12-04 05:05:58
I need my script to do something on the first time an element is clicked and continue to do something different on click 2,3,4 and so on $('selector').click(function() { //I would realy like this variable to be updated var click = 0; if (click === 0) { do this var click = 1; } else { do this } });//end click really I think it should rely on the variables but I can't think of how to update the variable from here on out any help would be awesome. Have a look at jQuery's .data() method. Consider your example: $('selector').click(function() { var $this = $(this), clickNum = $this.data('clickNum');

Break D3 Each Loop Without a flag

戏子无情 提交于 2019-12-04 04:39:36
问题 Consider the following code: circle.each(function (d) { //...code }); How can I break the loop? Is there a natural D3 way to break out of an each loop? I mean without a flag as follows: var flag = false; circle.each(function (d) { if (flag) return; if (someCondition) flag = true; //...code }); I've tried returning false inside the if statement but it did not work (thought that maybe this would work the same as jquery.each but I was wrong): circle.each(function (d) { if (someCondition) return

第016讲:序列!序列

只谈情不闲聊 提交于 2019-12-04 04:26:48
0.我们根据列表、元组和字符串的共同特点,把它们三统称为什么?   me:a)都可以通过索引值得到每个元素;b)默认的索引值都是从零开始;c)都可以通过切片的方式得到一个范围内的元素集合;d)有很多共同的操作符(重复操作符,拼接操作符,成员关系操作符)   参考答案:序列,因为他们有以下共同点:         1)都可以通过索引得到每一个元素         2)默认索引值总是从0开始(当然灵活的Python还支持负数索引)         3)可以通过分片的方法得到一个范围内的元素的集合         4)有很多共同的操作符(重复操作符、拼接操作符、成员关系操作符) 1.请问分别使用什么BIF,可以把一个可迭代对象转换为列表、元组和字符串?   me:list()--转换为列表、taple()--转换为元组、str()--转换为字符串   参考答案: list([iterable]) 把可迭代对象转换为列表         tuple([iterable]) 把可迭代对象转换为元组         str(obj) 把对象转换为字符串 例如 temp = 'I love FishC.com!' list(temp) ['I', ' ', 'l', 'o', 'v', 'e', ' ', 'F', 'i', 's', 'h', 'C', '.', 'c', 'o', 'm',

how to use for each with mustache javascript?

对着背影说爱祢 提交于 2019-12-04 03:56:39
i have some json objects and some of them have some other objects inside them. if i leave only the json obj that don't have other obj inside them and then apply the template, everything goes well, i get, in this case 3 li elements. but if i grab the original json obj the results are a bit wired. I believe i need to do a each statement to iterate through each sub json obj from inside each main one maybe i am a bit confuse so here is some code. i have some json data like this: { "msg_id":"134", "message":"Nick", "comment":[ { "com_id":"9", "comment":"test", }, { "com_id":"10", "comment":"testtt"