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can someone tell me what the difference between assigning event handlers using bind(): $(function(){ $('someElement') .bind('mouseover',function(e) { $(this).css({ //change color }); }) .bind('mouseout',function(e) { $(this).css({ //return to previous state }); }) .bind('click',function(e) { $(this).css({ //do smth. }); }) }); and using each() for the same task: $('someElement').each(function(){ $(this).mouseover(function(){$(this).css({/*change color*/}) .mouseout(function(){$(this).css({/*return to previous state*/}); }); }); }); thank you. KyleFarris From the examples you gave, I think you

I have a very long list of names, each of which will be wrapped in span tags. Example: <span>Yang Zajicek</span> <span>Daniela Athey</span> <span>Alanna Bumpers</span> <span>Audry Waldron</span> <span>Agnes Wininger</span> <span>Tarah Mandelbaum</span> <span>Dedra Paille</span> <span>Codi Morrone</span> <span>Shan Huntoon</span> <span>Silas Zerangue</span> <span>Thalia Saleh</span> <span>Britt Spurlock</span> <span>Miguelina Dasilva</span> <span>Scott Scholz</span> <span>Judith Badura</span> <span>Alfredia Kidder</span> <span>Jae Doty</span> <span>Charise Blakeslee</span> <span>Yen Axelson<

Closed . This question is opinion-based. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it can be answered with facts and citations by editing this post . Closed 6 years ago . Should we prefer the for-each loop instead of the traditional for-loops? Is the while-loop advantageous? List<String> names = Arrays.asList("John", "Jeff", "Mary", "Elise"); //for-each loop for(String name: names){ log(name); } //traditional for-loop for(int index=0; index < 10; ++index){ log(names.get(index)); } //Iterator while Iterator<String> iter1 = names

i am building an jQuery plugin, but i want to use objects in the options var, how can i loop this with the jQuery each? plugin options var var defaults = { test: 'yes', //css/classes type: { minvalue: '100', maxvalue: '200', name: 'id1' }, type: { minvalue: '200', maxvalue: '300', name: 'id2' }, type: { minvalue: '300', maxvalue: '400', name: 'id3' } }; $.each(defaults, function(key, value) { alert(key + ': ' + value); }); With your example it is a bit difficult to figure what exactly you are trying to do, but if you want to use arrays and $.each , you could do this: var defaults = { test:

这篇文章是关于C++语言的一个新的扩展——标准模板库的（Standard Template Library），也叫STL。 当我第一次打算写一篇关于STL的文章的时候，我不得不承认我当时低估了这个话题的深度和广度。有很多内容要含盖，也有很多详细描述STL的书。因此我重新考虑了一下我原来的想法。我为什么要写这篇文章，又为什么要投稿呢？这会有什麽用呢？有再来一篇关于STL的文章的必要吗？ 当我翻开Musser and Saini的页时，我看到了编程时代在我面前消融。我能看到深夜消失了， 目标软件工程出现了。我看到了可维护的代码。一年过去了，我使用STL写的软件仍然很容易维护。 让人吃惊的是其他人可以没有我而维护的很好！ 然而，我也记得在一开始的时候很难弄懂那些技术术语。一次，我买了Musser&Saini，每件事都依次出现，但是在那以前我最渴望得到的东西是一些好的例子。 当我开始的时候，作为C++一部分的Stroustrup还没出来，它覆盖了STL。 因此我想写一篇关于一个STL程序员的真实生活的文章可能会有用。如果我手上有一些好的例子的话，特别是象这样的新题目，我会学的更快。 另外一件事是STL应该很好用。因此，理论上说，我们应该可以马上开始使用STL。 什麽是STL呢？STL就是Standard Template Library，标准模板库

You play a computer game. In this game, you lead a party of m m heroes, and you have to clear a dungeon with n n monsters. Each monster is characterized by its power a i ai. Each hero is characterized by his power p i pi and endurance s i si. The heroes clear the dungeon day by day. In the beginning of each day, you choose a hero (exactly one) who is going to enter the dungeon this day. When the hero enters the dungeon, he is challenged by the first monster which was not defeated during the previous days (so, if the heroes have already defeated k k monsters, the hero fights with the monster k

D. Yet Another Monster Killing Problem You play a computer game. In this game, you lead a party of 𝑚 heroes, and you have to clear a dungeon with 𝑛 monsters. Each monster is characterized by its power 𝑎𝑖. Each hero is characterized by his power 𝑝𝑖 and endurance 𝑠𝑖. The heroes clear the dungeon day by day. In the beginning of each day, you choose a hero (exactly one) who is going to enter the dungeon this day. When the hero enters the dungeon, he is challenged by the first monster which was not defeated during the previous days (so, if the heroes have already defeated 𝑘 monsters, the hero