each

Is it possible to use variable names dynamically in SASS each loop? [duplicate]

由 我们两清 提交于 2019-12-30 08:03:44
问题 This question already has answers here : Creating or referencing variables dynamically in Sass (5 answers) Closed 4 years ago . This is a simplified example. What I'd like to do is use the items in the array to output variable values I've previously created. The syntax below that tries create a variable by concatenating a '$' is obviously wrong but I'm using it to make it clear what I'm trying to do. $puma-width: 100px; $slug-width: 200px; @each $animal in puma, slug { .#{$animal}-title {

Get label for input field

由 ⅰ亾dé卋堺 提交于 2019-12-30 08:03:12
问题 I'm doing a validation with Jquery and need to get the $label from each element with their own label. Now the alert() gives med [object object]. The best thing for me here is to get an alert() with all fields lined up that is not filled out. And not an alert() for each. Here is a fiddle: http://jsfiddle.net/s7pYX/ How is this accomplished? HTML: <div> <label for="txtName">Name</label> <input type="text" id="txtName" class="form-control" name="txtName"> </div> <div> <label for="txtEmail">E

ZeptoLab Code Rush 2015 B. Om Nom and Dark Park DFS

由 帅比萌擦擦* 提交于 2019-12-30 00:45:47
B. Om Nom and Dark Park Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/526/problem/B Description Om Nom is the main character of a game "Cut the Rope". He is a bright little monster who likes visiting friends living at the other side of the park. However the dark old parks can scare even somebody as fearless as Om Nom, so he asks you to help him. The park consists of 2 n  + 1  - 1 squares connected by roads so that the scheme of the park is a full binary tree of depth n . More formally, the entrance to the park is located at the square 1. The exits out of the park

Tell the end of a .each loop in ruby

由 橙三吉。 提交于 2019-12-29 03:12:15
问题 If i have a loop such as users.each do |u| #some code end Where users is a hash of multiple users. What's the easiest conditional logic to see if you are on the last user in the users hash and only want to execute specific code for that last user so something like users.each do |u| #code for everyone #conditional code for last user #code for the last user end end 回答1: users.each_with_index do |u, index| # some code if index == users.size - 1 # code for the last user end end 回答2: If it's an

Tell the end of a .each loop in ruby

由 点点圈 提交于 2019-12-29 03:12:10
问题 If i have a loop such as users.each do |u| #some code end Where users is a hash of multiple users. What's the easiest conditional logic to see if you are on the last user in the users hash and only want to execute specific code for that last user so something like users.each do |u| #code for everyone #conditional code for last user #code for the last user end end 回答1: users.each_with_index do |u, index| # some code if index == users.size - 1 # code for the last user end end 回答2: If it's an

jQuery关于$.each()的应用说明

由 ╄→尐↘猪︶ㄣ 提交于 2019-12-28 17:04:23
jQuery中$.each()方法的使用 $.each()是对数组，json和dom结构等的遍历，说一下他的使用方法吧。 1、遍历一维数组 var arr1=[‘aa’,‘bb’,‘cc’,‘dd’]; $.each(arr1,function(i,val){ //两个参数，第一个参数表示遍历的数组的下标，第二个参数表示下标对应的值 console.log(i+’```````’+val); 输出的结果为： 0 aa 1 bb 2 cc 3 dd 2、遍历二维数组 var arr2=[[‘aaa’,‘bbb’],[‘ccc’,‘ddd’],[‘eee’,‘fff’]]; $.each(arr2,function(i,item){ //两个参数，第一个参数表示下标，第二个参数表示一维数组中的每一个数组 console.log(i+’````’+item); 输出的结果为： 0 aaa,bbb 1 ccc,ddd 2````eee,fff 此时可以对输出的一维数组进行遍历 $.each(item,function(i,val){ //遍历二维数组 console.log(i+’`````’+val); }) 输出的结果为： 0 aaa,bbb 0`````aaa 1`````bbb 1 ccc,ddd 0 ccc 1 ddd 2````eee,fff 0 eee 1 fff 3

《英语语法新思维初级教程》学习笔记（四）数量限定词和个体限定词

由 风格不统一 提交于 2019-12-28 15:16:41
　　参考资料： 　　1. 《英语语法新思维初级教程》 　　 　　▶ 知识点 　　▼ 数量限定词：a few， few / a little， little 　　 从与名词的搭配来看，a few和few的后边只能接复数名词，而a little和little的后面只能接不可数名词。 　　▼ 数量限定词：some / any 　　从与名词的搭配来看，some和any均可以与不可数名词及可数名词复数连用，表示“一些”。some一般用于肯定句中，而any一般用在否定句中。 　　在疑问句中，当我们期待一个正面的回答或要鼓励对方说“是”时，要在疑问句中用some。 Would you like to give me some advice? Can I have some more coffee? 　　 当any后面接单数名词时，它的意思是“无论哪一个，任何一个”，可用于任何类型的句子中。 You can ask any person over there. 　　 当some与单数可数名词连用时，它的意思是“某一个”的意思。 Some person at the gate is asking to see you. 　　 　　▼ 个体限定词：each / every 　　从与名词的搭配来看，each和every的后面都只能接单数可数名词，这就是为什么称它们为“个体”限定词的原因。 　　两者的差别

jQuery animated number counter from zero to value

由 柔情痞子 提交于 2019-12-27 19:09:28
问题 I have created a script to animate a number from zero to it's value. Working jQuery $({ Counter: 0 }).animate({ Counter: $('.Single').text() }, { duration: 1000, easing: 'swing', step: function() { $('.Single').text(Math.ceil(this.Counter)); } }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <span class="Single">150</span> Not Working I now want to run the script several times on the page for each matching class. Below is what I am trying but with

PAT 1016. Phone Bills

由 人盡茶涼 提交于 2019-12-26 23:58:53
PAT 1016. Phone Bills A long-distance telephone company charges its customers by the following rules: Making a long-distance call costs a certain amount per minute, depending on the time of day when the call is made. When a customer starts connecting a long-distance call, the time will be recorded, and so will be the time when the customer hangs up the phone. Every calendar month, a bill is sent to the customer for each minute called (at a rate determined by the time of day). Your job is to prepare the bills for each month, given a set of phone call records. Input Specification: Each input

PAT 1080. Graduate Admission (30)

由 倾然丶 夕夏残阳落幕 提交于 2019-12-26 23:09:28
It is said that in 2013, there were about 100 graduate schools ready to proceed over 40,000 applications in Zhejiang Province. It would help a lot if you could write a program to automate the admission procedure. Each applicant will have to provide two grades: the national entrance exam grade G E , and the interview grade G I . The final grade of an applicant is (G E + G I ) / 2. The admission rules are: The applicants are ranked according to their final grades, and will be admitted one by one from the top of the rank list. If there is a tied final grade, the applicants will be ranked
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