问题
This is a simplified example. What I'd like to do is use the items in the array to output variable values I've previously created. The syntax below that tries create a variable by concatenating a '$' is obviously wrong but I'm using it to make it clear what I'm trying to do.
$puma-width: 100px;
$slug-width: 200px;
@each $animal in puma, slug {
.#{$animal}-title {
width: $+#{$animal}-width;
}
}
Desired output:
.puma-title {
width: 100px;
}
.slug-title {
width: 200px;
}
回答1:
That's something that I wanted in SASS as well, but after reading their discussion list, I concluded that this kind of variable interpolation is not supported yet.
I didn't try Less, but their documentation suggests it would be possible with @@ syntax.
回答2:
The alternative is to pass a map instead of item list for the @each directive. The following will work:
@each $animal, $width in (puma, 100px),
(slug, 200px) {
.#{$animal}-title {
width: #{$width};
}
}
来源：https://stackoverflow.com/questions/7209031/is-it-possible-to-use-variable-names-dynamically-in-sass-each-loop