duplicates

find and update duplicates in a list of lists

由 孤街醉人 提交于 2019-12-01 11:22:03
I am looking for a Pythonic way to solve the following problem. I have (what I think is) a working solution but it has complicated flow controls and just isn't "pretty". (Basically, a C++ solution) I have a list of lists. Each list contains multiple items of varying types (maybe 10 items per list) The overall order of the lists is not relevant, but the order of the items in any individual list is important. (ie I can't change it). I am looking to "tag" duplicates by adding an extra field to the end of an individual list. However, in this case a "duplicate" list is one that has equal values in

How to avoid duplicate insert in Entity Framework 4.3.1

由 旧城冷巷雨未停 提交于 2019-12-01 11:21:50
问题 I have a small model created using code-first approach - a class City which contains only information about city name. public class City { public City() { Posts = new List<Post>(); } public City(string cityName) { Name = cityName; } public virtual ICollection<Post> Posts { get; private set; } public int Id { get; set; } public string Name { get; private set; } } A Post class represents combination of zip code and city reference public class Post { public virtual City City { get; set; } public

Best way to remove duplicate characters (words) in a string?

由 被刻印的时光 ゝ 提交于 2019-12-01 11:18:57
What would be the best way of removing any duplicate characters and sets of characters separated by spaces in string? I think this example explains it better: foo = 'h k k h2 h' should become: foo = 'h k h2' # order not important Other example: foo = 's s k' becomes: foo = 's k' ' '.join(set(foo.split())) Note that split() by default will split on all whitespace characters. (e.g. tabs, newlines, spaces) So if you want to split ONLY on a space then you have to use: ' '.join(set(foo.split(' '))) Do you mean? ' '.join( set( someString.split() ) ) That's the unique space-delimited words in no

PHP - Need to remove duplicate characters within a String but would like to include exceptions

由 a 夏天 提交于 2019-12-01 11:15:25
I have been searching all over the internet for a solution, but could not find one. I need to remove duplicate characters within a String but would also like to include an exception to allow a integer amount of characters to repeat / remain in the string. For example, I tried the following: $str = 'This ----------is******** a bbbb 999-999-9999 ******** 8888888888 test 4444444444 ********##########Sammy!!!!!! ###### hello !!!!!!'; $t1 = preg_replace('/(.)\1{3,}/','',$str); $t2 = preg_replace('/(\S)\1{3,}/','',$str); $t3 = preg_replace('{(.)\1+}','$1',$str); $t4 = preg_replace("/[;,:\s]+/",',',

JPA/Hibernate duplicate records

由 好久不见. 提交于 2019-12-01 11:10:29
问题 I have a One-to-Many relationship between entities. When doing this JPQL query: SELECT parent FROM Parent parent JOIN parent.child child WHERE ... I get duplicate records when a parent has 2 children, only one when a parent have one child, none when there is no child (none when no child is fine). Note that there is no duplicate of Parent in the SQL database. The entities are declared as follow: @Entity(...) public class Parent { @Id Long parentId; @OneToMany(mappedBy = "parentID") List<Child>

Find duplicate items within a list of list of tuples Python

由 蹲街弑〆低调 提交于 2019-12-01 10:36:42
I want to find the matching item from the below given list.My List may be super large. The very first item in the tuple "N1_10" is duplicated and matched with another item in another array tuple in 1st array in the ListA ('N1_10', 'N2_28') tuple in 2nd array in the ListA ('N1_10', 'N3_98') ListA = [[('N1_10', 'N2_28'), ('N1_35', 'N2_44')], [('N1_22', 'N3_72'), ('N1_10', 'N3_98')], [('N2_33', 'N3_28'), ('N2_55', 'N3_62'), ('N2_61', 'N3_37')]] what I want for the output is output --> [('N1_10','N2_28','N3_98') , .... and the rest whatever match one of the key will get into same tuple ] If you

List of values for duplicate keys in dictionary Python

由 六月ゝ 毕业季﹏ 提交于 2019-12-01 10:32:39
问题 Apologies in advance if this question has already been explored here - I looked at different answers here but couldn't find what I need. My goal is to create a dictionary like this -- {'a':[10, 9, 10, 10], 'b':[10, 9, 1, 0], 'c':[0, 5, 0, 1], and so on} What I have is multiple dictionaries with duplicate keys (same keys in every other dictionary), something like this {'a':10, 'b': 0, 'c': 2} {'a':7, 'b': 4, 'c': 4} {'a':4, 'b': 5, 'c': 3} I have no way of knowing the number of such

RemoveDuplicates gives 1004 error

由 断了今生、忘了曾经 提交于 2019-12-01 10:26:33
I want to remove duplicates from my selection, but this line gives me a 1004 error: ActiveSheet.Range("B3", Range("B3").End(xlDown)).RemoveDuplicates Columns:=2, Header:=xlNo How do I fix this? Change your line into: ActiveSheet.Range(range("B3"), Range("B3").End(xlDown)).RemoveDuplicates Columns:=1, Header:=xlNo or,if you really have 2 columns into: ActiveSheet.Range(range("B3"), Range("C3").End(xlDown)).RemoveDuplicates Columns:=2, Header:=xlNo 来源： https://stackoverflow.com/questions/15929896/removeduplicates-gives-1004-error

Xcode referencing old/removed frameworks, causing multiple interface declarations

由 落爺英雄遲暮 提交于 2019-12-01 09:00:32
问题 I'm getting interface re-declaration errors when I'm trying to build because xcode keeps referencing these old frameworks and headers that I've already removed from the project. I've sifted through my build phases and build settings and nothing seems to point to those files. The funny thing is when xcode shows me my error and the line of code where the interface is supposedly redeclared, it won't show me any specific file when I click "Show in project navigator". However, if I ask it to "Show

Fastest way to deduplicate contiguous characters in string - Python [duplicate]

由 百般思念 提交于 2019-12-01 08:54:44
This question already has an answer here: Python: Best Way to remove duplicate character from string 6 answers We can deduplicate the contiguous characters in a string with: def deduplicate(string, char): return char.join([substring for substring in string.strip().split(char) if substring]) E.g. >>> s = 'this is an irritating string with random spacing .' >>> deduplicate(s) 'this is an irritating string with random spacing .' On the command line there is a squeeze option for tr : $ tr -s " " < file Is there a squeeze function in Python's string? What is the fastest way to deduplicate
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