duplicates

(This is my first try with php) I have a very basic register page. http://graves-incorporated.com/test_sites/member_test/register/register.php * I just remembered PHP code doesn't show up in the source so here it is: enter code here <?php include('connection.php'); if(isset($_POST['form'])){ if(empty($_POST['username']) || empty($_POST['password']) || empty($_POST['conf_pass']) || empty($_POST['email'])){ echo '<b>Please fill out all fields.</b>'; }elseif($_POST['password'] != $_POST['conf_pass']){ echo '<b>Your Passwords do not match.</b>'; }else{ $url = 'http://graves-incorporated.com/test

Just to clarify : I don't want to remove duplicates rows, I want to remove Duplicate Cells within a row So here's a classic address table, and in some row there's duplicate entries I need to remove those entries. Most of what I've seen in VBA is used to remove duplicates values within a column, but I can't find a way to remove duplicate values within a row. Name | Address1 | Address2 | City | Country Peter | 2 foobar street |2 foobar street | Boston | USA And I want it to be like : Name | Address1 | Address2 | City | Country Peter | 2 foobar street | | Boston | USA I've write a macro that will

Exmaple: [empid date bookid] ---------- 1 5/6/2004 8 2 5/6/2004 8 1 5/7/2004 8 1 5/8/2004 6 3 5/8/2004 8 2 5/8/2004 7 In this table,I need to get empid 1 as output..since it has bookid 8 more than once.. thanks in advance.. You can use: SELECT DISTINCT id FROM table GROUP BY empid, bookid HAVING COUNT(*) > 1 But it will give you duplicates. If, for example, you have 1-8,1-8,1-9,1-9 you will get 1,1 as output because empid 1 has duplicate bookid's for two distinct bookid values. You will need to use SELECT DISTINCT to filter out the duplicate empid. SELECT empid from table group by empid having

Apologies in advance if this question has already been explored here - I looked at different answers here but couldn't find what I need. My goal is to create a dictionary like this -- {'a':[10, 9, 10, 10], 'b':[10, 9, 1, 0], 'c':[0, 5, 0, 1], and so on} What I have is multiple dictionaries with duplicate keys (same keys in every other dictionary), something like this {'a':10, 'b': 0, 'c': 2} {'a':7, 'b': 4, 'c': 4} {'a':4, 'b': 5, 'c': 3} I have no way of knowing the number of such dictionaries, or if there are keys continuing up to 'f', or a 'g' in them but I know that the keys are duplicated

There is a bug that I found in MySql 5.5.19. When executing: select uuid(), uuid(); You are getting two equals ids. I run in two this bug when inserted two uuids to my table, I always got same values. Does anyone else run in two this bug? How can I perform insert command that requires two uuids for my keys? Edit : Actually I got wrong they are different in one digit so it was really hard to see c3db913 7 -705e-11e1-ae17-1c6f6531b785 c3db913 f -705e-11e1-ae17-1c6f6531b785 From the docs A UUID is designed as a number that is globally unique in space and time. Since the query is compiled before

I am having trouble removing the duplicates from two arrays that have been merged into one. I have written the following code that merges the arrays, yet I'm not sure how to remove the duplicates from the final array. Assume the arrays are already sorted. public static int[] merge(int[] list1, int[] list2) { int[] result = new int[list1.length + list2.length]; int i = 0; int j = 0; for (int k = 0; k < (list1.length + list2.length); k++) { if (i >= list1.length) { result[k] = list2[j]; j++; } else if (j >= list2.length) { result[k] = list1[i]; i++; } else { if (list1[i] < list2[j]) { result[k]

I'm trying to remove duplicate values in my dict but its not working: samples_antibiotics_with_duplicates = {'S00541-09': ['Streptomycin', 'Sulfamethoxazole', 'Trimethoprim', 'Spectinomycin', 'Streptomycin', 'Streptomycin', 'Trimethoprim']} samples_antibiotics = {} for key,value in samples_antibiotics_with_duplicates.iteritems(): if value not in samples_antibiotics.values(): samples_antibiotics[key] = value print samples_antibiotics This prints: {'S00541-09': ['Streptomycin', 'Sulfamethoxazole', 'Trimethoprim', 'Spectinomycin', 'Streptomycin', 'Streptomycin', 'Trimethoprim']} Any help will be