django-views

问题 I have created 'post' model in which I included 'post_id' as the primary key field. When I am trying to create a post, it is raising an error: 'badly formed hexadecimal UUID string'. I would appreciate helping me in solve this. Here's my code. Models.py: class Post(models.Model): post_id = models.UUIDField(primary_key=True, default='uuid.uuid4', editable=False) user = models.ForeignKey(settings.AUTH_USER_MODEL, default=1) from1 = models.CharField(max_length=20) To = models.CharField(max

问题 I have a problem when saving Strings as file in my Django models, as whenever I try to get the data back, it gives me a ValueError ("attribute has no file associated"). Here's the details: MODEL: class GeojsonData(models.Model): dname = models.CharField(max_length=200, unique=True) gdata = models.FileField(upload_to='data') def __str__(self): return self.dname CODE THAT SAVES THE DATA: cf = ContentFile(stringToBeSaved) gj = GeojsonDatua(dname = namevar, gdata = cf) gj.save() CODE THAT TRIES

问题 Django==1.10.5. I have a problem RelatedObjectDoesNotExist Views.py: def register(request): if request.method == 'POST': user_form = UserRegistrationForm(request.POST) if user_form.is_valid(): # Create a new user object but avoid saving it yet new_user = user_form.save(commit=False) # Set the chosen password new_user.set_password(user_form.cleaned_data['password']) # Save the User object new_user.save() # Create the user profile profile = Profile.objects.create(user=new_user) return render

问题 Let's say I have 3 django apps, app Country , app Social and app Financial . Country is a 'master navigation' app. It lists all the countries in a 'index' view and shows details for each country on its 'details' view. Each country's details include their Social details (from the social app) and their Financial details (from the financial app). Social and Financial both have a detail view (for each country) Is there an elegant way to 'plug' in those sub-detail views into the master detail view

问题 i have two models class A(models.Model): name = models.CharField(50) type = models.CharField(50) class B(models.Model): field1 = ForeignKeyField(A) value = IntegerField() I'd like to display a number of forms via a ModelFormSet (from model A) where each one of the forms displays in turn InlineFormSets (from model B) for all objects connected to the object. How can i combine both modelformsets (model A) and inline formsets (mdoel B) on save method in django views? 回答1: I'm not sure this is a

问题 I'm implementing James Bennett's excellent django-contact-form but have hit a snag. My contact page not only contains the form, but also additional flat page information. Without rewriting the existing view the contact form uses, I'd like to be able to wrap, or chain, the views. This way I could inject some additional information via the context so that both the form and the flat page data could be rendered within the same template. I've heard it mentioned that this is possible, but I can't

问题 In my Django project I need to be able to check whether a host on the LAN is up using an ICMP ping. I found this SO question which answers how to ping something in Python and this SO question which links to resources explaining how to use the sodoers file. The Setting A Device model stores an IP address for a host on the LAN, and after adding a new Device instance to the DB (via a custom view, not the admin) I envisage checking to see if the device responds to a ping using an AJAX call to an

问题 Hi i want to display count of answers to my question model my model: class Question(models.Model): text = models.TextField() title = models.CharField(max_length=200) date = models.DateTimeField(default=datetime.datetime.now) author = models.ForeignKey(CustomUser) tags = models.ManyToManyField(Tags) def __str__(self): return self.title class Answer(models.Model): text = models.TextField() date = models.DateTimeField(default=datetime.datetime.now) likes = models.IntegerField(default=0) author =

问题 I have the following scenario. class A(models.Model): a = models.IntegerField() class B(models.Model): c = models.OneToOneField(A) d = models.DecimalField() In my templates, I have a list of objects A. In my template how do I access the attribute "d" from my template? Thanks. 回答1: class B(models.Model): c = models.OneToOneField(A, related_name='b') d = models.DecimalField() {{ a.b.d }} 来源： https://stackoverflow.com/questions/6676134/accessing-django-onetoonefield-in-templates

问题 I try to test a view, I receive a json request from the IPad, the format is: req = {"custom_decks": [ { "deck_name": "deck_test", "updates_last_applied": "1406217357", "created_date": 1406217380, "slide_section_ids": [ 1 ], "deck_id": 1 } ], "custom_decks_to_delete": [] } I checked this in jsonlint and it passed. I post the req via: response = self.client.post('/library/api/6.0/user/'+ uuid + '/store_custom_dec/',content_type='application/json', data=req) The view return "creation_success":