django-templates

问题 I am trying to group messages by received today, received yesterday, ect. To clarify, I am trying to have a single header that says "Today" and then list those messages underneath. I am NOT trying to print "Today" along with each message that was received on that day (which is currently what's happening). I currently have the TODAY and YESTERDAY headers inside of my for loop so I understand that is why it is printing these headers for each mail message, but as previously stated I just want to

问题 I would like to make a django custom tag to display 10 entry titles from the category where the user is reading an article. How can I do this? I need to pass the category from the actual entry. 回答1: The best way to do this would be with an inclusion tag. This is a tag that renders a template fragment which renders the 10 related articles. You just pass in the current article into the tag, and return the context for the template fragment - ie the related articles. @register.inclusion_tag(

问题 I am trying to export some data in a PDF file. I am using: Django 1.9.12 django-easy-pdf 0.1.0 Python 2.7 The export works fine and all (no problem with my view) but I am struggling with adding a page header into every page of the document. At this point I can only render it on the first page. I have no such problem with the footer, it renders properly on every page. My template is as follows: {% extends "easy_pdf/base.html" %} {% block extra_style %} <style type="text/css"> @page { size:

问题 I want to include things like twitter status, or delicious tags, in my django templates. These things are dynamic, yet regular. How would this be done? 回答1: There are a number of ways to handle this, so you can choose a method that best matches your own personal style or requirements: Template context variable : as answered by Alex you can put your content into a context variable that is included in the context of every template created by every view. Django even provides a mechanism for

问题 I have a list of userprofiles that I want to be able to sort and filter. I have been able to do this manually, by manually typing in the URLs, but I haven't been able to code the template page to allow the persistence of a previously-applied filter or sort. Here is the url and template code that I currently have -- # in urls url(r'^talent/filter\:(?P<position>[A-Za-z]+)/sort\:(?P<sort>[A-Za-z]+)$', 'talent_filter', name='talent_filter_sort'), url(r'^talent/filter\:(?P<position>[A-Za-z]+)/$',

问题 I'm writing a custom template tag that wraps an HTML element with some code to make it editable. This is backed up by some CSS, and JS that takes care of sending the data to the server to save it. This component requires the inclusion of <script type="text/javascript" src="../myscript.js"></script> at the bottom of the page and <link rel="stylesheet" type="text/css" href="../mystyle.css"> at the top. I already have two "js" and "css" template blocks in the page template. My question - is

问题 I have tried something like this in views.py: class HomePage(TemplateView): template_name = "clouderp/index.html" def get_context_data(self, **kwargs): context = super(HomePage, self).get_context_data(**kwargs) qs = Blog.objects.all() context['blog_list'] = qs page = self.request.GET.get('page') paginator = Paginator(qs, 4) try: users = paginator.page(page) except PageNotAnInteger: users = paginator.page(1) except EmptyPage: users = paginator.page(paginator.num_pages) context['users'] = users

问题 I have a simple ChoiceField and want to access the 'selected' item during my template rendering. Lets say the form gets show again (due to error in one of the fields), is there a way to do something like: <h1> The options you selected before was # {{ MyForm.delivery_method.selected }} </h1> (.selected() is not working..) Thanks ! 回答1: It would be accessed by {{ myform.delivery_method.data }} <h1> The options you selected before was # {{ MyForm.delivery_method.data }} </h1> 回答2: @Yuji

问题 I have a Customer table and one of the fields here is for Status ....I want to have the background colour of the cell containing this field to be set according to it's value e.g green for the status "Closed"; yellow for the status "Pending" and so on. What's the best way to do this...possibly something that'll be easy to modify if need be in future? 回答1: On your css create class for td as follows, considering you want to display your customer table information in a html table, td.closed{

问题 I'm trying to show user group permissions in Django and show them in a "Drupal" style like a matrix. It works, but it takes too long to make the query and paint it in the template. Is there some way to improve my code? view img up(accomplished),down(views and template.html) views : def GroupPermissionsView(request): title = "Groups Permissions" groups = Group.objects.all() permissions = Permission.objects.all() context = Context({ 'title': title, 'groups': groups, 'permissions': permissions,