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It's not a typo. And for the one who doesn't notice, there is a space on the second one, and no space on the first. It happens to me when i make a homework like this: #include<stdio.h> int main(){ int id,d,m,y; char name[30]; printf("\tSTUDENT ID\t\t: ");scanf("%d",&id);\ printf("\tNAME\t\t: ");scanf("%[^\n]",&name); printf("\tDATE OF BIRTH\t: ");scanf("%d/%d/%d",&d,&m,&y); } when i do that code, the "NAME" part get skip to inputting "DATE OF BIRTH" part But, when i change the scanf("%[^\n]",&name); into scanf(" %[^\n]",&name); everything works fine. How this could happen? I don't seem to

What is wrong with this? import java.io.*; class TUI{ public static void main(String[] args) { System.out.println("Enter the two numbers:"); int n1=readInt("Enter n1:"); int n2=readInt("Enter n2:"); int total=n1+n2; System.out.println("Total is =" + total+"."); } } Getting these errors Day2.java:5: error: cannot find symbol int n1=readInt("Enter n1:"); ^ symbol: method readInt(String) location: class TUI Day2.java:6: error: cannot find symbol int n2=readInt("Enter n2:"); ^ symbol: method readInt(String) location: class TUI PS- Also What is the difference between readInt and nextInt ? Can I use

Update: The p-values and S.E.'s are similar between SPSS and R if I change the parameter estimation method in SPSS to 'Hybrid' and the scale parameter method to 'Pearson Chi-square'. Does anyone now how to change these settings in R and what these settings actually mean? I am trying to perform an GLM with a gamma log link function in R, to analyse a multiple imputation dataset. However, when I compare the results from the same analysis in R and SPSS they are very different. This example is in a non-imputation dataset to make things easier to interpret. The SPSS result is as follows: Parameter

I have a two dates in excel "1/2/2016 01:56:05" and "8/3/2016 06:21:46". How do I calculate the time difference between them in a format of days and hours? Thanks! Try this to include the spelled out hours and minutes: =INT(A2-A1) & " days, " & TEXT(A2-A1,"h "" hours, ""m "" minutes""") Note that since the m comes immediately (ignoring the separator text in quotes) after the h it will be interpreted as minutes and not months I prefer to work with dates as decimals. It looks cumbersome, but I'm much happier knowing what it's doing. What I would usually do is to have A1-A2 in cell A3, then work

I have two dataframes of different size ( df1 nad df2 ). I would like to remove from df1 all the rows which are stored within df2 . So if I have df2 equals to: A B 0 wer 6 1 tyu 7 And df1 equals to: A B C 0 qwe 5 a 1 wer 6 s 2 wer 6 d 3 rty 9 f 4 tyu 7 g 5 tyu 7 h 6 tyu 7 j 7 iop 1 k The final result should be like so: A B C 0 qwe 5 a 1 rty 9 f 2 iop 1 k I was able to achieve my goal by using a for loop but I would like to know if there is a better and more elegant and efficient way to perform such operation. Here is the code I wrote in case you need it: import pandas as pd df1 = pd.DataFrame(

Considering these two time vectors: a<-seq(as.POSIXct("2010-01-01 05:00:00"), as.POSIXct("2010-01-02 23:55:00"), by = '5 min') b<-seq(as.POSIXct("2010-01-01 00:00:00"), as.POSIXct("2010-01-03 23:55:00"), by = '10 min') How to get the different elements between these two vectors? I've tried: union(setdiff(a, b), setdiff(b, a)) But the returned values are not in time format. This uses only operations that preserve "POSIXct" class: c(a[!a %in% b], b[!b %in% a]) This will also work (using the default origin): as.POSIXct(union(setdiff(a, b), setdiff(b, a)), origin = '1970-01-01') #[1] "2010-01-01