destructor

I have written the very basic program below, I am new to C#. The destructor ~Program() doesn't get called, so I do not see in the output the 'Destructor called' string. I have checked other similar questions but I don't find the answer to mine. Thanks. using System; using System.Collections.Generic; using System.Linq; using System.Text; using static System.Console; namespace LyfeCicleObject { class Program { public Program() { WriteLine("Cons called"); } ~Program() { WriteLine("Destructor called"); } static void Main(string[] args) { WriteLine("Main started"); Program p1 = new Program(); {

I have this class definition: class FlashStream { public: explicit FlashStream(const char * url, vector<uint8> * headers, vector<uint8> * data, void * ndata, void * notifyData = NULL, uint32 lastModified = NULL); ~FlashStream(); private: NPStream _stream; // ... } ( NPStream description ) and its implemetation: FlashStream::FlashStream(const char * url, vector<uint8> * headers, vector<uint8> * data, void * ndata, void * notifyData, uint32 lastModified) { // ... memset(&_stream, 0, sizeof(NPStream)); _stream.headers = new char[data->size()]; memcpy((void*)_stream.headers, &(*data)[0], data-

I have a piece of code where I can call the destructor multiple times and access member functions even the destructor was called with member variables' values preserved. I was still able to access member functions after I called delete but the member variables were nullified (all to 0). And I can't double delete . Please kindly explain this. #include <iostream> using namespace std; template <typename T> void destroy(T* ptr) { ptr->~T(); } class Testing { public: Testing() : test(20) { } ~Testing() { printf("Testing is being killed!\n"); } int getTest() const { return test; } private: int test;

I am writing a c++ Hashtable Here is my destructor: HashMap::~HashMap() { for (int i=0; i<cap; i++) { Node* ptr = Hashtable[i]; while (ptr!=NULL) { Node* delptr; delptr=ptr; ptr=ptr->next; delete delptr; } } delete [] Hashtable; } My add function: void HashMap::add(const std::string& key, const std::string& value) { int index = hashfunction(key)%cap;; Node* ptr=Hashtable[index]; Node* newnode=new Node; if (contains(key)==false) { if (ptr == nullptr) { newnode->key=key; newnode->value=value; newnode->next=NULL; Hashtable[index]=newnode; } else { newnode->key=key; newnode->value=value; newnode-

As I have read in certain forums,when derived class object is created base class members and methods are allocated space in the memory but there is no specific base class object. Now as the derived class object goes out of scope , why derived class destructor is called first.What is the constraint of the compiler where derived class destructor cannot be called after base class destructor..? Please correct me in case I have built a wrong understanding..Thanks in advance When a derived class object is created, there is a specific base-class object (sub-object, really). I.e., when you create a