decimal

问题 I have this field: public decimal Price { get; set; } in Database it is decimal (7,2). View: @Html.EditorFor(model => model.Price, new { htmlAttributes = new { @class = "form-control" } }) If i put a value with comma, MVC default validation doesn't accept, says: "The field must be a number" . (I tried use a Regex, but no way) For example: 5,00, 55,00 or 555,00 Also this: public DateTime date { get;set; } View: @Html.EditorFor(model => model.Date, new { htmlAttributes = new { @class = "form

问题 I am having to interface some C# code with SQL Server and I want to have exactly as much precision when storing a value in the database as I do with my C# code. I use one of .NET's decimal type for a value. What datatype/precision would I use for this value in SQL Server? I am aware that the SQL Server decimal type is the type that most likely fits my needs for this. My question though is what scale and precision do I use so that it matches .NET's decimal type? 回答1: You can use the SQL Server

问题 I read data stored in the format DECIMAL from a MySQL-Table. I want to do calculations on those numbers within R. I used to cast them to a numeri represaentation using as.numeric() , but the documentation says: numeric is identical to double (and real). But is there also a datatype Decimal in R? (Datatype without rounding errors,...) Here a simple example for the problem with rounding errors: numbersStrings = c("0.1", "0.9") numbersNumeric = as.numeric(numbersStrings) numbersMirror = c

问题 I don't know what the correct wording is for what I am trying to achieve so it may already be posted online. Please be kind if it is. Ok so basically I have this method. public static T IsNull<T>(IDataReader dr, String name, T nullValue) { return Helpers.IsNull(dr, dr.GetOrdinal(name), nullValue); } public static T IsNull<T>(IDataReader dr, Int32 index, T nullValue) { if (dr.IsDBNull(index)) { return nullValue; } else { return (T)dr.GetValue(index); } } Being called as Helpers.IsNull(dr,

问题 Currently i have this method: static boolean checkDecimalPlaces(double d, int decimalPlaces){ if (d==0) return true; double multiplier = Math.pow(10, decimalPlaces); double check = d * multiplier; check = Math.round(check); check = check/multiplier; return (d==check); } But this method fails for checkDecmialPlaces(649632196443.4279, 4) probably because I do base 10 math on a base 2 number. So how can this check be done correctly? I thought of getting a string representation of the double

问题 I'm trying to figure out why framework refuses to bind "1,234.00" value to decimal. What can be the reason for it? Values like "123.00" or "123.0000" bind successfully. I have the following code setting my culture config in Global.asax public void Application_AcquireRequestState(object sender, EventArgs e) { var culture = (CultureInfo)Thread.CurrentThread.CurrentCulture.Clone(); culture.NumberFormat.NumberDecimalSeparator = culture.NumberFormat.CurrencyDecimalSeparator = culture.NumberFormat

问题 So, I am creating a mathematical program, it has a couple of functions, one of the function is a decimal place holder, what this is: the user is asked how many decimal places he would like his answers to be shown for the different mathematical solvers, so example is if he says 3 then my answer for another function e.g 1+1 would equal 2.000 They are asked a range between 1 and 5, I have the code for this but do not know how to implement it for the answer of the functions 'Decimal place Sub

问题 What the heck is going on with the syntax to fix a Decimal to two places? >>> from decimal import Decimal >>> num = Decimal('1.0') >>> num.quantize(Decimal(10) ** -2) # seriously?! Decimal('1.00') Is there a better way that doesn't look so esoteric at a glance? 'Quantizing a decimal' sounds like technobabble from an episode of Star Trek! 回答1: Use string formatting: >>> from decimal import Decimal >>> num = Decimal('1.0') >>> format(num, '.2f') '1.00' The format() function applies string

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 2 years ago . I have a std::string with a large integer encoded in Base16: bbb91c1c95b656f386b19ab284b9c0f66598e7761cd71569734bb72b6a7153b77613a6cef8e63 e9bd9bb1e0e53a0fd8fa2162b160fcb7b461689afddf098bfc32300cf6808960127f1d9f0e287

问题 I woud like to ask, what bin-'0' means in this piece of code which convert binary number to decimal. Thanks. #include <stdio.h> #include <stdlib.h> int main(){ char bin; int dec = 0; printf("Binary: \n"); bin = getchar(); while((bin != '\n')){ if((bin != '0') && (bin != '1')){ printf("Wrong!\n"); return 0; } printf("%c",bin-'0'); // ? dec = dec*2+(bin-'0'); // ? bin = getchar(); } printf("Decimal: %d\n", dec); return 0; } 回答1: bin - '0' converts the ASCII value of bin to its integer value.