curve

Equidistant points across Bezier curves

痞子三分冷 提交于 2019-11-28 06:36:36
Currently, I'm attempting to make multiple beziers have equidistant points. I'm currently using cubic interpolation to find the points, but because the way beziers work some areas are more dense than others and proving gross for texture mapping because of the variable distance. Is there a way to find points on a bezier by distance rather than by percentage? Furthermore, is it possible to extend this to multiple connected curves? distance between P_0 and P_3 (in cubic form), yes, but I think you knew that, is straight forward. Distance on a curve is just arc length: fig 1 http://www.codecogs

Fitting a curve to specific data

ぐ巨炮叔叔 提交于 2019-11-28 06:07:17
I have the following data in my thesis: 28 45 91 14 102 11 393 5 4492 1.77 I need to fit a curve into this. If I plot it, then this is what I get. I think some kind of exponential curve should fit this data. I am using GNUplot. Can someone tell me what kind of curve will fit this and what initial parameters I can use? Ben Just in case R is an option, here's a sketch of two methods you might use. First method: evaluate the goodness of fit of a set of candidate models This is probably the best way as it takes advantage of what you might already know or expect about the relationship between the

transparent shape with arrow in upper corner

我只是一个虾纸丫 提交于 2019-11-28 01:05:47
Please see the image below. I want to add an arrow to the top right of a div which I am treating as editable input box. Please help me how I can achieve this using CSS. I cannot use a SVG since I need this as a div to show emoticons as images over it. <div placeholder="Your message" id="Message"> ... </div> You can do it like in the below snippet. The method used to achieve the shape is as given below: The main div element only has a top, bottom and left border. The right border is nullified because the element and its arrows needs to be transparent. With a transparent arrow, if a right border

plotting a curve around a set of points

落花浮王杯 提交于 2019-11-27 20:08:11
问题 I have a set of points on a plane. They are partitioned into subsets. I want to plot a closed curve around points that belong to the same subset, so that points that belong to a subset will be inside the curve, and those that aren't will be outside. Therefore simple circles, or a convex hull might not work. For a starter, let's say I just want to have a smooth curve around a set of point (without the requirement that it excludes other points) Any ideas how to do that in R? ---added later---

Draw a curve with css

雨燕双飞 提交于 2019-11-27 19:05:48
I want to create an animation with css that simulate a wave movement. I need to change a line-or div- to a curve for this... The CSS rules that I'm familiar to, make the entire div to semicircular or change element border. For example: border-radius , or perspective or border-top-radius ... This image show you what I want: Do you have experience about this? or is it possible? Thanks in Advance... Elad Shechter You could use an asymmetrical border to make curves with CSS. border-radius: 50%/100px 100px 0 0; VIEW DEMO .box { width: 500px; height: 100px; border: solid 5px #000; border-color: #000

svg multiple color on circle stroke

醉酒当歌 提交于 2019-11-27 18:24:14
i want to create a rainbow circle like the picture below: but how can i draw the curved and multiple color stop gradient? here's my current code: <svg width="500" height="500" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"> <defs> <linearGradient id="test"> <stop offset="0%" stop-color="#f00"/> <stop offset="100%" stop-color="#0ff"/> </linearGradient> </defs> <circle cx="50" cy="50" r="40" fill="none" stroke="url(#test)" stroke-width="6"/> </svg> This approach won't work. SVG doesn't have conical gradients. To simulate the effect, you would have to fake it with a

Gradient Stroke Along Curve in Canvas

六眼飞鱼酱① 提交于 2019-11-27 14:25:31
I'm trying to draw a curve in canvas with a linear gradient stoke style along the curve, as in this image . On that page there is a linked svg file that gives instructions on how to accomplish the effect in svg. Maybe a similar method would be possible in canvas? A Demo: http://jsfiddle.net/m1erickson/4fX5D/ It's fairly easy to create a gradient that changes along the path : It's more difficult to create a gradient that changes across the path : To create a gradient across the path you draw many gradient lines tangent to the path: If you draw enough tangent lines then the eye sees the curve as

How to place the intercept of x and y axes at (0 , 0) and extend the x and y axes to the edge of the plot [duplicate]

▼魔方 西西 提交于 2019-11-27 13:55:59
问题 This question already has answers here : Set R plots x axis to show at y=0 (2 answers) Closed 9 months ago . Suppose I want to plot x^2 . I can use curve() as follows. curve(x^2, -5, 5) However, I would like the axes to go through (0, 0). I could do something as follows: curve(x^2, -5, 5, axes=FALSE) axis(1, pos=0) axis(2, pos=0) abline(h=0) abline(v=0) And I end up getting something like below, which looks OK. But the only gripe I have is that this way of plotting axes makes the actual axes

ggplot2: histogram with normal curve

女生的网名这么多〃 提交于 2019-11-27 11:34:46
I've been trying to superimpose a normal curve over my histogram with ggplot 2. My formula: data <- read.csv (path...) ggplot(data, aes(V2)) + geom_histogram(alpha=0.3, fill='white', colour='black', binwidth=.04) I tried several things: + stat_function(fun=dnorm) ....didn't change anything + stat_density(geom = "line", colour = "red") ...gave me a straight red line on the x-axis. + geom_density() doesn't work for me because I want to keep my frequency values on the y-axis, and want no density values. Any suggestions? Thanks in advance for any tips! Solution found! +geom_density(aes(y=0.045*.

Draw a quadratic Bézier curve through three given points

*爱你&永不变心* 提交于 2019-11-27 11:29:26
I have three points in 2D and I want to draw a quadratic Bézier curve passing through them. How do I calculate the middle control point ( x1 and y1 as in quadTo)? I know linear algebra from college but need some simple help on this. How can I calculate the middle control point so that the curve passes through it as well? Let P0, P1, P2 be the control points, and Pc be your fixed point you want the curve to pass through. Then the Bezier curve is defined by P(t) = P0*t^2 + P1*2*t*(1-t) + P2*(1-t)^2 ...where t goes from zero to 1. There are an infinite number of answers to your question, since it