cumulative-sum

How do i create a query that will give me a cumulative total?

末鹿安然 提交于 2019-12-24 10:23:08
问题 I have a table with the following columns: reportDate DATETIME and losses CURRENCY and of course the ID column. How do I write a query that will return a table with a running total of the losses column? Each date will have multiple entries so i think they will need use Sum() for each date. I know this has to do with the DSum function but im still lost on this one. It should look something like Month Losses Cum ----- ------ ----- Jan $3,000 $3,000 Feb $2,000 $5,000 Mar $1,500 $6,500 Having a

Conditional running count (cumulative sum) with reset in R (dplyr)

和自甴很熟 提交于 2019-12-22 10:34:49
问题 I'm trying to calculate a running count (i.e., cumulative sum) that is conditional on other variables and that can reset for particular values on another variable. I'm working in R and would prefer a dplyr -based solution, if possible. I'd like to create a variable for the running count, cumulative , based on the following algorithm: Calculate the running count ( cumulative ) within combinations of id and age Increment running count ( cumulative ) by 1 for every subsequent trial where

Fetch cumulative sum from MySQL table

こ雲淡風輕ζ 提交于 2019-12-22 00:33:08
问题 I have a table containing donations, and I am now creating a page to view statistics. I would like to fetch monthly data from the database with gross and cumulative gross. mysql> describe donations; +------------------+------------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+------------------+------+-----+---------+----------------+ | id | int(10) unsigned | NO | PRI | NULL | auto_increment | | transaction_id | varchar(64

Applying cumsum to binary vector

懵懂的女人 提交于 2019-12-20 07:15:16
问题 I have a simple binary vector a which I try to translate into vector b using the R function cumsum . However, cumsum does not exactly return vector b . Here is an example: a <- c(1,0,0,0,1,1,1,1,0,0,1,0,0,0,1,1) b <- c(1,2,2,2,3,4,5,6,7,7,8,9,9,9,10,11) > cumsum(a) [1] 1 1 1 1 2 3 4 5 5 5 6 6 6 6 7 8 The problem is that whenever a 0 appears in vector a then the previous number should be increased by 1 but only for the first 0. The remaining ones are given the same value. Any advise would be

PDF and CDF plot for central limit theorem using Matlab

寵の児 提交于 2019-12-17 21:22:59
问题 I am struggling to plot the PDF and CDF graphs of where Sn=X1+X2+X3+....+Xn using central limit theorem where n = 1; 2; 3; 4; 5; 10; 20; 40 I am taking Xi to be a uniform continuous random variable for values between (0,3). Here is what i have done so far - close all %different sizes of input X %N=[1 5 10 50]; N = [1 2 3 4 5 10 20 40]; %interval (1,6) for random variables a=0; b=3; %to store sum of differnet sizes of input for i=1:length(N) %generates uniform random numbers in the interval X

Conditional Running Sum in Pandas for All Previous Values Only

会有一股神秘感。 提交于 2019-12-14 03:57:32
问题 Suppose I have the following DataFrame: df = pd.DataFrame({'Event': ['A', 'B', 'A', 'A', 'B', 'C', 'B', 'B', 'A', 'C'], 'Date': ['2019-01-01', '2019-02-01', '2019-03-01', '2019-03-01', '2019-02-15', '2019-03-15', '2019-04-05', '2019-04-05', '2019-04-15', '2019-06-10'], 'Sale': [100, 200, 150, 200, 150, 100, 300, 250, 500, 400]}) df['Date'] = pd.to_datetime(df['Date']) df Event Date Sale A 2019-01-01 100 B 2019-02-01 200 A 2019-03-01 150 A 2019-03-01 200 B 2019-02-15 150 C 2019-03-15 100 B

mysql rolling sum cumulative serialized

非 Y 不嫁゛ 提交于 2019-12-14 02:57:19
问题 For example I have the bellow table (tb_transaction) id_trans date_trans production_plant dead_plant distribution_plant 25 2017-12-31 1000 100 200 26 2018-01-17 150 0 0 27 2018-02-07 0 50 100 28 2018-03-07 250 0 75 29 2018-05-10 500 50 0 Than I try to make a report table for this Year, like bellow table month EarlyStock production dead LivePlant Distri EndStock January 150 0 150 0 150 February 0 50 -50 100 -150 March 250 0 250 75 175 April 0 0 0 0 0 May 500 50 450 0 450 June 0 0 0 0 0 July 0

Finding cumulative features in dataframe?

那年仲夏 提交于 2019-12-13 03:49:25
问题 I have a datframe with around 200 features and 3000 rows. These data samples are logged in different time, basically one per month, as shown in the below example in “col101”: 0 col1 (id) col2. col3 …. col100 col101 (date) … col2000 (target value) 1 001 653. 675 …. 343.3 01-02-2017. … 1 2 001 673. 432 …. 387.3 01-03-2017. … 0 3 001 679. 528 …. 401.2 01-04-2017. … 1 4 001 685 223 …. 503.4 01-05-2017. … 1 5 002 343 428 …. 432.5 01-02-2017. … 0 6 002 479. 421 …. 455.3 01-03-2017. … 0 7 … … … …. …

Cumulative multiplication in R with the addition of extra constants

浪尽此生 提交于 2019-12-12 15:15:20
问题 I'm new to R and struggling with the following combination of cumulative multiplication with the addition of extra constants. I'm looking to achieve the following in a dataframe: Variable_X Variable_Y Variable_Z X1 Y1 Y1*X1 = Z1 X2 Y2 (Z1+Y2)*X2 = Z2 X3 Y3 (Z2+Y3)*X3 = Z3 X4 Y4 (Z3+Y4)*X4 = Z4 Any help would be greatly appreciated. 回答1: library(Rcpp) cppFunction("NumericVector foo_cpp (NumericVector x, NumericVector y) { int n = x.size(), i; NumericVector z(n); double tmp = 0.0; for (i = 0; i

Cumulative sum over index in MATLAB

≯℡__Kan透↙ 提交于 2019-12-12 10:36:41
问题 Consider the following matrix, where the first column is the index, the second - is values, the third - is the cumulative sum which resets once the index changes: 1 1 1 % 1 1 2 3 % 1+2 1 3 6 % 3+3 2 4 4 % 4 2 5 9 % 4+5 3 6 6 % 6 3 7 13 % 6+7 3 8 21 % 13+8 3 9 30 % 21+9 4 10 10 % 10 4 11 21 % 10+11 How can one get the third column avoiding loops? I try the following: A = [1 1;... % Input 1 2;... 1 3;... 2 4;... 2 5;... 3 6;... 3 7;... 3 8;... 3 9;... 4 10;... 4 11]; CS = cumsum(A(:,2)); %