counter

//定义自增计数器，初始值是0，步长是1 var add = (function(){ 　　var counter =0; 　　return function () {counter += 1; return counter;} })(); //调用，每次自增1 add(); //值为1 add(); //值为2 add(); //值为3 来源： https://www.cnblogs.com/shurun/p/11947422.html

This may be simpler than I think but I'd like to create timer that, upon reaching a limit (say 15 mins), some code is executed. Meanwhile every second, I'd like to test for a condition. If the condition is met, then the timer is reset and the process begins again, otherwise the countdown continues. If the condition is met after the countdown has reached the end, some code is executed and the timer starts counting down again. Does this involve threading or can it be achieved with a simple time.sleep() function? If the whole process is as simple as you say, I would go about it like this (semi

In CSS, with: @page { @top-right { content: "Page " counter(page) " of " counter(pages); } } I can have page numbers displayed at the top of every page when the page is printed. This works great. But now, how can I make it so the page number starts with 2 instead of 1? Can I do that by modifying the CSS rule above? If you are using Flying Saucer (which was my case), use the following CSS: table { -fs-table-paginate: paginate; } It works like a charm. And Flying Saucer rocks :). Really highly recommended. Try: @page { counter-increment: page; counter-reset: page 1; @top-right { content: "Page "

I'm trying to get the counts of unique items in a csv column using Python. Sample CSV file (has no header): AB,asd AB,poi AB,asd BG,put BG,asd I've tried this so far. import csv from collections import defaultdict, Counter input_file = open('Results/1_sample.csv') csv_reader = csv.reader(input_file, delimiter=',') data = defaultdict(list) for row in csv_reader: data[row[0]].append(row[1]) for k, v in data.items(): print k print Counter(v) This gives output in this format: AB Counter({'asd': 2, 'poi': 1}) BG Counter({'asd': 1, 'put': 1}) But I want my output to be like: AB:2 BG:2 total_unique

Does anyone know of a method to use CRTP to count the number of subclasses of an object? Suppose we had a setup similar to the following one: template <typename T> class Object { .... }; const unsigned int ObjectSubClassCount = ...; class Subobject : public Object<SubObject> { .... }; class Second : public Object<Second> { .... }; and so on, such that, using TMP, we might have a constant ( ObjectSubClassCount ) that represents the total number of subclasses? Does anyone know a way to do this? Edit: I am wanting to use the result as a template parameter later on, so I need it to be done with

We are doing the following to update the value of a counter, now we wonder if there is a straightforward way to get back the updated counter value immediately. mutator.incrementCounter(rowid1, "cf1", "counter1", value); Wildfire There's no single 'incrementAndGet' operation in Cassandra thrift API. Counters in Cassandra are eventually consistent and non-atomic. Fragile ConsistencyLevel.ALL operation is required to get "guaranteed to be updated" counter value, i.e. perform consistent read. ConsistencyLevel.QUORUM is not sufficient (as specified in counters design document: https://issues.apache

When I run the code below: s = pandas.Series(['c', 'a', 'b', 'a', 'b']) print(s.value_counts()) Sometimes I get this: a 2 b 2 c 1 dtype: int64 And sometimes I get this: b 2 a 2 c 1 dtype: int64 e.g. the index order returned for equivalent counts is not the same. I couldn't reproduce this if the Series values are integers instead of strings. Why does this happen, and what is the most efficient way to get the same index order every time? I want it to still be sorted in descending order by counts, but to be consistent in the order of equivalent-counts items. I'm running Python 3.7.0 and pandas 0

I'm trying to find the shared elements (and the shared number of occurrences) between two lists. For example, the intersection of these two lists: a = [1, 1, 2, 3, 4, 5, 6, 7, 8, 1] b = [1, 1, 3, 5, 7, 9] should return Counter({1: 2, 3: 1, 5: 1, 7: 1}) or something similar, e.g. {1: 2, 3: 1, 5: 1, 7: 1} or [1, 1, 3, 5, 7] (order of the list doesn't matter). I already have an approach that works: cnts_a = Counter(a) cnts_b = Counter(b) cnts_a_b = Counter() # counter for the shared values for key in set(cnts_a).intersection(cnts_b): cnts_a_b[key] = min(cnts_a[key], cnts_b[key]) But perhaps there

<body><div id="app"> <h2>{{counter}}</h2> <button v-on:click="increament()">增加</button> <button v-on:click="decreament()">减少</button></div><!--<button></button>--><script> const app=new Vue({ el:'#app', data:{ counter:0 }, methods:{ increament(){ return this.counter++; }, decreament(){ return this.counter--; } } })</script>v-on的语法糖：@ <button @click="increament()">增加</button><button @click="decreament()">减少</button>设置函数时要求有返回值，但是，我们在传递了一个空参数，此时 就会产生一个undefined；对于网页的操作时，网页会给我们反馈event对象，所以，当设置监听函数时省略小括号，但是方法本身需要我们传递参数，那么就会传递回去一个event参数 来源： https://www.cnblogs.com/Damocless/p/11906803.html